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A random sample of 200New York State voters included 88Republicans, while a random sample of 300California voters produced 141Republicans. Which of the following represents the 95%confidence interval that should be used to estimate the true difference in the proportions of Republicans in New York State and California?

(a)0.44-0.471.960.440.56+0.470.53200+300

(b)0.44-0.471.960.440.56200+0.470.53300

(c)0.44-0.471.960.440.56200+0.470.53300

(d)0.44-0.471.960.440.56+0.470.53200+300

(e)0.44-0.471.960.450.551200+1300

Short Answer

Expert verified

The true difference in the proportions of Republicans in New York State and California is (c) (0.44-0.47)1.960.440.56200+0.470.53300

Step by step solution

01

Given information

We are given that a random sample of New York voters and California voters include republicans. We have to estimate the true difference in the proportions of Republicans in New York State and California.

02

Simplify

According to question

Sample of New York n1=200

Republicans in New York x1=88

Sample of California n2=300

Republicans in x2=141

For difference of proportions:

p1^-p2^-z/2p1^1-p1^n1+p2^1-p2^n2p1^=x1n1=88200=0.44p2^=x2n2=141300=0.47

Critical value z/2=z0.025=1.96

Now , from above formula

=0.44-0.471.960.441-0.44200+0.471-0.47300=0.44-0.471.960.440.56200+0.470.53300

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