/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 For Exercises 27 to 30, check wh... [FREE SOLUTION] | 91影视

91影视

For Exercises 27 to 30, check whether each of the conditions is met for calculating a confidence interval for the population proportion p. High tuition costs Glenn wonders what proportion of the students at his school think that tuition is too high. He interviews an SRS of 50 of the 2400 students at his college. Thirty- eight of those interviewed think tuition is too high.

Short Answer

Expert verified
All conditions for calculating a confidence interval for the population proportion are satisfied.

Step by step solution

01

Verify Sample Randomness

The problem states that Glenn interviewed a Simple Random Sample (SRS) of 50 students from the college. This condition is satisfied as an SRS ensures that each student had an equal chance of being selected.
02

Check Sample Size Condition

The condition for the sample size is that the sample size should be less than 10% of the population for independence. Here, the sample size is 50, which is indeed less than 10% of 2400 students (10% of 2400 is 240). Therefore, this condition is satisfied.
03

Check Success/Failure Condition

For calculating a confidence interval, both the number of `successes` and the number of `failures` should be at least 10. In this case, `successes` refers to students who think tuition is too high (38 students), and `failures` refers to those who do not think so (50 - 38 = 12 students). Both numbers are greater than 10, satisfying this condition.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion (\( p \)) represents the fraction of a population that possesses a certain characteristic. It is often difficult to measure directly. Instead, we estimate it using sample data. In this exercise, Glenn is interested in finding the proportion of students who believe tuition costs are too high.

We use the sample proportion (\( \hat{p} \)) to estimate the population proportion. This sample proportion is calculated as the number of successes (i.e., students who think tuition is too high) divided by the total number of observations in the sample. Thus, \( \hat{p} = \frac{38}{50} \). This is a critical step in creating a confidence interval, which gives us a range of values within which we expect the true population proportion to fall.

A confidence interval helps us understand the precision of our estimate, offering a window around the sample proportion where we expect the actual population proportion to lie. The wider the interval, the more uncertainty there is about the population proportion.
Simple Random Sample (SRS)
A Simple Random Sample (SRS) is a sampling method where each member of the population has an equal chance of being selected. This is crucial for ensuring that the sample represents the entire population well, avoiding biases in the data.

In the given exercise, Glenn used an SRS of 50 students from his college. This means that each of the 2400 students at his school had an equal opportunity of being included in the survey. When an SRS is employed, the statistical inferences drawn, such as confidence intervals, are more reliable because the sample is less likely to be skewed or biased.

The simplicity of the Simple Random Sample doesn't mean it's easy to perform in practice, especially with large populations. However, it is one of the best ways to gather representative data for statistical analysis.
Sample Size Condition
The Sample Size Condition states that the sample should be less than 10% of the entire population. This ensures that the sample is independent and does not overly represent the population, which could skew results.

In Glenn's case, the sample size of 50 students is significantly less than 10% of the total population of 2400 students (as 10% would be 240 students). This condition is important because it supports the validity of the statistical methods used, including the calculation of confidence intervals.

Adhering to the Sample Size Condition allows us to draw more accurate conclusions from the sample. It minimizes the effects that may arise from having too large a sample relative to the population, which could lead to dependency issues.
Success/Failure Condition
The Success/Failure Condition is necessary for calculating a valid confidence interval for a population proportion. It stipulates that both the number of 'successes' and the number of 'failures' in the sample should be at least 10.

In the situation outlined in the exercise, a 'success' is when a student believes that tuition is too high, whereas a 'failure' is when a student does not. With 38 successes and 12 failures (\( 50 - 38 = 12 \)), both numbers exceed the minimum requirement of 10.

This condition ensures that the distribution of the sample proportion is approximately normal. A normal distribution allows us to apply certain statistical methods more effectively, such as the creation of a confidence interval. Without meeting this condition, any results derived from the analysis might be unreliable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Multiple choice: Select the best answer for Exercises 49 to 52. I collect an SRS of size n from a population and compute a 95% confidence interval for the population proportion. Which of the following would produce a new confidence interval with larger width (larger margin of error) based on these same data? (a) Use a larger confidence level. (b) Use a smaller confidence level. (c) Increase the sample size. (d) Use the same confidence level, but compute the interval n times. Approximately 5% of these intervals will be larger. (e) Nothing can guarantee absolutely that you will get a larger interval. One can only say that the chance of obtaining a larger interval is 0.05.

Multiple choice: Select the best answer for Exercises 21 to 24. A polling organization announces that the proportion of American voters who favor congressional term limits is 64%, with a 95% confidence margin of error of 3%. If the opinion poll had announced the margin of error for 80% confidence rather than 95% confidence, this margin of error would be (a) 3%, because the same sample is used. (b) less than 3%, because we require less confidence. (c) less than 3%, because the sample size is smaller. (d) greater than 3%, because we require less confidence. (e) greater than 3%, because the sample size is smaller.

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this question to an SRS of 172 undergraduates at a large university: 鈥淵ou witness two students cheating on a quiz. Do you go to the professor? Only 19 answered "Yes." (a) Identify the population and parameter of interest. (b) Check conditions for constructing a confidence interval for the parameter. (c) Construct a 99% confidence interval for p. Show your method. (d) Interpret the interval in context.

Abstain from drinking In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students were classified as abstainers (nondrinkers). (a) Construct and interpret a 99% confidence interval for p. Follow the four- step process. (b) A newspaper article claims that 25% of U.S. college students are nondrinkers. Use your result from (a) to comment on this claim.

Lying online Many teens have posted profiles on sites such as Facebook and MySpace. A sample survey asked random samples of teens with online profiles if they included false information in their profiles. Of 170 younger teens (ages 12 to 14) polled, 117 said 鈥淵es.鈥 Of 317 older teens (ages 15 to 17) polled, 152 said 鈥淵es.鈥6 A 95% confidence interval for the difference in the population proportions (younger teens 鈥 older teens) is 0.120 to 0.297. Interpret the confidence interval and the confidence level.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.