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A Gallup Poll in November 2019 found that \(55 \%\) of the people in the sample said they wanted to lose weight. The poll's margin of error for \(95 \%\) confidence was \(4 \%\). This means that a. the poll used a method that gets an answer within \(4 \%\) of the truth about the population \(95 \%\) of the time. b. we can be sure that the percentage of all adults who want to lose weight is between \(50 \%\) and \(58 \%\). c. if Gallup takes another poll using the same method, the results of the second poll will lie between \(51 \%\) and \(59 \%\).

Short Answer

Expert verified
The correct answer is (a).

Step by step solution

01

Understanding the Problem

We are given a Gallup Poll finding and a margin of error. The poll determined that 55% of people in the sample wanted to lose weight with a 4% margin of error at a 95% confidence level. We need to determine what this margin of error and confidence level imply about the population and poll results.
02

Interpreting Margin of Error

The margin of error is a statistical estimate expressing the amount of random sampling error in a survey's results. In this case, a 4% margin of error means that the true percentage of the population who want to lose weight is expected to be within 4% of the sample result, 95% of the time.
03

Calculating Confidence Interval

To find the confidence interval, subtract and add the margin of error from the sample percentage: 55% - 4% = 51% and 55% + 4% = 59%. Thus, the confidence interval is from 51% to 59%, meaning we are 95% confident that the true percentage of the whole population who want to lose weight falls within this range.
04

Analyzing Each Option

- Option (a): States the method gets an answer within 4% of the truth 95% of the time, which is true because it describes a confidence interval. - Option (b): Claims certainty about the percentage falling between 50% and 58%, which is incorrect as it doesn't consider the margin of error interval properly. - Option (c): Claims future polls will fall in a different range, which misconstrues what the margin of error represents.
05

Determining the Correct Answer

Based on the definition and calculation of confidence intervals and margin of error, option (a) correctly describes the significance of the margin of error with respect to Gallup's polling method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a crucial concept in statistics, especially when understanding the results of polls or surveys. This number tells us how much we can expect the results of our sample to differ from the actual opinions or behaviors of the population. In a survey, like the Gallup Poll, it's common to include a margin of error. Here, it was noted as 4% at a 95% confidence level. This means that, based on the sample, we are confident that the true proportion of the entire population will fall within 4 percentage points above or below the sample estimate. To illustrate this, if 55% of those surveyed want to lose weight, the margin of error tells us the true proportion of the population likely falls between 51% and 59%. Thus, this margin of error is a built-in acknowledgment of the variability and uncertainty in sampling methods.
Statistical Estimation
Statistical estimation involves using data from a sample to infer information about a larger population. In the context of the Gallup Poll, this means taking the 55% of people surveyed who expressed a desire to lose weight and using that figure to estimate a similar trend in the broader population. Estimates are not just about providing a single value; they come with a level of certainty or confidence. For Gallup, the 95% confidence level involves a calculated range, or confidence interval (i.e., from 51% to 59%), reflecting where the true population parameter is likely to fall, with a high degree of certainty. Using a confidence interval gives a more reliable sense of an estimate, as it represents the scope of variability accounted for by the margin of error. Thus, statistical estimation provides a framework for making informed predictions about a population, acknowledging that complete certainty is rare, and instead offering a probable range.
Random Sampling Error
Random sampling error is the difference between the characteristics of the sample and those of the population purely due to chance. This concept is significant when dealing with survey data, like that from a Gallup Poll. No sample perfectly represents a population; as samples are just subsets, they will naturally differ. Every time a sample is taken, there is some level of random variation. This "error" doesn’t imply a mistake but rather the natural variability that occurs in sampling. When Gallup reports a 4% margin of error, they implicitly account for random sampling error. It shows the extent to which the stats might naturally differ if the whole population were surveyed. Hence, acknowledging random sampling error is essential in interpreting the reliability and accuracy of survey results, and why it’s paired with confidence levels in statistical reports.

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Most popular questions from this chapter

Harris Announces a Margin of Error. Exercise \(22.25\) describes a Harris Poll survey of smokers in which 848 of a sample of 1010 smokers agreed that smoking would probably shorten their lives. Harris announces a margin of error of \(\pm 3\) percentage points for all samples of about this size. Opinion polls announce the margin of error for \(95 \%\) confidence. a. What is the actual margin of error (in percent) for the large-sample confidence interval from this sample? b. The margin of error is largest when \(\hat{p}=0.5\). What would the margin of error (in percent) be if the sample had resulted in \(\widehat{p}=0.5\) ? c. Why do you think that Harris announces a \(\pm 3 \%\) margin of error for all samples of about this size?

Do You Listen to Podcasts? In January and February 2019, Edison Research conducted a national telephone survey of 1500 Americans aged 12 and older, using random digit dialing techniques to both cell phones and landlines. The survey included questions about the use of mobile devices, Internet audio, podcasting, social media, smart speakers, and more. Of the 1500 people surveyed, 480 said they had listened to a podcast in the past month. 12 a. What is the margin of error of the large-sample \(95 \%\) confidence interval for the proportion of Americans aged 12 and older who had listened to a podcast in the past month? b. How large a sample is needed to get the common \(\pm 3\) percentage point margin of error? Use the January/February survey of 1500 as a pilot study to get \(p^{*}\)

Based on the sample, the large-sample \(90 \%\) confidence interval for the proportion of all American adults who actively try to avoid drinking regular soda or pop is a. \(0.61 \pm 0.015\). b. \(0.61 \pm 0.025\). c. \(0.61 \pm 0.029\).

The 68-95-99.7 Rule and \(\widehat{\boldsymbol{p}}\). Greenville County, South Carolina, has 396,183 adult residents, of which 80,987 are 65 years or older. A survey wants to contact \(n=689\) residents. \({ }^{5}\) a. Find \(p\), the proportion of Greenville County adult residents who are 65 years or older. b. If repeated simple random samples of 689 residents are taken, what would be the range of the sample proportion of adults over 65 in the sample according to the 95 part of the 68-95-99.7 rule? c. Suppose the actual survey contacted 689 adults using random digit dialing of residential numbers using a database of exchanges, with no cell phone numbers contacted. The 689 respondents represent a response rate of approximately \(30 \%\). In the sample obtained, 253 of the 689 adults contacted were over 65 . Do you have any concerns treating this as a simple random sample from the population of adult residents of Greenville County? Explain briefly.

College-Educated Parents. The National Assessment of Educational Progress (NAEP) includes a "longterm trend" study that tracks reading and mathematics skills over time and obtains demographic information. In the 2012 study (the most recent available as of 2020), a random sample of 9000 17-year-old students was selected. \(\underline{27}\) The NAEP sample used a multistage design, but the overall effect is quite similar to an SRS of 17-year-olds who are still in school. a. In the sample, \(51 \%\) of students had at least one parent who was a college graduate. Estimate, with \(99 \%\) confidence, the proportion of all 17-year-old students in 2012 who had at least one parent graduate from college. b. The sample does not include 17-year-olds who dropped out of school, so your estimate is valid only for students. Do you think the proportion of all 17-year- olds with at least one parent who was a college graduate would be higher or lower than \(51 \%\) ? Explain.

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