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93% confidence Find z* for a 93% confidence interval using Table A or your calculator. Show your method.

Short Answer

Expert verified
The \( z^* \) value for a 93% confidence interval is approximately 1.81.

Step by step solution

01

Understand Confidence Level and Critical Value

The confidence level tells us the proportion of samples that contain the population parameter when the method is used many times. The critical value \( z^* \) is the z-score that corresponds to the boundary between the middle \( 93\% \) and the tails \( 7\% \) in a standard normal distribution.
02

Determine Tail Areas

Since we're working with a 93% confidence interval in a symmetric distribution, the remaining probability is \( 1 - 0.93 = 0.07 \). This probability is shared equally by the two tails of the standard normal distribution. Thus, each tail has an area of \( \frac{0.07}{2} = 0.035 \).
03

Find Cumulative Probability for z*

The cumulative probability up to \( z^* \) from the left is \( 0.035 \), and from the right is \( 1 - 0.035 = 0.965 \). We look for this probability in the standard normal distribution table (or use a calculator) to find the corresponding z-score.
04

Use Standard Normal Distribution Table

Using the cumulative probability of \( 0.965 \), find the closest z-score in the standard normal distribution table. From the table, this cumulative probability corresponds to approximately \( z^* \approx 1.81 \).
05

Double-check with a Calculator

Using a calculator with inverse cumulative standard normal distribution function, enter \( 0.965 \) to find that \( z^* \approx 1.81 \) confirms our table lookup.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Value
The critical value, denoted as \( z^* \), is an essential component when computing confidence intervals. It is essentially a point on the scale of the standard normal distribution that captures the probability of observing a value less extreme than it under the null hypothesis. This value reliably serves the purpose of marking the boundary that separates the most probable 93% of the data from the more extreme 7%. If you picture the normal distribution curve, you would see this value lying at the edges of the middle area, thus forming the basis of the confidence interval. For a 93% confidence level, the critical value is inherently linked to a tail probability of 3.5% per side, helping in shaping this interval. By locating this critical value, you gain insight into how values compare to each other concerning the predicted mean value, establishing your interval's scope.
Standard Normal Distribution
The standard normal distribution is a bell-shaped curve representing a normal distribution with a mean of 0 and a standard deviation of 1. It's the foundation for understanding probability and statistics. When dealing with various forms of data, converting a normal distribution to a standard normal distribution simplifies the process of finding probabilities. The transformation to this form involves the formula \( z = \frac{X - ext{mean}}{ ext{standard deviation}} \), where \( z \) represents the z-score鈥攁 pivotal element in the exercise of finding z*. The standard normal distribution is symmetrical around the mean, making it straightforward to split data into sections using differences in \( z \)-scores. This aspect is pivotal in defining confidence intervals, as it enables us to identify areas under the curve that correspond to our level of confidence, exemplified by our exercise's 93% interval.
Cumulative Probability
Cumulative probability refers to the total probability that a variable takes on a value less than or equal to a specific threshold. For our use, it means "adding up" probabilities to reach a certain z-score value from the left of the curve. This cumulative aspect is vital when working out confidence intervals since acquiring exact areas beneath the curve helps to establish these intervals. For instance, tracing a cumulative probability of 0.965 indicates where the critical point lies on the standard normal distribution. By knowing that your cumulative probability up to the left edge of our interval is 0.035 and up to the right edge as 0.965, you can use standard normal distribution tables or a calculator to faithfully trace the z-score which marks your confidence interval boundaries.
z-score
The z-score is an instrumental statistical measure that signifies how many standard deviations an element is from the mean. When you calculate a z-score, you essentially standardize your data, making comparisons more manageable. The formula mentioned earlier demonstrates its calculation, where each element's deviation from the mean is divided by the standard deviation. In using a z-score within this context, the calculated \( z^* \) represents the critical upper limit of our confidence interval. For our 93% confidence level, the z-score acts as a border lining the confidence range. Using standard statistical tools like a z-score table or a calculator, you seek to find the score that ensures 93% of data lies within it under ideal normal distribution conditions. Keeping track of these scores becomes instrumental in many areas of statistics, providing a lens through which statistical hypotheses can be tested and understood.

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Most popular questions from this chapter

Multiple choice: Select the best answer for Exercises 49 to 52. You want to design a study to estimate the proportion of students at your school who agree with the statement, 鈥淭he student government is an effective organization for expressing the needs of students to the administration.鈥 You will use a 95% confidence interval, and you would like the margin of error to be 0.05 or less. The minimum sample size required is (a) 22. (b) 271. (c) 385. (d) 769. (e) 1795.

In Exercises 1 to 4, determine the point estimator you would use and calculate the value of the point estimate. Going to the prom Tonya wants to estimate what proportion of the seniors in her school plan to attend the prom. She interviews an SRS of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom.

A big-toe problem Hallux abducto valgus (call it HAV) is a deformation of the big toe that is fairly uncommon in youth and often requires surgery. Doctors used X-rays to measure the angle (in degrees) of deformity in a random sample of patients under the age of 21 who came to a medical center for surgery to correct HAV. The angle is a measure of the seriousness of the deformity. For these 21 patients, the mean HAV angle was 24.76 degrees and the standard deviation was 6.34 degrees. A dotplot of the data revealed no outliers or strong skewness. \(^{27}\) (a) Construct and interpret a 90% confidence interval for the mean HAV angle in the population of all such patients. (b) Researchers omitted one patient with an HAV angle of 50 degrees from the analysis due to a measurement issue. What effect would including this outlier have on the confidence interval in (a)? Justify your answer.

Critical values What critical value t* from Table B would you use for a confidence interval for the population mean in each of the following situations? (a) A 95% confidence interval based on n 10 observations. (b) A 99% confidence interval from an SRS of 20 observations.

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this question to an SRS of 172 undergraduates at a large university: 鈥淵ou witness two students cheating on a quiz. Do you go to the professor? Only 19 answered "Yes." (a) Identify the population and parameter of interest. (b) Check conditions for constructing a confidence interval for the parameter. (c) Construct a 99% confidence interval for p. Show your method. (d) Interpret the interval in context.

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