/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Harris Announces a Margin of Err... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Harris Announces a Margin of Error. Exercise \(22.25\) describes a Harris Poll survey of smokers in which 848 of a sample of 1010 smokers agreed that smoking would probably shorten their lives. Harris announces a margin of error of \(\pm 3\) percentage points for all samples of about this size. Opinion polls announce the margin of error for \(95 \%\) confidence. a. What is the actual margin of error (in percent) for the large-sample confidence interval from this sample? b. The margin of error is largest when \(\hat{p}=0.5\). What would the margin of error (in percent) be if the sample had resulted in \(\widehat{p}=0.5\) ? c. Why do you think that Harris announces a \(\pm 3 \%\) margin of error for all samples of about this size?

Short Answer

Expert verified
a. The actual margin of error is 2.31%. b. The margin is 3.08% for \(\hat{p}=0.5\). c. Harris uses \(\pm 3\%\) reflecting a worst-case margin.

Step by step solution

01

Calculate Sample Proportion

The first step is to calculate the sample proportion \( \hat{p} \) of smokers who agreed that smoking would probably shorten their lives. This is done using the formula \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of smokers who agreed (848) and \( n \) is the total number of smokers surveyed (1010). Thus, \( \hat{p} = \frac{848}{1010} \approx 0.8396 \).
02

Calculate Standard Error of Proportion

The standard error of the proportion \( SE_{\hat{p}} \) is calculated using the formula: \[ SE_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}. \] Substituting the values, \( SE_{\hat{p}} = \sqrt{\frac{0.8396 \times (1 - 0.8396)}{1010}} \approx 0.0118 \).
03

Calculate Margin of Error for 95% Confidence

The margin of error for a 95% confidence interval is calculated using the formula \( ME = z^{*} \times SE_{\hat{p}} \), where \( z^{*} \approx 1.96 \) for 95% confidence. Thus, \( ME = 1.96 \times 0.0118 \approx 0.0231 \), or 2.31%.
04

Calculate Margin of Error for \(\hat{p}=0.5\)

The margin of error is maximum when \( \hat{p} = 0.5 \). Using this value, calculate the standard error: \[ SE = \sqrt{\frac{0.5(1-0.5)}{1010}} \approx 0.0157. \] Then calculate the margin of error: \( ME = 1.96 \times 0.0157 \approx 0.0308 \), or 3.08%.
05

Explanation for Harris' Constant Margin of Error

Harris likely uses a standard \( \pm 3\% \) margin of error because it reflects the worst-case scenario (when \( \hat{p} = 0.5 \)), thereby providing a consistent and straightforward estimate of the margin of error to report, independent of the actual sample proportion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a crucial concept in statistics, particularly in polling. It helps describe the accuracy of an estimate. When a survey or poll provides a margin of error, it tells you how much you can expect the results to differ if the entire population were surveyed instead of just a sample. For example, if a survey reveals that 60% of respondents favor a particular option with a margin of error of ±3%, the real percentage in the population could be anywhere between 57% and 63%.
In the context of polls, the margin of error usually indicates a level of confidence, commonly 95%. This means 95% of similarly conducted surveys would produce results within the stated margin of error. It's crucial to note that the margin of error depends on several factors, including sample size and variability within the data. In our exercise, Harris uses a margin of error of ±3% because it represents a common choice to reflect maximum uncertainty at a sample size typical to the survey.
There's an interesting point here about why Harris would announce a 3% error margin. By using the maximum possible error margin where the sample proportion, \(\hat{p}\), is assumed to be 0.5, this ensures they cover the worst-case scenario. It simplifies reporting across a variety of samples, providing a straightforward way for readers to understand the extent of potential error without recalculating for every different result.
Confidence Interval
In statistics, a confidence interval is a range of values that is likely to contain a population parameter with a certain level of confidence. Often, a 95% confidence interval is used, which suggests that if the data collection were repeated multiple times, 95 out of 100 of these intervals would contain the true population parameter.
The confidence interval is calculated based on the sample data at hand. For instance, in our exercise, a 95% confidence interval for the proportion of smokers who believe smoking will shorten their lives was computed. The calculation uses the sample proportion \(\hat{p}\) and adds or subtracts the margin of error from this proportion to determine the interval.
To reiterate, the confidence interval provides a balance between accuracy and certainty in statistical estimates. This becomes particularly useful in fields such as medicine or social sciences, where determining population-level effects and attitudes is necessary. By providing a range instead of a single estimate, a confidence interval acknowledges the inherent uncertainty in using samples to make inferences about larger populations.
Sample Proportion
The sample proportion is a foundational concept in statistics and is used to estimate the proportion of a population that has a certain characteristic, based on a subset of that population. It is represented by \(\hat{p}\). The sample proportion provides a point estimate around which other statistical measures like the margin of error and confidence intervals are calculated.
To determine the sample proportion, you divide the number of favorable outcomes observed in the sample by the total number of observations. In the given exercise, the sample proportion \(\hat{p}\) is calculated as \(\frac{848}{1010}\), which equals approximately 0.8396. This indicates that about 83.96% of the sample surveyed agreed that smoking would likely shorten their lifespan.
Understanding the sample proportion is critical as it sets the foundation for further analysis such as calculating the standard error and constructing confidence intervals. The closer \(\hat{p}\) is to an extreme (0 or 1), the more precise it usually is, but estimating near the middle (around 0.5) often provides higher variability, necessitating a larger sample size or accepting a larger margin of error.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Gallup Poll in November 2019 found that \(55 \%\) of the people in the sample said they wanted to lose weight. The poll's margin of error for \(95 \%\) confidence was \(4 \%\). This means that a. the poll used a method that gets an answer within \(4 \%\) of the truth about the population \(95 \%\) of the time. b. we can be sure that the percentage of all adults who want to lose weight is between \(50 \%\) and \(58 \%\). c. if Gallup takes another poll using the same method, the results of the second poll will lie between \(51 \%\) and \(59 \%\).

No Confidence Interval. The 2017 Youth Risk Behavioral Survey, in a random sample of 497 high school seniors in Connecticut, found that \(0.8 \%\) (that's \(0.008\) as a decimal fraction) smoked cigarettes daily. \({ }^{2}\) Explain why we can't use the large-sample confidence interval to estimate the proportion \(p\) in the population of all Connecticut high school seniors in 2017 who smoked cigarettes daily.

No Test.Explain whether we can use the \(z\) test for a proportion in these situations. a. You toss a coin 10 times in order to test the hypothesis \(H_{0}: p=0.5\) that the coin is balanced. b. A local congressperson contacts an SRS of 500 of the registered voters in his district to see if there is evidence that more than half support the bill he is sponsoring. c. The CEO of a large corporation says, "only \(2 \%\) of our employees are dissatisfied with our new health insurance plan." You contact an SRS of 150 of the company's 10,000 employees to test the hypothesis \(H_{0}: p=0.02\).

How many American adults must be interviewed to estimate the proportion of all American adults who actively try to avoid drinking regular soda or pop within \(\pm 0.01\) with \(99 \%\) confidence using the large-sample confidence interval? Use \(0.5\) as the conservative guess for \(p\). a. \(n=6765\) b. \(n=9604\) c. \(n=16590\)

Downloading Music. A husband and wife, Stan and Lucretia, share a digital audio player that has a feature that randomly selects which song to play. A total of 2444 songs have been loaded into the player, some by Stan and the rest by Lucretia. They are interested in determining whether they have loaded different proportions of songs into the player. Suppose that when the player was in the randomselection mode, 26 of the first 40 songs selected were songs loaded by Lucretia. Let \(p\) denote the proportion of songs that were loaded by Lucretia. a. State the null and alternative hypotheses to be tested. How strong is the evidence that Stan and Lucretia have loaded different proportions of songs into the player? Make sure to check the conditions for the use of this test. b. Are the conditions for the use of the large-sample confidence interval met? If so, estimate with \(95 \%\) confidence the proportion of songs that were loaded by Lucretia.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.