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A 2015 Gallup Poll asked a national random sample of 398 adult women to state their current weight. The mean weight in the sample was \(\mathrm{x}^{-} \bar{x}=155\). We will treat these data as an SRS from a Normally distributed population with standard deviation \(\sigma=35\). (a) Give a \(95 \%\) confidence interval for the mean weight of adult women based on these data. (b) Do you trust the interval you computed in part (a) as a 95\% confidence interval for the mean weight of all U.S. adult women? Why or why not?

Short Answer

Expert verified
(a) The 95% confidence interval is approximately (151.56, 158.44). (b) The interval might not be fully reliable for all U.S. adult women due to potential sampling bias.

Step by step solution

01

Identify the Known Values

We are given the sample mean \( \bar{x} = 155 \), the population standard deviation \( \sigma = 35 \), and the sample size \( n = 398 \). We need to use these to find a 95% confidence interval.
02

Determine the Z-score for 95% Confidence Level

For a 95% confidence interval, the critical Z-value is approximately 1.96, which corresponds to 0.025 in each tail of the standard normal distribution (Cumulative distribution function value = 0.975).
03

Calculate the Standard Error (SE)

The standard error is given by the formula \( SE = \frac{\sigma}{\sqrt{n}} \). Substituting the known values: \( SE = \frac{35}{\sqrt{398}} \approx 1.755 \).
04

Calculate the Margin of Error (MOE)

The margin of error can be found by multiplying the Z-score by the SE: \( MOE = 1.96 \times 1.755 \approx 3.4438 \).
05

Compute the Confidence Interval

The confidence interval is given by \( \bar{x} \pm MOE \). Substituting the known values: \( 155 \pm 3.4438 \), so the confidence interval is approximately \( (151.5562, 158.4438) \).
06

(Part b): Evaluate the Confidence Interval's Trustworthiness

The interval likely does not fully represent the mean weight of all U.S. adult women because the sample only includes adult women, and variations in weight distribution could differ due to factors not covered in a single sample (e.g., location, health conditions). Thus, this might not be fully representative of the broader population.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a simple but powerful concept in statistics. It represents the average value of a set of numerical data collected from a sample. In our exercise, the Gallup Poll surveyed 398 adult women, and their average weight, the sample mean, was calculated to be 155 pounds.
This value is used as an estimate of the true mean of the population, meaning the average weight of all adult women we want to understand. Good sampling is crucial because it allows this estimate to be as close to the true population mean as possible. The reason behind using the sample mean is that in many cases, getting data from the entire population is not feasible due to time or resource constraints.
Standard Error
The standard error (SE) is a measure that helps us understand the precision of the sample mean as an estimate of the population mean. It tells us how much the sample mean is expected to vary from one sample to another. Smaller SE indicates more reliable estimates.
In our exercise, the formula for the SE is \[ SE = \frac{\sigma}{\sqrt{n}} \]where \(\sigma\) is the population standard deviation, and \(n\) is the sample size. Using the provided values, \[ SE = \frac{35}{\sqrt{398}} \approx 1.755 \].
This SE shows that even though we only sampled a group of women, the estimate of the average weight is within approximately 1.755 pounds of the actual average weight of the entire population.
Z-score
A Z-score is a statistical measure that describes a value's relation to the mean of a group of values. It indicates how many standard deviations an element is from the mean. In the context of confidence intervals, the Z-score determines the "spread" of data around the sample mean.
To construct a 95% confidence interval for the mean, a Z-score of 1.96 is used. This value comes from the standard normal distribution and corresponds to 0.025 probability in each tail (2.5% on either extreme), ensuring that we cover 95% of the possible sample means. The Z-score helps in establishing how wide the confidence interval should be, which directly impacts how confident we are that the interval contains the true population mean.
Margin of Error
The margin of error (MOE) is a crucial component in estimating how accurate the sample mean is likely to be. It defines the range in which we expect the true population mean to fall, given our sample data.
The MOE is calculated by multiplying the Z-score by the standard error: \[ MOE = Z \times SE \]. Using the values from the exercise, \[ MOE = 1.96 \times 1.755 \approx 3.4438 \].
This means the true mean weight of all adult women would most likely fall within the interval created by adding and subtracting this margin from the sample mean. In our example, the confidence interval is \[ 155 \pm 3.4438 \], resulting in approximately \[ (151.5562, 158.4438) \]. This interval suggests that if we were to take many samples, about 95% of those intervals would capture the true mean, reflecting the inherent variability in sample estimates.

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Most popular questions from this chapter

The most important condition for sound conclusions from statistical inference is usually that (a) the data can be thought of as a random sample from the population of interest. (b) the population distribution is exactly Normal. (c) the data contain no outliers.

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