/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Sweetening colas Cola makers tes... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sweetening colas Cola makers test new recipes for loss of sweetness during storage. Trained tasters rate the sweetness before and after storage. From experience, the population distribution of sweetness losses will be close to Normal. Here are the sweetness losses (sweetness before storage minus sweetness after storage) found by tasters from a random sample of 10 batches of a new cola recipe: \(2.0 \quad 0.4 \quad 0.7 \quad 2.0 \quad-0.4 \quad 2.2 \quad-1.3 \quad 1.2 \quad 1.1 \quad 2.3\) Are these data good evidence that the cola lost sweetness? Carry out a test to help you answer this question.

Short Answer

Expert verified
The data shows significant evidence that the cola loses sweetness.

Step by step solution

01

Formulate the Hypotheses

We want to test whether there is a significant loss of sweetness. This can be tested by setting the null hypothesis that the mean sweetness loss is zero (\( H_0: \mu = 0 \)), against the alternative hypothesis that the mean sweetness loss is not zero (\( H_a: \mu eq 0 \)).
02

Calculate the Sample Mean and Standard Deviation

First, calculate the mean sweetness loss from the sample data: \( \text{mean} = \frac{2.0 + 0.4 + 0.7 + 2.0 - 0.4 + 2.2 - 1.3 + 1.2 + 1.1 + 2.3}{10} = 1.02 \).Next, find the sample standard deviation using the formula:\[ s = \sqrt{\frac{1}{n-1} \sum (x_i - \bar{x})^2} \]where \( x_i \) are the sample values and \( \bar{x} \) is the sample mean.
03

Compute the Test Statistic

Use the t-statistic formula for a single sample:\[ t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]where \( \bar{x} = 1.02 \) is the sample mean, \( \mu_0 = 0 \) is the population mean under the null hypothesis, \( s \) is the sample standard deviation, and \( n = 10 \) is the sample size.
04

Determine the Critical Value and p-Value

With \( n - 1 = 9 \) degrees of freedom (since \( n = 10 \)), find the critical t-value for a chosen significance level (typically \( \alpha = 0.05 \)). Use a t-table or calculator to find that for a two-tailed test, the critical values are approximately \( \pm 2.262 \).Calculate the p-value based on the calculated t-statistic to see how likely the observed sample mean would be if the null hypothesis were true.
05

Draw a Conclusion

Compare the calculated t-statistic to the critical value and examine the p-value.- If \(|t|\) is greater than the critical value and the p-value is less than 0.05, reject the null hypothesis.- Otherwise, do not reject the null hypothesis, indicating insufficient evidence to conclude the cola loses sweetness. If you reject the null, state that the evidence suggests a significant sweetness loss.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sweetness Loss
When testing new cola recipes, it's important to measure any potential sweetness loss during storage. Sweetness loss is calculated as the difference between the sweetness rating before storage and after storage. This measurement helps companies understand if their formula maintains the desired taste over time.
In the exercise example, tasters rated batches of a new cola recipe both before and after storage. The individual differences, or sweetness losses, were: 2.0, 0.4, 0.7, 2.0, -0.4, 2.2, -1.3, 1.2, 1.1, and 2.3. These values are used to see if the cola experiences an overall loss in sweetness. Accurately measuring this helps companies decide if recipe adjustments are needed to ensure consistent taste.
T-Statistic
The t-statistic is a key part of hypothesis testing. It helps determine if the sample provides enough evidence to conclude that the cola loses sweetness. Calculating the t-statistic involves the difference between the sample mean and the hypothesized population mean, all divided by the standard error.

In this case, the formula is:
  • \[ t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]
  • \(\bar{x} = 1.02\): the sample mean sweetness loss
  • \(\mu_0 = 0\): the population mean under the null hypothesis (no loss)
  • \(s\): the sample standard deviation, and \(n = 10\): the sample size
Using this formula helps us decide if the observed sweetness loss can happen by chance or if it's statistically significant.
Sample Mean
The sample mean is an average of the sweetness losses from all batches tested. It's a crucial measure because it represents the central tendency of the data. The sample mean is calculated by summing all individual sweetness losses and dividing by the number of samples.

In our example:
  • \[\text{mean} = \frac{2.0 + 0.4 + 0.7 + 2.0 - 0.4 + 2.2 - 1.3 + 1.2 + 1.1 + 2.3}{10} = 1.02\]

This value, 1.02, indicates the average extent to which the cola's sweetness decreases during storage. Understanding the sample mean helps us assess whether the sweetness loss is significant enough to warrant changes in the formula.
Statistical Significance
Statistical significance helps us determine if the sweetness loss observed in our cola batches is meaningful or if it happened by random chance. We achieve this by comparing our calculated t-statistic to a critical value and examining the p-value.

Usually, a significance level \(\alpha\) of 0.05 is chosen. This means we're willing to accept a 5% chance of incorrectly rejecting the null hypothesis. For our exercise, with 9 degrees of freedom, the critical t-values in a two-tailed test are approximately \(\pm 2.262\).
We compare our t-statistic to these critical values:
  • If \(|t|\) is larger than the critical value, the loss is statistically significant.
  • If the p-value is less than \(0.05\), it strengthens our case to reject the null hypothesis.
This process decides if the evidence suggests that the cola has a significant loss of sweetness after storage.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Side effects A drug manufacturer claims that less than 10% of patients who take its new drug for treating Alzheimer’s disease will experience nausea. To test this claim, researchers conduct an experiment. They give the new drug to a random sample of 300 out of 5000 Alzheimer’s patients whose families have given informed consent for the patients to participate in the study. In all, 25 of the subjects experience nausea. Use these data to perform a test of the drug manufacturer’s claim at the \(\alpha=0.05\) significance level.

Growing tomatoes An agricultural field trial compares the yield of two varieties of tomatoes for commercial use. Researchers randomly select 10 Variety A and 10 Variety B tomato plants. Then the researchers divide in half each of 10 small plots of land in different locations. For each plot, a coin toss determines which half of the plot gets a Variety A plant; a Variety B plant goes in the other half. After harvest, they compare the yield in pounds for the plants at each location. The 10 differences (Variety \(A-\) Variety \(B )\) give \(\overline{x}=0.34\) and \(s_{x}=0.83\) A graph of the differences looks roughly symmetric and single- peaked with no outliers. Is there convincing evidence that Variety A has the higher mean yield? Perform a significance test using \(\alpha=0.05\) to answer the question.

Packaging \(\operatorname{CDs}(6.2,5.3)\) A manufacturer of compact discs (CDs) wants to be sure that their CDs will fit inside the plastic cases they have bought for packaging. Both the CDs and the cases are circular. According to the supplier, the plastic cases vary Normally with mean diameter \(\mu=4.2\) inches and standard deviation \(\sigma=0.05\) inches. The CD manufacturer decides to produce CDs with mean diameter \(\mu=4\) inches. Their diameters follow a Normal distribution with \(\sigma=0.1\) inches. (a) Let X the diameter of a randomly selected CD and Y the diameter of a randomly selected case. Describe the shape, center, and spread of the distribution of the random variable X Y. What is the importance of this random variable to the CD manufacturer? (b) Compute the probability that a randomly selected CD will fit inside a randomly selected case. (c) The production process actually runs in batches of 100 CDs. If each of these CDs is paired with a randomly chosen plastic case, find the probability that all the CDs fit in their cases.

Check that the conditions for carrying out a one-sample z test for the population proportion p are met. Don’t argue! A Gallup Poll report on a national survey of 1028 teenagers revealed that 72% of teens said they rarely or never argue with their friends.12 Yvonne wonders whether this national result would be true in her large high school, so she surveys a random sample of 150 students at her school.

You use technology to carry out a significance test and get a P-value of 0.031 . The correct conclusion is (a) accept \(H_{a}\) at the \(\alpha=0.05\) significance level. (b) reject \(H_{0}\) at the \(\alpha=0.05\) significance level. (c) reject \(H_{0}\) at the \(\alpha=0.01\) significance level. (d) fail to reject \(H_{0}\) at the \(\alpha=0.05\) significance level. (e) fail to reject \(H_{a}\) at the \(\alpha=0.05\) significance level.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.