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Based on the sample, the large-sample \(90 \%\) confidence interval for the proportion of all American adults who actively try to avoid drinking regular soda or pop is a. \(0.61 \pm 0.015\). b. \(0.61 \pm 0.025\). c. \(0.61 \pm 0.029\).

Short Answer

Expert verified
Option b: 0.61 ± 0.025 offers a reasonable confidence interval balance.

Step by step solution

01

Identify the Meaning of Confidence Interval

A confidence interval gives a range of values for a parameter (here, the proportion) estimated from the data, along with a specified level of confidence (here, 90%). The question provides three options representing 90% confidence intervals, each with a given center (0.61) and margin of error.
02

Understand Margin of Error in Confidence Interval

The confidence interval is structured as the central proportion plus or minus the margin of error. This means the confidence interval is \([0.61 - ext{{margin of error}}, 0.61 + ext{{margin of error}}]\). Compare each option's margin of error to calculate the confidence interval limits.
03

Calculate Confidence Interval Boundaries

Calculate the boundaries for each option:- a: \(0.61 ightarrow [0.61 - 0.015, 0.61 + 0.015] = [0.595, 0.625]\)- b: \(0.61 ightarrow [0.61 - 0.025, 0.61 + 0.025] = [0.585, 0.635]\)- c: \(0.61 ightarrow [0.61 - 0.029, 0.61 + 0.029] = [0.581, 0.639]\)
04

Determine Effects of Margin of Error

The margin of error impacts the width of the confidence interval. A larger margin of error results in a wider interval. Determine which margin of error best matches a plausible confidence interval for large samples.
05

Evaluate Choice Based on Confidence Level

For a 90% confidence interval, the most realistic range results from a balanced margin of error for such significant proportions. Consider that larger errors typically equate to larger confidence in covering the true parameter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a critical aspect when constructing a confidence interval. It accounts for variations expected within a sample to infer about a larger population. Imagine you are trying to estimate the average height of people in a city. You measure a sample and find a mean. However, you know this sample mean might differ slightly from the true population mean.
This potential difference is what the margin of error represents. It tells us how much we can expect the true mean to vary from our sample mean.
  • A smaller margin of error suggests that the sample estimate is very close to the true population parameter.
  • A larger margin ensures more confidence in encompassing the true value, but sometimes at the expense of precision.
To find the margin of error in a confidence interval, you subtract and add it to the sample proportion or mean. This creates a range where you expect the true parameter to lie with a certain level of confidence, let's say 90% as in our example. For instance, if your center is 0.61 and the margin of error is 0.015, your confidence interval is [0.595, 0.625]. Larger margins create wider intervals, giving more room for the true value but less precision.
Proportion
Proportion refers to the part of the whole, expressed in a ratio or fraction, and is often seen in everyday statistics. It is essentially a way of describing probability in scenarios with two outcomes, such as success or failure. In this exercise, proportion represents the percentage of American adults who actively avoid drinking soda. You might encounter it as a decimal, such as 0.61, which means 61 out of 100 adults avoid regular soda in this context.
Understanding proportions is vital because it provides a snapshot of behavior or characteristics of a population segment. When dealing with confidence intervals and proportions, it's important to remember:
  • The sample proportion is the estimated probability of the outcome in the sample you study.
  • As sample size increases, the sample proportion tends to better estimate the actual proportion, but it is still prone to some degree of error (margin of error).
Confidence intervals use the sample proportion to estimate the range of possible true proportions in the population, adding and subtracting the margin of error from the sample proportion.
Large Sample
When conducting statistical analysis, a large sample size often leads to more reliable results, and for good reason. Large samples help ensure your data more accurately represents the population. With a large enough sample, the Central Limit Theorem guarantees that the sampling distribution of the mean will approach a normal distribution regardless of the shape of the population distribution. This is beneficial for creating more accurate confidence intervals.
Large samples also influence the margin of error. They allow for smaller margins of error, leading to tighter confidence intervals. This implies that the larger your sample, the more precise your estimates will be, given other factors like variance remain constant. Moreover,
  • A large sample reduces the impact of outliers or anomalies, enhancing the robustness of an analysis.
  • Larger samples increase the reliability of inferential statistics like confidence intervals and margins of error.
In our exercise, using a large sample justifies assuming a normal distribution of the sample proportion, thereby allowing the use of normal approximation methods for constructing the confidence intervals.

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Most popular questions from this chapter

Gun Violence and Video Games. People disagree about the impact of video games on gun violence. A survey in 2017 of a random sample of 1501 U.S. adults asked "Does the amount of gun violence in video games contribute a great deal or a fair amount to gun violence?" Of the 1501 sampled, 180 said "Not at all."20 a. Give the \(95 \%\) large-sample confidence interval for the proportion \(p\) of all U.S. adults who said that gun violence in video games does not contribute at all to gun violence. Be sure to verify that the sample size is large enough to use the large-sample confidence interval. b. Give the plus four \(95 \%\) confidence interval for \(p\). If you express the two intervals in percentages, rounded to the nearest 10 th of a percent, how do they differ? (The plus four interval always pulls the results toward \(50 \%\).)

No Test.Explain whether we can use the \(z\) test for a proportion in these situations. a. You toss a coin 10 times in order to test the hypothesis \(H_{0}: p=0.5\) that the coin is balanced. b. A local congressperson contacts an SRS of 500 of the registered voters in his district to see if there is evidence that more than half support the bill he is sponsoring. c. The CEO of a large corporation says, "only \(2 \%\) of our employees are dissatisfied with our new health insurance plan." You contact an SRS of 150 of the company's 10,000 employees to test the hypothesis \(H_{0}: p=0.02\).

Harris Announces a Margin of Error. Exercise \(22.25\) describes a Harris Poll survey of smokers in which 848 of a sample of 1010 smokers agreed that smoking would probably shorten their lives. Harris announces a margin of error of \(\pm 3\) percentage points for all samples of about this size. Opinion polls announce the margin of error for \(95 \%\) confidence. a. What is the actual margin of error (in percent) for the large-sample confidence interval from this sample? b. The margin of error is largest when \(\hat{p}=0.5\). What would the margin of error (in percent) be if the sample had resulted in \(\widehat{p}=0.5\) ? c. Why do you think that Harris announces a \(\pm 3 \%\) margin of error for all samples of about this size?

Running Red Lights. A random digit dialing telephone survey of 880 drivers asked, "Recalling the last 10 traffic lights you drove through, how many of them were red when you entered the intersections?" Of the 880 respondents, 171 admitted that at least one light had been red. 25 a. Give a \(95 \%\) confidence interval for the proportion of all drivers who ran one or more of the last 10 red lights they met. b. Nonresponse is a practical problem for this survey: only \(21.6 \%\) of calls that reached a live person were completed. Another practical problem is that people may not give truthful answers. What is the likely direction of the bias? Do you think more or fewer than 171 of the 880 respondents really ran a red light? Why?

College-Educated Parents. The National Assessment of Educational Progress (NAEP) includes a "longterm trend" study that tracks reading and mathematics skills over time and obtains demographic information. In the 2012 study (the most recent available as of 2020), a random sample of 9000 17-year-old students was selected. \(\underline{27}\) The NAEP sample used a multistage design, but the overall effect is quite similar to an SRS of 17-year-olds who are still in school. a. In the sample, \(51 \%\) of students had at least one parent who was a college graduate. Estimate, with \(99 \%\) confidence, the proportion of all 17-year-old students in 2012 who had at least one parent graduate from college. b. The sample does not include 17-year-olds who dropped out of school, so your estimate is valid only for students. Do you think the proportion of all 17-year- olds with at least one parent who was a college graduate would be higher or lower than \(51 \%\) ? Explain.

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