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Songs on an iPod David's iPod has about \(10,000\) songs. The distribution of the play times for these songs is heavily skewed to the right with a mean of 225 seconds and a standard deviation of \(60 \mathrm{seconds}\). Suppose we choose an SRS of 10 songs from this population and calculate the mean play time \(\overline{x}\) of these songs. What are the mean and the standard deviation of the sampling distribution of \(\overline{x} ?\) Explain.

Short Answer

Expert verified
The mean is 225 seconds and the standard deviation is approximately 18.97 seconds.

Step by step solution

01

Understanding the Problem

We are asked to find the mean and standard deviation of the sampling distribution of the sample mean, \(\overline{x}\), for samples taken from a population of songs.
02

Identify the Given Information

The population mean \(\mu\) is given as 225 seconds, and the population standard deviation \(\sigma\) is 60 seconds. We take a sample size \(n\) of 10 songs.
03

Determine the Sampling Distribution Mean

For the sample mean \(\overline{x}\), the mean \(\mu_{\overline{x}}\) of the sampling distribution is the same as the population mean. Therefore, \(\mu_{\overline{x}} = \mu = 225 \text{ seconds}\).
04

Calculate the Standard Deviation of the Sampling Distribution

The standard deviation of the sample mean (often referred to as the standard error) is given by the formula \(\sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}\). Substituting the given values, \(\sigma_{\overline{x}} = \frac{60}{\sqrt{10}}\approx 18.97 \text{ seconds}\).
05

Conclusion and Explanation

The mean of the sampling distribution of \(\overline{x}\) remains 225 seconds, and the standard deviation is reduced to about 18.97 seconds due to the effect of averaging over a sample of size 10. This shows that the spread of the sample means is much smaller than that of individual observations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
In statistics, the mean refers to the average value of a data set. It's a central concept because it provides a single value that summarizes an entire distribution of numbers. To find the mean, you add up all the numbers and divide by the total count of values.
For instance, in David's iPod example, the mean play time \( \mu \) of the songs is provided as 225 seconds. This tells us that, on average, each song has a playtime of 225 seconds.
The mean is a fundamental building block when dealing with sampling distributions. When a random sample is taken, the mean of that sample, denoted as \( \overline{x} \), may differ from the population mean but tends towards it as the sample size increases. This tendency is crucial when analyzing sample data because it helps to estimate the population mean reliably.
The mean of a sampling distribution, \( \mu_{\overline{x}} \), reflects the mean of the population, meaning sample averages calculated will hover around this central point.
Standard Deviation
The standard deviation is a measure that describes how spread out the numbers are in a data set. It indicates how much the data points typically deviate from the mean.
In other words, it helps reveal the variability or dispersion present in the data.
For David's iPod, the standard deviation \( \sigma \) of the songs' play times is 60 seconds, showing how widely the lengths of the songs vary from the average 225 seconds.
When dealing with sampling, the standard deviation also plays a key role in indicating the variability of a sample mean. The standard deviation of a sampling distribution is termed the 'standard error' and can be calculated using the formula:
  • \( \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}} \)
where \( \sigma \) is the population standard deviation and \( n \) is the sample size.
In our example, for a sample of 10 songs, the standard error is approximately 18.97 seconds. This reduced variability is due to the averaging process involved in calculating samples, which minimizes the impact of extreme values.
Central Limit Theorem
The Central Limit Theorem (CLT) is one of the cornerstones of statistics, particularly in the context of sampling distributions. It explains why the normal distribution turns up so frequently in statistical analysis.
According to the CLT, the distribution of the sample mean \( \overline{x} \) approaches a normal distribution as the sample size \( n \) increases, even if the original population distribution is not normal.
  • This theorem holds true generally for sample sizes of 30 or more. However, it can also apply to smaller sample sizes, especially if the population distribution is not heavily skewed.
In David's iPod case, where the distribution is heavily skewed to the right, the CLT assures us that with a large enough sample size, the distribution of the sample mean will still approach normalcy. For our sample size of 10, it suggests that while the approximation might not be perfect, the sample means will still center around the population mean, i.e., 225 seconds. This insight guides statisticians to make inferences about population parameters even when dealing with non-normal data.

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