/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Credit card charges A credit car... [FREE SOLUTION] | 91Ó°ÊÓ

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Credit card charges A credit card company takes a random sample of 100 cardholders to see how much they charged on their card last month. Here's a histogram. A computer program found that the resulting \(95 \%\) confidence interval for the mean amount spent in March 2005 is \((-\$ 28366.84, \$ 90691.49) .\) Explain why the analysts didn't find the confidence interval useful, and explain what went wrong.

Short Answer

Expert verified
The confidence interval is too wide to be useful due to high variability or errors in sampling or assumptions.

Step by step solution

01

Understanding the Confidence Interval

A confidence interval is a range of values that's used to estimate the true mean of a population. In this case, the given confidence interval is \((-\\(28366.84, \\)90691.49)\), which means that we are \(95\%\) confident that the true mean amount charged by cardholders lies between these two values.
02

Analyzing the Width of the Confidence Interval

The confidence interval is very wide, spanning a range of \(\$119,058.33\). This broad range suggests there is a lot of uncertainty or variability in the sample data regarding the mean amount spent. Such a wide interval is not useful because it does not provide a precise estimate of the population mean.
03

Examining the Possible Causes of the Wide Interval

Several factors can cause such a wide confidence interval, like high variability in the data or potential outliers. Another reason could be a high standard deviation in the sample, which directly affects the width of the confidence interval. Misestimation of the population variance can also lead to inaccuracies.
04

Evaluating the Sample and Methodology

To have a more useful confidence interval, analysts need to ensure that the sample accurately represents the population. They may need to increase the sample size or remove outliers to reduce variability. It is also important to verify the assumptions made for the confidence interval calculations, such as normality and population variance.
05

Conclusion of the Analysis

The confidence interval provided is not useful due to its excessive width, indicating a lack of precision in the estimate of the true mean spent. This issue likely results from high variability or methodological errors in sampling or statistical assumptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean represents the average of a certain characteristic across an entire population. In the context of the credit card charges exercise, it indicates the average amount all cardholders spend in a month. To estimate this mean, analysts often use sample data.
Taking a random sample of 100 cardholders provides a statistical basis to infer or estimate this mean. However, the actual population mean cannot be known exactly without data from every cardholder.
Thus, using a confidence interval allows analysts to express a range in which the true mean likely falls.
  • The given confidence interval (\(-\\( 28366.84, \\) 90691.49\)) is meant to reflect this uncertainty around the true population mean.
  • This interval is very wide, indicating a lack of precision in estimating the mean.
The overly broad range suggests there might be issues in how the data was sampled or analyzed. To improve accuracy, analysts need better sampling techniques or perhaps a larger sample size.
Sample Variability
Variability within a sample is a measure of how spread out the data points are. In simpler terms, it shows how much the spending amounts differ among the sampled cardholders.
If you have high variability, it means individuals in the sample show a large difference in their charge amounts.
This variability can significantly affect certain statistical calculations, like the confidence interval.
  • High variability in the sample increases the range of the confidence interval.
  • It signals uncertainty regarding the estimate of the population mean.
  • Reducing sample variability can help make the confidence interval more precise.
One way to reduce variability is to ensure your sample accurately represents the broader population.
Using techniques such as stratified random sampling or increasing the sample size might assist in achieving this.
Standard Deviation
The standard deviation is a crucial measure that demonstrates the amount of variability or dispersion in a dataset. It tells us, on average, how far each cardholder's spending amount is from the mean amount.
A high standard deviation indicates that the spending amounts are spread out over a wider range.
This spread can make estimating the true population mean more challenging.
  • Larger standard deviations broaden the confidence interval.
  • Steps like analyzing data for outliers can help in reassessing the deviation.
  • The formula to compute standard deviation involves determining the square root of the variance.
During the confidence interval calculation, the standard deviation is used to estimate the margin of error. To enhance precision, it's essential to calculate and understand this vital metric carefully.
Statistical Assumptions
Statistical assumptions underpin confidence interval calculations and greatly influence their accuracy. In our credit card charges example, assumptions include that data are normally distributed and the sample represents the population accurately.
Ignoring or misjudging these assumptions can lead to poor quality confidence intervals.
  • The data should ideally follow a normal distribution.
  • A random sample selection helps ensure a representative dataset.
  • Homogeneity of variance is another assumption that affects the confidence interval's reliability.
Violation of these assumptions can lead to a wider confidence interval, as seen in the exercise result.
Carefully checking and validating these assumptions before analysis helps achieve more accurate results, providing better insights.

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Most popular questions from this chapter

LSAT The LSAT (a test taken for law school admission) has a mean score of 151 with a standard deviation of 9 and a unimodal, symmetric distribution of scores. A test preparation organization teaches small classes of 9 students at a time. A larger organization teaches classes of 25 students at a time. Both organizations publish the mean scores of all their classes. a) What would you expect the distribution of mean class scores to be for each organization? b) If cither organization has a graduating class with a mean score of \(160,\) they'll take out a full-page ad in the local school paper to advertise. Which organization is more likely to have that success? Explain. c) Both organizations advertise that if any class has an average score below \(145,\) they'll pay for everyone to retake the LSAT. Which organization is at greater risk to have to pay?

Cattle Livestock are given a special feed supplement to see if it will promote weight gain. Researchers report that the 77 cows studicd gaincd an average of 56 pounds, and that a \(95 \%\) confidence interval for the mean weight gain this supplement produces has a margin of error of ±11 pounds. Some students wrote the following conclusions. Did anyone interpret the interval correctly? Explain any misinterpretations. a) \(95 \%\) of the cows studied gained between 45 and 67 pounds. b) We're \(95 \%\) sure that a cow fed this supplement will gain between 45 and 67 pounds. c) We're \(95 \%\) sure that the average weight gain among the cows in this study was between 45 and 67 pounds. d) The average weight gain of cows fed this supplement will be between 45 and 67 pounds \(95 \%\) of the time. e) If this supplement is tested on another sample of cows, there is a \(95 \%\) chance that their average weight gain will be between 45 and 67 pounds.

A good book An English professor is attempting to estimate the mean number of novels that the student body reads during their time in college. He is conducting an exit survey with seniors. He hopes to have a margin of error of 3 books with \(95 \%\) confidence. From reading previous studies, he expects a large standard deviation and is going assume it is \(10 .\) How many students should he survey?

For Example, 2 nd look This chapter's For Examples looked at mirex contamination in farmed salmon. We first found a \(95 \%\) confidence interval for the mean concentration to be 0.0834 to 0.0992 parts per million. Later we rejected the null hypothesis that the mean did not exceed the EPA's recommended safe level of 0.08 ppm based on a P-value of \(0.0027 .\) Explain how these two results are consistent. Your explanation should discuss the confidence level, the P-value, and the decision.

Home sales The housing market has recovered slowly from the economic crisis of \(2008 .\) Recently, in one large community, realtors randomly sampled 36 bids from potential buyers to estimate the average loss in home value. The sample showed the average loss was \(\$ 9560\) with a standard deviation of \(\$ 1500\) a) What assumptions and conditions must be checked before finding a confidence interval? How would you check them? b) Find a \(95 \%\) confidence interval for the mean loss in value per home. c) Interpret this interval and explain what \(95 \%\) confidence means in this context.

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