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How tall? 6.2 ) The heights of young men follow a Normal distribution with mean 69.3 inches and standard deviation 2.8 inches. The heights of young women follow a Normal distribution with mean 64.5 inches and standard deviation 2.5 inches. (a) Let \(M=\) the height of a randomly selected young man and \(W=\) the height of a randomly selected young woman. Describe the shape, center, and spread of the distribution of \(M-W\) (b) Find the probability that a randomly selected young man is at least 2 inches taller than a randomly selected young woman. Show your work.

Short Answer

Expert verified
The probability that a man is at least 2 inches taller than a woman is 0.7734.

Step by step solution

01

Understanding the combined distribution

Given the heights of young men and women are normally distributed, their difference, \(M-W\), is also normally distributed. The center of this distribution is the difference in their means, \(69.3 - 64.5 = 4.8\), and the spread (or standard deviation) is the square root of the sum of their variances, \(\sqrt{2.8^2 + 2.5^2}\).
02

Calculate the variance and standard deviation of M-W

The variance of \(M - W\) is equal to the sum of the variances of \(M\) and \(W\), so \(\sigma_{M-W}^2 = 2.8^2 + 2.5^2 = 7.84 + 6.25 = 14.09\). The standard deviation is \(\sigma_{M-W} = \sqrt{14.09} \approx 3.75\).
03

Describe the distribution of M-W

The distribution of \(M-W\) is Normal with mean \(\mu = 4.8\) inches and standard deviation \(\sigma \approx 3.75\) inches.
04

Determine the success condition

We need the probability that \(M - W \geq 2\). This translates to finding \(P(M - W \geq 2)\).
05

Standardize the distribution

Convert the variable \(M-W\) into a standard normal variable \(Z\) using \(Z = \frac{(M-W) - \mu}{\sigma}\). For \(M-W = 2\), \(Z = \frac{2 - 4.8}{3.75} \approx -0.75\).
06

Compute the probability using the standard normal table

The probability we need is \(P(Z \geq -0.75)\). Using the Z-table or a statistical calculator, \(P(Z \geq -0.75) = 0.7734\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is the measure of the likelihood that an event will occur. In statistics, it helps us predict future events based on patterns, and is expressed as a number between 0 and 1.
A probability of 0 means an event will not happen, while a probability of 1 means it definitely will.
In the context of our problem, we're trying to find the probability that a randomly selected young man is at least 2 inches taller than a randomly selected young woman. This is a nice example of using probability to make a prediction based on a statistical distribution.
To calculate this, we use the concept of the Normal distribution and the Z-score, which is a measure of how many standard deviations an element is from the mean. This allows us to transform the problem into one involving the standard normal distribution, making it easier to find the required probability using Z-tables or calculators.
  • Probability is between 0 and 1
  • Used to predict how likely an event is
  • Helps to understand normal distributions, such as the one in our problem
Standard Deviation
Standard deviation is a measure of how spread out the numbers in a data set are. It tells us the average distance of the data points from the mean.
In a Normal distribution, most data points fall within one standard deviation of the mean. Less will be two standard deviations away, and even fewer will be three or more.
In our example, the standard deviations for the heights of young men and women were given as 2.8 inches and 2.5 inches, respectively. When comparing the two groups' heights, we calculated the standard deviation of the difference, known as the spread of the new distribution, to be approximately 3.75 inches.
This number is crucial because it quantifies the variability we might expect between the heights of randomly selected members of each group. It helps determine how much individual heights differ from the average difference.
  • Measures spread of a data set
  • Essential in calculating probability in Normal distributions
  • For the problem, \(\sigma_{M-W} \approx 3.75\) inches indicates variability between compared heights
Variance
Variance gives us an initial insight into data variability by measuring how far each number in the set is from the mean and consequently from every other number in the set.
Essentially, it's the square of the standard deviation. This means if you have the variance, you can find the standard deviation by taking the square root.
In statistical terms, for normally distributed variables like the heights in our exercise, the variance lets us calculate how much these individual heights differ. In our case, to find the variance of the distribution of the difference between men and women's heights, we sum their individual variances: \[\sigma_{M-W}^2 = 2.8^2 + 2.5^2 = 7.84 + 6.25 = 14.09\]This number might seem abstract, but when you take its square root, you find the standard deviation, which is more intuitive.
Variance can initially seem complex, but it's very useful in calculating the likelihood of events when combined with other statistical tools.
  • Variance is critical in understanding data spread
  • Square of standard deviation
  • Variance of heights difference helps predict individual variance between random members
Mean
The mean, or average, is a fundamental statistical measure. It sums up all data points and divides by the number of points to provide the central value of the data.
It's the center of a Normal distribution, where data points are equally distributed around the mean.
In the exercise provided, we calculated the mean of the difference in heights between young men and women, which was found to be:\[\mu_{M-W} = 69.3 - 64.5 = 4.8\] This tells us that, on average, young men are 4.8 inches taller than young women.
Understanding the mean is crucial because it gives us the "center" of our data, which informs discussions about probability, standard deviation, and other statistical insights.
  • Also known as the average
  • Central point of data distribution
  • Crucial for determining probability and variability

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Most popular questions from this chapter

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