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Check that the conditions for carrying out a one-sample z test for the population proportion p are met. Don’t argue! A Gallup Poll report on a national survey of 1028 teenagers revealed that 72% of teens said they rarely or never argue with their friends.12 Yvonne wonders whether this national result would be true in her large high school, so she surveys a random sample of 150 students at her school.

Short Answer

Expert verified
The conditions for the one-sample z test are met.

Step by step solution

01

Verify Random Sampling

First, confirm that the sample is randomly selected, which ensures each individual in the population has an equal chance of being selected. The exercise states that a random sample of 150 students was surveyed, so the random condition is met.
02

Check the Sample Size Condition

The sample size must be large enough to justify the use of normal approximation. Specifically, both the expected number of successes, \( np \), and the expected number of failures, \( n(1-p) \), should be at least 10. Here, \( n = 150 \) and \( p = 0.72 \) from the Gallup Poll, so calculate: \( np = 150 \times 0.72 = 108 \) and \( n(1-p) = 150 \times 0.28 = 42 \). Both values exceed 10, so the condition is satisfied.
03

Population Proportion Assumption

The assumption is that the sample proportion (72%) from the Gallup Poll approximates the population proportion for the school, which should be similar given a large population. The large high school presumably has a student population that satisfies this assumption due to its size.
04

Conclusion on Conditions

Having verified that the random sampling, sample size condition, and population approximation assumptions are met, all conditions for carrying out a one-sample z test for the population proportion are satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
When conducting a one-sample z test, understanding the concept of population proportion is crucial. Population proportion refers to the ratio of individuals in a population who have a particular characteristic. In the context of our example, we're interested in the proportion of teens who rarely or never argue with their friends. Based on a larger survey, we know that this proportion is 72%. It's important for us to assume that this national proportion is generally reflective of other similar groups, like the large high school, provided that the sample selection and size conditions are appropriately met. This helps ensure the sample proportion can be a reliable estimate of the population proportion, allowing researchers to make inferences about the population from which the sample was drawn.
Random Sampling
Random sampling is a key principle in statistics, essential for obtaining reliable and unbiased results. When we talk about random sampling, we mean that every individual in the population has an equal chance of being selected. In our exercise, a random sample of 150 students was chosen from a large high school. This random selection is critical because it helps to approximate the true diversity and characteristics of the entire school population. Random sampling minimizes bias, making the sample representative of the population, which is essential for the results of our one-sample z test to be valid. Therefore, confirming that a random sample was used allows us to proceed with confidence in our statistical analysis.
Sample Size Condition
For a one-sample z test to be valid, the sample size needs to meet specific conditions. These ensure that the test results are reliable and the normal approximation is appropriate. In general, the sample size should be large enough so that both the expected number of successes (\( np \)) and the expected number of failures (\( n(1-p) \)) are at least 10. In our example, we have a sample size (\( n \)) of 150, with a national success proportion (\( p \)) of 0.72.Calculating gives us \( np = 150 \times 0.72 = 108 \) and \( n(1-p) = 150 \times 0.28 = 42 \), both values are comfortably above 10. This indicates our sample size is sufficient, supporting the validity of using the normal approximation for the z test.
Normal Approximation
Normal approximation involves using a normal distribution to approximate the sampling distribution of a sample statistic. In the context of a one-sample z test for a population proportion, this means treating the sample proportion as if it follows a normal distribution. For normal approximation to be valid, certain conditions, such as random sampling and appropriate sample size, must be met. With the sample size condition verified in the previous section, we can utilize the normal approximation for our z test. This approximation simplifies calculations and allows for easy interpretation of results, making it easier to test hypotheses about population proportions. When conditions are satisfied, normal approximation is a powerful tool for making statistical inferences.

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Most popular questions from this chapter

Error probabilities You read that a statistical test at the \(\alpha=0.01\) level has probability 0.14 of making a Type II error when a specific alternative is true. What is the power of the test against this alternative?

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Filling cola bottles Bottles of a popular cola are supposed to contain 300 milliliters (ml) of cola. There is some variation from bottle to bottle because the filling machinery is not perfectly precise. From experience, the distribution of the contents is approximately Normal. An inspector measures the contents of six randomly selected bottles from a single day’s production. The results are 299.4\(\quad 297.7 \quad 301.0 \quad 298.9 \quad 300.2 \quad 297.0\) Do these data provide convincing evidence that the mean amount of cola in all the bottles filled that day differs from the target value of 300 \(\mathrm{ml}\) ? Carry out an appropriate test to support your answer.

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