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Multiple choice: Select the best answer for Exercises 49 to 52. You want to design a study to estimate the proportion of students at your school who agree with the statement, 鈥淭he student government is an effective organization for expressing the needs of students to the administration.鈥 You will use a 95% confidence interval, and you would like the margin of error to be 0.05 or less. The minimum sample size required is (a) 22. (b) 271. (c) 385. (d) 769. (e) 1795.

Short Answer

Expert verified
The minimum sample size required is 385; choose option (c).

Step by step solution

01

Understand the Formula

To determine the sample size needed for a proportion, we use the formula for the margin of error of a confidence interval: \( ME = \sqrt{ \frac{p(1-p)}{n} } \). Here, \( ME \) is the margin of error, \( p \) is the estimated proportion (commonly \(0.5\) used when unknown), and \( n \) is the sample size. Note that z-values are used depending on the confidence level.
02

Identify Parameters

The problem specifies a 95% confidence interval which corresponds to a z-value of approximately 1.96. The margin of error desired is 0.05. We will assume \( p = 0.5 \) as we do not know the proportion.
03

Set Up the Inequality

We need \( ME \leq 0.05 \). Substitute \( ME \) in the inequality: \( 1.96 \times \sqrt{ \frac{0.5(1-0.5)}{n} } \leq 0.05 \).
04

Solve the Inequality for n

First, square both sides to remove the square root, giving: \( (1.96)^2 \times \frac{0.25}{n} \leq 0.0025 \). Then, solve for \( n \) to get \( n \geq \frac{(1.96)^2 \times 0.25}{0.0025} \).
05

Calculate the Minimum Sample Size

Substitute the values into the inequality: \( n \geq \frac{3.8416 \times 0.25}{0.0025} = 384.16 \). Round up to the nearest whole number, giving \( n = 385 \).
06

Choose the Correct Answer

Comparing the calculated sample size of 385 with the given options, option (c) 385 is the correct choice.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a critical concept in statistics, especially when estimating proportions in a population. It represents the range within which the true population parameter is expected to fall. In simple terms, margin of error tells us how much the estimated proportion could differ from the true proportion of the whole population. For example, in a survey, if we estimate that 40% of the students support the statement but have a margin of error of 5%, it means the real support could be anywhere between 35% to 45%.

What determines the margin of error?
  • Sample Size: Larger sample sizes generally decrease the margin of error because they provide more information about the population.
  • Confidence Level: A higher confidence level (like 99%) will result in a larger margin of error because you're more certain the interval contains the true proportion.
  • Estimated Proportion: A proportion close to 50% usually leads to a larger margin of error compared to proportions closer to 0% or 100%.
To find the desired sample size for a specific margin of error, such as 0.05 for this example, it's necessary to apply the margin of error formula and solve it accordingly.
Confidence Interval
Confidence intervals are a fundamental concept in statistics used to indicate the reliability of an estimate. A confidence interval provides a range that is likely to contain the true value of the population parameter, with a certain level of confidence. In our exercise, we're working with a 95% confidence interval. This means if we were to repeat the study 100 times, we would expect the true proportion to be within our calculated confidence intervals in 95 of those times.

To calculate a confidence interval:
  • Determine the sample proportion: This is your estimate from the sample data.
  • Identify the standard error: This measures how much the sample proportion is expected to vary due to random sampling.
  • Use the appropriate z-value: For a 95% confidence interval, this is typically 1.96.
The calculation uses the equation: \[ CI = ext{Sample Proportion} \pm (Z \times ext{Standard Error}) \]Confidence intervals are invaluable when making inferences about a population. They provide a range rather than a single estimate, offering more insight into the variability and reliability of the data.
Proportion Estimation
Proportion estimation involves determining the proportion of a particular characteristic or attribute in a population based on sample data. In our scenario, the goal is to estimate the proportion of students who agree that the student government is an effective organization.

Here's how proportion estimation typically works:
  • Select a Sample: Choose a random sample of individuals from the population.
  • Calculate the Sample Proportion: This is the fraction of your sample that has the characteristic of interest. In this situation, it's the percentage of students agreeing with the statement.
  • Estimate the Population Proportion: Use the sample proportion to estimate the population proportion, ensuring you account for potential sampling error by utilizing confidence intervals and margins of error.
The larger the sample, the more likely the sample proportion will be a close estimate of the true population proportion. In cases where there's no prior knowledge of the proportion, statisticians often use 0.5 as it provides the maximum variability and thus the largest sample size ensuring safety in estimations. This approach was indeed used in calculating the sample size in the exercise example.

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Most popular questions from this chapter

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