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This Wine Stinks. How sensitive are the untrained noses of students? Exercise 16.27 (page 381) gives the lowest levels of dimethyl sulfide (DMS) that 10 students could detect. You want to estimate the mean DMS odor threshold among all students, and you would be satisfied to estimate the mean to within \(\pm 0.1\) with \(99 \%\) confidence. The standard deviation of the odor threshold for untrained noses is known to be \(\sigma=7\) micrograms per liter of wine. How large an SRS of untrained students do you need?

Short Answer

Expert verified
A sample size of at least 18033 students is needed.

Step by step solution

01

Understand the Problem

We want to estimate the mean DMS odor threshold and determine the sample size required for a specified margin of error and confidence level. The margin of error is \( \pm 0.1 \), the confidence level is \(99\%\), and the standard deviation is \(\sigma = 7\) micrograms per liter.
02

Identify the Formula for Sample Size Calculation

To calculate the sample size needed for a given margin of error in a mean estimate, we use the formula for sample size: \[ n = \left( \frac{Z \cdot \sigma}{E} \right)^2 \]where \(Z\) is the z-score corresponding to the desired confidence level, \(\sigma\) is the standard deviation, and \(E\) is the margin of error.
03

Determine the Z-Score for 99% Confidence

Find the z-score that corresponds to a \(99\%\) confidence level. For \(99\%\) confidence, the critical value is approximately \(Z = 2.576\).
04

Plug Values into the Sample Size Formula

Substitute \(Z = 2.576\), \(\sigma = 7\), and \(E = 0.1\) into the formula:\[ n = \left( \frac{2.576 \times 7}{0.1} \right)^2 \]
05

Calculate the Sample Size

Perform the arithmetic:\[ n = \left( \frac{18.032}{0.1} \right)^2 = 18032.896 \\approx 18033 \]Since the sample size must be a whole number, round up to the nearest whole number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
Understanding confidence intervals is crucial when estimating population parameters, like the mean DMS odor threshold in our wine exercise. A confidence interval provides a range of values, likely to contain the true population parameter, based on sample data. The level of confidence, such as 99% in this problem, indicates how certain we can be that the interval includes the true mean.

The wider the confidence interval, the more uncertainty about the exact value of the mean. A 99% confidence interval will be wider than a 95% one, offering more assurance that the interval captures the true mean. In practical terms, this means we are 99% confident the actual mean threshold for detecting DMS among students falls within our calculated range.

In essence, confidence intervals are powerful tools in statistics that help convey uncertainty about estimates based on sample data.
Margin of Error
The margin of error defines how close we believe our sample estimate is to the true population parameter. In the wine example, the margin of error is set at \( \pm 0.1 \) micrograms per liter, meaning we aim to estimate the mean DMS odor threshold within 0.1 micrograms of its true value.

A smaller margin of error requires a larger sample size, as more data is needed to achieve precision. Conversely, allowing a larger margin of error means you can rely on smaller samples. Balancing these factors is key: policymakers aim for the smallest margin of error possible to ensure reliable estimates, while also being mindful of resources and constraints.

The margin of error directly impacts the width of the confidence interval: a smaller margin means a narrower interval, providing a more precise estimate of the population mean.
Z-Score
The z-score is a standard measure in statistics, representing the number of standard deviations a data point is from the mean. In the context of sample size determination, it's used to reflect the level of confidence in your estimate.

For our exercise, a 99% confidence level corresponds to a z-score of approximately 2.576. This z-score is derived from standard normal distribution tables and indicates that 99% of sample means will fall within 2.576 standard deviations of the true mean.

The z-score is essential in calculating the sample size, as it adjusts for the desired confidence level. The higher the desired confidence level, the larger the z-score and, consequently, the sample size needed to achieve that level of assurance. This reflects how more information is required to be more confident in our estimates.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. In our example, the standard deviation (\( \sigma = 7 \) micrograms per liter) describes the variability in the DMS odor threshold among students.

It's a crucial component in determining sample size because it quantifies the extent to which individual measurements differ from the mean. The larger the standard deviation, the larger the sample size needed to achieve a certain margin of error and confidence level.

Understanding the role of standard deviation helps in appreciating the variability inherent in any dataset. In simpler terms, knowing how much variation to expect guides us in planning how much data we need for reliable insights.

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Most popular questions from this chapter

Running Red Lights. A survey of licensed drivers inquired about running red lights. One question asked, "Of every 10 motorists who run a red light, about how many do you think will be caught?" The mean result for 880 respondents was \(x=1.92\), and the standard deviation was \(s=1.83 . \stackrel{2}{*}\) For this large sample, \(s\) will be close to the population standard deviation \(\sigma\), so suppose we know that \(\sigma=1.83 .\) a. Give a \(95 \%\) confidence interval for the mean opinion in the population of all licensed drivers. b. The distribution of responses is skewed to the right rather than Normal. This will not strongly affect the \(z\) confidence interval for this sample. Why not? c. The 880 respondents are an SRS from completed calls among 45,956 calls to randomly chosen residential telephone numbers listed in telephone directories. Only 5029 of the calls were completed. This information gives two reasons to suspect that the sample may not represent all licensed drivers. What are these reasons?

What Is Power? The Trial Urban District Assessment (TUDA) measures educational progress within participating large urban districts. TUDA gives a reading test scored from 0 to 500 . A score of 208 is a "basic" reading level for fourthgraders. I Suppose scores on the TUDA reading test for fourthgraders in your district follow a Normal distribution with standard deviation \(\sigma=40\). In 2019 the mean score for fourthgraders in your district was 219 . You plan to give the reading test to a random sample of 25 fourth-graders in your district this year to test whether the mean score \(\mu\) for all fourthgraders in your district is still above the basic level. You will therefore test $$ \begin{aligned} &H_{0}: \mu=208 \\ &H_{a}: \mu>208 \end{aligned} $$ If the true mean score is again 219, on average, students are performing above the basic level. You learn that the power of your test at the \(5 \%\) significance level against the alternative \(\mu=219\) is \(0.394 .\) a. Explain in simple language what "power \(=0.394\) " means. b. Explain why the test you plan will not adequately protect you against incorrectly deciding that average reading scores in your district are not above basic level.

Sample Size and Margin of Error. Example 16.1 (page 368) described NHANES data on the body mass index (BMI) of 936 young men. The mean BMI in the sample was \(x=27.2 \mathrm{~kg} / \mathrm{m}^{2}\). We treated these data as an SRS from a Normally distributed population with standard deviation \(\sigma=11.6\) a. Suppose that we had an SRS of just 100 young men. What would be the margin of error for \(95 \%\) confidence? b. Find the margins of error for \(95 \%\) confidence based on SRSs of 400 young men and 1600 young men. c. Compare the three margins of error. How does increasing the sample size change the margin of error of a confidence interval when the confidence level and population standard deviation remain the same?

The First Child Has Higher IQ. Does the birth order of a family's children influence their IQ scores? A careful study of 241,310 Norwegian 18- and 19 -year-olds found that firstborn children scored \(2.3\) points higher on the average than second children in the same family. This difference was highly significant \((P<0.001)\). A commentator said, "One puzzle highlighted by these latest findings is why certain ot her within-family studies have failed to show equally consistent results. Some of these previous null findings, which have all been obtained in much smaller samples, may be explained by inadequate stat istical power." \(\underline{12}\) a. Explain in simple language why tests having low power often fail to give evidence against a null hypothesis even when the hypothesis is really false. b. Do you think a difference of \(2.3\) points in IQ scores is an important difference?

What Is Significance Good For? Which of the following questions does a test of significance answer? Briefly explain your replies. a. Is the observed effect large? b. Is the observed effect due to chance? c. Is the observed effect important?

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