/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Exercises 23 through 26 involve ... [FREE SOLUTION] | 91影视

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Exercises 23 through 26 involve the following setting. Some women would like to have children but cannot do so for medical reasons. One option for these women is a procedure called in vitro fertilization (IVF), which involves injecting a fertilized egg into the woman鈥檚 uterus. Prayer and pregnancy Two hundred women who were about to undergo IVF served as subjects in an experiment. Each subject was randomly assigned to either a treatment group or a control group. Women in the treatment group were intentionally prayed for by several people (called intercessors) who did not know them, a process known as intercessory prayer. The praying continued for three weeks following IVF. The intercessors did not pray for the women in the control group. Here are the results: 44 of the 88 women in the treatment group got pregnant, compared to 21 out of 81 in the control group.\(^{17}\) Is the pregnancy rate significantly higher for women who received intercessory prayer? To find out, researchers perform a test of \(H_{0} : p_{1}=p_{2}\) versus \(H_{a} : p_{1}>p_{2},\) where \(p_{1}\) and \(p_{2}\) are the actual pregnancy rates for women like those in the study who do and don't receive intercessory prayer, respectively. (a) Name the appropriate test and check that the conditions for carrying out this test are met. (b) The appropriate test from part (a) yields a P-value of 0.0007. Interpret this P-value in context. (c) What conclusion should researchers draw at the \(\alpha=0.05\) significance level? Explain. (d) The women in the study did not know if they were being prayed for. Explain why this is important.

Short Answer

Expert verified
Researchers should conduct a two-sample z-test for proportions; the P-value is interpreted as significant, leading to rejection of the null hypothesis. Blinding ensures unbiased results.

Step by step solution

01

Identify the appropriate test for the hypothesis test

Since we are comparing two proportions (the pregnancy rates for women who received intercessory prayer and those who didn't), we use a two-sample z-test for proportions. The hypotheses are stated as follows:- Null hypothesis (H_{0}): \( p_{1} = p_{2} \) (the proportions are equal)- Alternative hypothesis (H_{a}): \( p_{1} > p_{2} \) (the proportion of women getting pregnant in the treatment group is greater than in the control group).
02

Check the conditions for the z-test for proportions

The conditions required for the z-test for proportions are:- Random sampling: The subjects were randomly assigned to treatment and control groups.- Independence: The results of one subject should not influence the others.- Normality: Both groups should satisfy \( np \geq 10 \) and \( n(1-p) \geq 10 \).For the treatment group, \( np = 88 \cdot 0.5 = 44 \) and \( n(1-p) = 88 \cdot 0.5 = 44 \);for the control group, \( np = 81 \cdot 0.5 = 40.5 \) and \( n(1-p) = 81 \cdot 0.5 = 40.5 \). Both are greater than 10, so the normality condition is satisfied.
03

Interpret the P-value

A P-value of 0.0007 indicates there is a 0.07% probability of observing a difference in proportions as large as (44/88) vs. (21/81) or more extreme, if the null hypothesis (\( p_{1} = p_{2} \)) is true. This low P-value suggests that the observed difference is unlikely to have occurred by chance alone.
04

Make a conclusion at the significance level \(\alpha=0.05\)

Since the P-value (0.0007) is much less than the significance level of 0.05, we reject the null hypothesis \( H_{0} \). Researchers conclude that there is significant evidence at the \( \alpha = 0.05 \) level that the pregnancy rate is higher for women who received intercessory prayer.
05

Importance of blinding the participants

Blinding ensures that the women didn't know if they were receiving prayer, which eliminates bias that could affect their physiological response or outcomes. This helps to ensure that differences in pregnancy rates are due to the treatment (intercessory prayer) rather than psychological factors such as stress or expectations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-sample z-test
A two-sample z-test is a statistical method used to determine if there is a significant difference between the proportions of two independent groups. In the context of the IVF experiment, it was used to compare the pregnancy rates of women who were prayed for and those who were not.
The null hypothesis (\( H_0 \)) posits that there is no difference between the two groups; specifically, that the proportions are equal. On the other hand, the alternative hypothesis (\( H_a \)) suggests that the pregnancy rate for women who received prayer is greater than that for those who did not. Consequently, if the test finds significant difference, it implies that intercessory prayer might have an impact on pregnancy outcomes.
It's crucial to ensure that conditions for the z-test are met. These include random sampling, independence of observations, and the normality condition, which states that both groups must have expected frequencies of successes and failures \( \geq 10 \). In this case, these conditions were checked and satisfied, validating the use of the z-test.
P-value Interpretation
The P-value is a critical aspect of hypothesis testing, providing a measure of statistical significance. In the IVF study, a P-value of 0.0007 was calculated using the two-sample z-test.
This P-value tells us the probability of observing the difference in pregnancy proportions between the treatment and control groups, assuming the null hypothesis is true. A P-value of 0.0007 means there is only a 0.07% chance that the observed result, or one more extreme, would occur due to random chance alone.
A low P-value, such as 0.0007, indicates strong evidence against the null hypothesis, suggesting that the observed difference in pregnancy rates is unlikely to have occurred by chance, and may be attributed to the intercessory prayer.
Significance Level
The significance level, denoted as \( \alpha \), is the threshold used to decide whether to reject the null hypothesis. Typically, a \( \alpha \) of 0.05 is utilized in many scientific studies, including the IVF experiment.
If the P-value is less than or equal to \( \alpha \), the null hypothesis is rejected. In the IVF study, since the P-value (0.0007) is much smaller than 0.05, it provides strong evidence against \( H_0 \), leading researchers to conclude that intercessory prayer has a significant effect on increasing pregnancy rates.
This significance level acts as a safeguard against making a Type I error鈥攊ncorrectly rejecting a true null hypothesis. It is important to choose a significance level that balances the risks of Type I and Type II errors, ensuring reliable conclusions.
Experimental Design
The design of an experiment greatly affects its validity and reliability. In the IVF study, the experimental design included important elements like randomization and blinding, which enhance the study's robustness.
Randomization involved randomly assigning participants to either the treatment group or the control group. This process ensures that each participant has an equal chance of receiving any treatment, helping to eliminate selection bias and confounding variables.
Blinding was another key feature in this experiment. The participating women did not know whether they were being prayed for, preventing them from potentially altering their behavior or physiological response based on expectations or stress. Meanwhile, those who offered prayers also did not know the women they were praying for, maintaining objectivity.
  • Randomization reduces bias and allows for the generalization of results to the larger population.
  • Blinding helps ensure that observed effects are due to the treatment, not psychological influences or expectations.
This careful design strengthens the credibility of the results, suggesting that any observed differences in pregnancy rates are likely due to the treatment effect of intercessory prayer.

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Most popular questions from this chapter

Exercises 23 through 26 involve the following setting. Some women would like to have children but cannot do so for medical reasons. One option for these women is a procedure called in vitro fertilization (IVF), which involves injecting a fertilized egg into the woman鈥檚 uterus. Acupuncture and pregnancy A study reported in the medical journal Fertility and Sterility sought to determine whether the ancient Chinese art of acupuncture could help infertile women become pregnant.\(^{18}\) One hundred sixty healthy women who planned to have IVF were recruited for the study. Half of the subjects (80) were randomly assigned to receive acupuncture 25 minutes before embryo transfer and again 25 minutes after the transfer. The remaining 80 women were assigned to a control group and instructed to lie still for 25 minutes after the embryo transfer. Results are shown in the table below. $$\begin{array}{ll}&{\text { Acupuncture group }} & {\text { Control group }} \\\ \text { Pregnant } & \quad\quad\quad\quad {34} & \quad\quad\quad {21} \\\ \text { Not Pregnant } & \quad\quad\quad\quad {46} & \quad\quad\quad {59} \\\ \text { Total } & \quad\quad\quad\quad {80} & \quad\quad\quad {80}\end{array}$$ Is the pregnancy rate significantly higher for women who received acupuncture? To find out, researchers perform a test of \(H_{0} : p_{1}=p_{2}\) versus \(H_{a} : p_{1}>p_{2},\) where \(p_{1}\) and \(p_{2}\) are the actual pregnancy rates for women like those in the study who do and don't receive acupuncture, respectively. (a) Name the appropriate test and check that the conditions for carrying out this test are met. (b) The appropriate test from part (a) yields a P-value of 0.0152. Interpret this P-value in context. (c) What conclusion should researchers draw at the \(\alpha=0.05\) significance level? Explain. (d) What flaw in the design of the experiment prevents us from drawing a cause-and-effect conclusion? Explain.

Fear of crime The elderly fear crime more than younger people, even though they are less likely to be victims of crime. One study recruited separate random samples of 56 black women and 63 black men over the age of 65 from Atlantic City, New Jersey. Of the women, 27 said they 鈥渇elt vulnerable鈥 to crime; 46 of the men said this.\(^{12}\) (a) Construct and interpret a 90% confidence interval for the difference in population proportions (men minus women). (b) Does your interval from part (a) give convincing evidence of a difference between the population proportions? Explain.

Exercises 33 and 34 refer to the following setting. Thirty randomly selected seniors at Council High School were asked to report the age (in years) and mileage of their main vehicles. Here is a scatterplot of the data: We used Minitab to perform a least-squares regression analysis for these data. Part of the computer output from this regression is shown below. Predictor \(\quad\) coef \(\quad\) stdev \(\quad\) t-ratio \(\quad \mathrm{P}\) Constant \(-13832 \qquad 8773 \qquad-1.58 \qquad 0.126\) Age \(\quad 14954 \qquad 1546 \qquad 9.67 \quad 0.000\) \(s=22723 \qquad R-s q=77.08 \qquad R-s q(a d j)=76.18\) Drive my car (3.2, 4.3) (a) Explain what the value of r2 tells you about how well the least-squares line fits the data. (b) The mean age of the students鈥 cars in the sample was x 8 years. Find the mean mileage of the cars in the sample. Show your work. (c) Interpret the value of s in the context of this setting. (d) Would it be reasonable to use the least-squares line to predict a car鈥檚 mileage from its age for a Council High School teacher? Justify your answer.

Paying for college College financial aid offices expect students to use summer earnings to help pay for college. But how large are these earnings? One large university studied this question by asking a random sample of 1296 students who had summer jobs how much they earned. The financial aid office separated the responses into two groups based on gender. Here are the data in summary form:\(^{33}\) $$\begin{array}{llll}{\text { Group }} & {n} & {\overline{x}} & {s_{x}} \\\ \hline \text { Males } & {675} & {\$ 1884.52} & {\$ 13688.37} \\ {\text { Females }} & {621} & {\$ 1360.39} & {\$ 1037.46}\end{array}$$ (a) How can you tell from the summary statistics that the distribution of earnings in each group is strongly skewed to the right? A graph of the data reveals no outliers. The use of two-sample t procedures is still justified. Why? (b) Construct and interpret a 90% confidence interval for the difference between the mean summer earnings of male and female students at this university. (c) Interpret the 90% confidence level in the context of this study.

Web business You want to compare the daily sales for two different designs of Web pages for your Internet business. You assign the next 60 days to either Design A or Design B, 30 days to each. (a) Describe how you would assign the days for Design A and Design B using the partial line of random digits provided below. Then use your plan to select the first three days for using Design A. Show your method clearly on your paper. $$24005 \qquad 52114 \qquad 26224 \qquad 39078$$ (b) Would you use a one-sided or a two-sided significance test for this problem? Explain your choice. Then set up appropriate hypotheses. (c) If you plan to use Table B to calculate the P-value, what are the degrees of freedom? (d) The t statistic for comparing the mean sales is 2.06. Using Table B, what P-value would you report? What would you conclude?

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