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Two-sided test The one-sample \(t\) statistic from a sample of \(n=25\) observations for the two-sided test of $$ \begin{array}{l}{H_{0} : \mu=64} \\ {H_{a} : \mu \neq 64}\end{array} $$ has the value t 1.12. (a) Find the P-value for this test using (i) Table B and (ii) your calculator. What conclusion would you draw at the 5% significance level? At the 1% significance level? (b) Redo part (a) using an alternative hypothesis of \(H_{a} : \mu<64 .\)

Short Answer

Expert verified
(a) Table B: P-value > 0.2; Calculator: P-value 鈮 0.272. Do not reject at 5% or 1%. (b) For \( H_a: \mu < 64 \), P-value 鈮 0.136; do not reject at 5% or 1% level.

Step by step solution

01

Understanding the Test Context

We are given a one-sample two-sided t-test with sample size \( n = 25 \) and a t-statistic \( t = 1.12 \). The null hypothesis is \( H_0: \mu = 64 \), and the alternative hypothesis is \( H_a: \mu eq 64 \). We need to find the P-value for this test and then interpret it against significance levels of 5% and 1%. We also need to repeat this process with \( H_a: \mu < 64 \).
02

Finding the P-value using Table B

The degrees of freedom (df) for this t-test is \( n - 1 = 24 \). Using Table B (commonly the t-distribution table), we locate the row for 24 df. We find the range in table for \( t = 1.12 \). Typically, t-tables provide cumulative probabilities for common significance levels. By locating the closest probabilities corresponding to \( t = 1.12 \), and remembering this is a two-tailed test, we multiply the found probability by 2 to get the P-value.
03

Finding the P-value using a Calculator

To find the P-value using a calculator, use the cumulative distribution function (CDF) for a t-distribution with 24 df. Calculate the cumulative probability for \( t = 1.12 \). Since this is a two-tailed test, double the one-tail probability. The P-value computed should match or closely approximate the value determined from Table B.
04

Conclusion at 5% Significance Level

Compare the computed P-value with 0.05. If the P-value is less than 0.05, reject the null hypothesis; otherwise, fail to reject it. This will determine if the data provides enough evidence against the null hypothesis at the 5% significance level.
05

Conclusion at 1% Significance Level

Compare the P-value with 0.01. If the P-value is less than 0.01, reject \( H_0 \); otherwise, fail to reject it. This leads to determining if there is strong evidence against \( H_0 \) under the stricter criteria of a 1% significance level.
06

Repeating the Test for H_a: \mu < 64

For \( H_a: \mu < 64 \), it becomes a one-sided test. Redo Steps 2 and 3, however, this time you only consider the negative tail since the hypothesis only covers deviations where the mean could be less than 64. Use Table B and calculator for a one-tail test to find the corresponding P-value. Compare these against the 5% and 1% levels, similar to Steps 4 and 5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-value calculation
The P-value in hypothesis testing is a critical measure used to make informed conclusions about statistical data. It represents the probability of observing the test results, or more extreme results, under the null hypothesis. In our exercise, the two-sided test involves a t-statistic, and we're tasked with finding the P-value.
  • To begin with, determine the degrees of freedom (df) which is calculated as the sample size minus one. For our sample size of 25, we have 24 df.
  • Next, we use a t-distribution table, commonly referred to as Table B, to find the P-value. Locate the value in the table that corresponds to our t-statistic of 1.12 and 24 df. The table provides cumulative probabilities, so it's crucial to remember that for a two-sided test, you multiply the found value by 2 to get the final P-value.
  • Alternatively, a calculator that supports statistical functions can simplify the process. Use the calculator's cumulative distribution function (CDF) for the t-distribution to find the one-tail probability for t = 1.12, and then double it to account for the two-sided nature of the test.
The calculated P-value helps gauge the possibility of rejecting the null hypothesis, based on the given significance levels, such as 5% or 1%.
Significance level
The concept of significance level is pivotal in hypothesis testing. It is the threshold at which we determine whether to reject the null hypothesis. Commonly expressed as a percentage, significance levels like 5% or 1% help manage the risk of making a Type I error 鈥 rejecting a true null hypothesis.
  • A 5% significance level signifies that we are willing to accept a 5% chance of wrongly rejecting the null hypothesis. Therefore, if the P-value is less than 0.05, we reject the null hypothesis in favor of the alternative hypothesis.
  • A 1% significance level represents a much stricter threshold. It's useful in situations where we require more robust evidence to reject the null hypothesis. If the P-value is less than 0.01, the null hypothesis is rejected with strong evidence against it.
By comparing the P-value with these levels, we derive meaningful conclusions about our hypothesis, determining whether the observed data is statistically significant.
Alternative hypothesis
The alternative hypothesis, denoted as \( H_a \), is a statement that suggests the null hypothesis is unlikely under the given data. In our exercise, initially, the alternative hypothesis was two-sided, \( H_a: \mu eq 64 \), indicating that the actual mean may be either greater or less than 64. This required us to consider both possible extremes of the distribution.
When we explore \( H_a: \mu < 64 \), the hypothesis becomes one-sided. This suggests an expectation or suspicion that the true mean is specifically less than the hypothesized mean of 64. This form of the hypothesis is more focused, looking only into one tail of the distribution for significant findings.
  • In a two-sided hypothesis, the P-value calculation considers both tails of the distribution. We double the probability from the t-table or calculator.
  • When a one-sided hypothesis like \( H_a: \mu < 64 \) is used, the P-value is straightforward and involves only the negative tail.
Understanding these distinctions in alternative hypotheses clarifies the direction of evidence we search for within our statistical test, guiding appropriate decision-making in statistical analysis.

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