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Coin Tossing. The French naturalist Count Buffon (1707-1788) tossed a coin 4040 times. The result was 2048 heads, with \(\frac{2048}{4040}=0.5069\) the proportion of heads. Is this evidence that the coin was not fair? State the appropriate hypotheses and give the P-value.

Short Answer

Expert verified
There is not enough evidence to conclude the coin is not fair.

Step by step solution

01

State the Hypotheses

To determine if the coin is not fair, we set up the null and alternative hypotheses. The null hypothesis (\(H_0\)) states that the coin is fair, i.e., the probability of heads (\(p\)) is 0.5: \(H_0: p = 0.5\). The alternative hypothesis (\(H_a\)) is that the coin is not fair, i.e., \(H_a: p eq 0.5\).
02

Calculate the Standard Deviation

We calculate the standard deviation (\(\sigma\)) for the proportion of a fair coin, using the formula \(\sigma = \sqrt{\frac{p(1-p)}{n}}\), where \(n\) is the number of trials. Here, \(p = 0.5\) and \(n = 4040\), so: \(\sigma = \sqrt{\frac{0.5 \times 0.5}{4040}} = 0.00785\).
03

Calculate the Test Statistic

The Z-score (test statistic) is calculated using \(Z = \frac{\hat{p} - p}{\sigma}\), where \(\hat{p}\) is the sample proportion. With \(\hat{p} = 0.5069, p = 0.5,\) and \(\sigma = 0.00785\), we get: \(Z = \frac{0.5069 - 0.5}{0.00785} = 0.878\).
04

Determine the P-value

Using the Z-score, we find the P-value. Since this is a two-tailed test, we calculate the area under the standard normal distribution beyond \(\pm Z\). With \(Z = 0.878\), the P-value is approximately 0.38.
05

Make a Decision

Given a common significance level of 0.05, compare the P-value to the significance level. Here, the P-value of 0.38 is greater than 0.05, so we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis ( H_0 ) is a key element. It represents a starting point where it is assumed that there is no effect or that a specific condition holds true unless there is strong evidence against it. For instance, in the coin toss experiment by Count Buffon, the null hypothesis was that the coin is fair. This means the probability of getting heads is 0.5. Formally, we write this as:
  • H_0: p = 0.5
This hypothesis is tested statistically to find any evidence that could contradict it. Remember, the null hypothesis is a default position we aim to test, not something we necessarily want to prove. It's often tested with the hope of finding sufficient reasons to reject it when considering the experiment's outcome.
Z-score
The Z-score is a crucial component in hypothesis testing, which quantifies how far a data point is from the average of the data set. It tells us how many standard deviations away the observed value is from the expected value.
  • A Z-score is used to determine the position of a value within a distribution.
  • It lets us understand if the observed data deviates significantly from what's expected under the null hypothesis.
In the context of our coin tossing example, the Z-score helps in assessing whether the proportion of heads, 0.5069, is statistically different from the expected 0.5 if the coin were fair:\[Z = \frac{\hat{p} - p}{\sigma}\]Here, \(\hat{p}\) is the sample proportion, \(p\) is the expected proportion for a fair coin, and \(\sigma\) is the standard deviation of the distribution.
P-value
The P-value is another essential component that helps us to interpret the Z-score result. It's the probability of obtaining a result at least as extreme as the observed results of a statistical hypothesis test, assuming that the null hypothesis is true.
  • The P-value measures the strength of evidence against the null hypothesis.
  • A lower P-value indicates stronger evidence in favor of the alternative hypothesis (that the coin is not fair).
In Buffon's coin-tossing, the calculated P-value was approximately 0.38. This represents the probability of obtaining a sample proportion as extreme as 0.5069, given the null hypothesis \(H_0: p = 0.5\). Quite intuitively, a P-value larger than a pre-decided threshold indicates insufficient evidence against the null hypothesis.
Significance Level
The significance level, often denoted by \(\alpha\), is a threshold set by the researcher before conducting the hypothesis test. It dictates the probability of rejecting the null hypothesis when it's true (Type I error).
  • Common significance levels are 0.05, 0.01, or 0.10.
  • The significance level determines how cautiously one interprets the P-value.
In the example, we used a common significance level of 0.05. This means we would reject the null hypothesis if the P-value was less than 0.05. However, since the P-value (0.38) is greater than 0.05, we have insufficient evidence to claim the coin is unfair. Thus, we "fail to reject" the null, aligning our decision based on this chosen level of significance.

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Most popular questions from this chapter

A Gallup Poll in November 2019 found that \(55 \%\) of the people in the sample said they wanted to lose weight. The poll's margin of error for \(95 \%\) confidence was \(4 \%\). This means that a. the poll used a method that gets an answer within \(4 \%\) of the truth about the population \(95 \%\) of the time. b. we can be sure that the percentage of all adults who want to lose weight is between \(50 \%\) and \(58 \%\). c. if Gallup takes another poll using the same method, the results of the second poll will lie between \(51 \%\) and \(59 \%\).

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