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Multiple choice: Select the best answer for Exercises 49 to 52. Most people can roll their tongues, but many can鈥檛. The ability to roll the tongue is genetically determined. Suppose we are interested in determining what proportion of students can roll their tongues. We test a simple random sample of 400 students and find that 317 can roll their tongues. The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to (a) 0.008. (c) 0.03. (e) 0.208. (b) 0.02. (d) 0.04.

Short Answer

Expert verified
The best answer is (d) 0.04.

Step by step solution

01

Identify Sample Proportion

First, we need to identify the sample proportion of students who can roll their tongues. Given the data, 317 out of 400 students can roll their tongues. Thus, the sample proportion \( \hat{p} \) is calculated as:\[ \hat{p} = \frac{317}{400} = 0.7925 \]
02

Calculate Standard Error

Next, calculate the standard error (SE) of the sample proportion \( \hat{p} \). The formula for standard error is:\[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \]where \( n = 400 \). Substitute \( \hat{p} = 0.7925 \):\[ SE = \sqrt{\frac{0.7925(1 - 0.7925)}{400}} \]
03

Find the 95% Confidence Interval Margin of Error

To find the margin of error (ME) for a 95% confidence interval, we use the critical value associated with a 95% confidence level, which is approximately 1.96 for a normal distribution. The margin of error is given by:\[ ME = 1.96 \times SE \]Substitute the SE from the previous step to find ME.
04

Calculate and Compare Margin of Error

After computing the above expression, we find:\[ ME = 1.96 \times 0.0194 \approx 0.038 \]The margin of error closest to 0.038 is option (d) 0.04.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Proportion
Imagine you want to know how many of your classmates can roll their tongues. Instead of asking everyone, you decide to ask a smaller group and then use this group's answers to estimate the whole class's ability. This smaller group gives you the "sample proportion." In our exercise, out of 400 students sampled, 317 can roll their tongues. We calculate the sample proportion \( \hat{p} \) as \( \frac{317}{400} = 0.7925 \). This means approximately 79.25% of the sampled students can roll their tongues. The sample proportion is vital because it helps us estimate the true proportion in the entire population. It's our best guess based on the available data.
Calculating Standard Error
The standard error is like a yardstick to measure the accuracy of our sample proportion in estimating the true population proportion. It indicates how much we're likely to deviate from the real number if we took many samples. To find the standard error for our sample proportion, we use the formula:
  • \[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \], where \( n \) is the sample size.
In our case, \( \hat{p} = 0.7925 \) and \( n = 400 \). Plugging these values in gives us the standard error. Calculating this provides an understanding of the reliability and precision of our estimate. The smaller the standard error, the more confident we are in our sample proportion's estimate of the true population proportion.
The Importance of Margin of Error
The margin of error tells us how much we can expect our sample results to vary from the actual population results. It's like saying: "Our estimate is 79.25%, but it might be off by a bit either way." In our exercise, the margin of error is calculated using the formula:
  • \[ ME = 1.96 \times SE \]
The number 1.96 comes from the normal distribution, corresponding to a 95% confidence level. Plug in the standard error to get your margin of error. This tells us how far off our sample estimate might be from the true population value if we want to be 95% confident. A smaller margin means a more precise estimate.
Role of Normal Distribution
The normal distribution, often represented as a bell curve, gives us critical values for calculating the margin of error in confidence intervals. When our sample size is large, like in our exercise with 400 students, the sampling distribution of the sample proportion tends to be normally distributed. This allows us to use the normal distribution to find critical values like 1.96, which is used for a 95% confidence interval. The assumption of normality helps in accurately estimating how much our sample proportion might differ from the true population proportion. Understanding the normal distribution in this context tells us how confident we can be about the reliability of our estimates. It's an essential concept in statistics for interval estimation and hypothesis testing.

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