/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Home sales The housing market ha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Home sales The housing market has recovered slowly from the economic crisis of \(2008 .\) Recently, in one large community, realtors randomly sampled 36 bids from potential buyers to estimate the average loss in home value. The sample showed the average loss was \(\$ 9560\) with a standard deviation of \(\$ 1500\) a) What assumptions and conditions must be checked before finding a confidence interval? How would you check them? b) Find a \(95 \%\) confidence interval for the mean loss in value per home. c) Interpret this interval and explain what \(95 \%\) confidence means in this context.

Short Answer

Expert verified
The 95% confidence interval for the mean loss in home value is between $9070 and $10050.

Step by step solution

01

Check Assumptions and Conditions

To calculate a confidence interval, we must check the assumptions and conditions. - **Random Sampling:** The problem states that the bids were randomly sampled, so this condition is satisfied. - **Independence:** The sampled bids should be independent from each other. Assuming this condition is met as well since the bids likely represent different potential buyers. - **Sample Size:** The sample size is 36, which is greater than 30. This allows us to apply the Central Limit Theorem, ensuring the sampling distribution of the sample mean is approximately normally distributed. - **Normal Distribution:** Since the sample size is large enough for the Central Limit Theorem, the condition of normal distribution of the sample mean is met.
02

Calculate the Standard Error

The standard error (SE) of the sample mean is calculated using the sample's standard deviation and size.The formula for standard error is:\[ SE = \frac{\text{Sample Standard Deviation}}{\sqrt{\text{Sample Size}}} \]Substitute the given values:\[ SE = \frac{1500}{\sqrt{36}} = \frac{1500}{6} = 250 \]
03

Determine the Critical Value

For a 95% confidence interval, we use the Z-distribution since the sample size is greater than 30. The critical value (Z*) for 95% confidence is 1.96.
04

Construct the Confidence Interval

The formula for the confidence interval is:\[ \text{Confidence Interval} = \text{Sample Mean} \pm Z^* \times SE \]Substitute the values:\[ 9560 \pm 1.96 \times 250 \]Calculate:- Lower bound: \( 9560 - 490 = 9070 \)- Upper bound: \( 9560 + 490 = 10050 \)Thus, the 95% confidence interval is:\[ (9070, 10050) \]
05

Interpret the Confidence Interval

The confidence interval tells us that we are 95% confident that the true mean loss in home value falls between $9070 and $10050. In this context, 95% confidence means that if we were to take many samples and construct confidence intervals in the same way, approximately 95% of those intervals would contain the true mean loss value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Limit Theorem (CLT)
The Central Limit Theorem (CLT) is a fundamental concept in statistics. It states that the sampling distribution of the sample mean will approximate a normal distribution, regardless of the shape of the population, as long as the sample size is sufficiently large. The CLT is particularly powerful because it allows us to make inferences about population parameters using sample statistics, even when we don’t know much about the population itself. For many practical purposes:
  • A sample size of 30 or more is usually considered large enough to invoke the CLT.
  • Normal approximation becomes better as sample size increases.
In the context of the home sales exercise, the sample size was 36, which is above 30, allowing us to use the CLT to assume the sampling distribution of the mean is approximately normal. This permits the further steps of calculating the confidence interval.
Standard Error
The Standard Error (SE) is a measure of the variability or spread of the sampling distribution of a statistic, most commonly the sample mean. It essentially provides a gauge for how much the sample mean of the population could vary from sample to sample. The formula for calculating the standard error of the sample mean is:\[SE = \frac{\text{Sample Standard Deviation}}{\sqrt{\text{Sample Size}}}\]A smaller SE indicates that the sample mean is more precise as an estimate of the population mean. In the given exercise, the sample's standard deviation was \(1,500, and the sample size was 36. Substituting these values, the SE was calculated to be \)250. This SE was then used to determine how wide the confidence interval should be, ultimately contributing to our understanding of the precision of our estimate for the mean loss in home value.
Normal Distribution
Normal distribution, often called the bell curve due to its shape, is a continuous probability distribution that is symmetric about the mean. Many natural phenomena and measurement errors exhibit a normal distribution. Characteristics:
  • It has a mean of 0 and a standard deviation of 1 in its standard form.
  • Approximately 68% of data falls within one standard deviation from the mean, 95% within two, and 99.7% within three.
In the context of confidence intervals, the normal distribution plays a crucial role since many statistical methods rely on the assumption of normality. Even if the population distribution isn't normal, the sampling distribution of the sample mean can approximate normality according to the Central Limit Theorem, provided the sample size is large enough. In the home sales example, the normal distribution allowed the use of the standard normal Z-distribution to determine the critical value needed to construct the 95% confidence interval.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For Example, 2 nd look This chapter's For Examples looked at mirex contamination in farmed salmon. We first found a \(95 \%\) confidence interval for the mean concentration to be 0.0834 to 0.0992 parts per million. Later we rejected the null hypothesis that the mean did not exceed the EPA's recommended safe level of 0.08 ppm based on a P-value of \(0.0027 .\) Explain how these two results are consistent. Your explanation should discuss the confidence level, the P-value, and the decision.

TV safety The manufacturer of a metal stand for home TV sets must be sure that its product will not fail under the weight of the TV. since some larger scis weigh nearly 300 pounds, the company's safety inspectors have set a standard of ensuring that the stands can support an average of over 500 pounds. Their inspectors regularly subject a random sample of the stands to increasing weight until they fail. They test the hypothesis \(\mathrm{H}_{0}: \mu=500\) against \(\mathrm{H}_{\mathrm{A}}: \mu>500,\) using the level of significance \(\alpha=0.01 .\) If the sample of stands fails to pass this safety test, the inspectors will not certify the product for sale to the general public. a) Is this an upper-tail or lower-tail test? In the context of the problem, why do you think this is important? b) Explain what will happen if the inspectors commit a Type I error. c) Explain what will happen if the inspectors commit a Type II error.

Marriage In \(1960,\) census results indicated that the age at which American men first married had a mean of 23.3 years. It is widely suspected that young people today are waiting longer to get marricd. We want to find out if the mean age of first marriage has increased during the past 40 years. a) Write appropriate hypotheses. b) We plan to test our hypothesis by selecting a random sample of 40 men who marricd for the first time last year. Do you think the necessary assumptions for inference are satisfied? Explain. c) Describe the approximate sampling distribution model for the mean age in such samples. d) The men in our sample married at an average age of 24.2 years, with a standard deviation of 5.3 years. What's the P-value for this result? e) Explain (in context) what this P-value means. f) What's your conclusion?

Ruffles Students investigating the packaging of potato chips purchased 6 bags of Lay's Ruffles marked with a net weight of 28.3 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): 29.3,28.2,29.1,28.7,28.9,28.5 a) Do these data satisfy the assumptions for inference? Explain. b) Find the mean and standard deviation of the weights. c) Create a \(95 \%\) confidence interval for the mean weight of such bags of chips. d) Explain in context what your interval means. e) Comment on the company's stated net weight of 28.3 grams.

\- Jelly A consumer advocate wants to collect a sample of jelly jars and measure the actual weight of the product in the container. He needs to collect enough data to construct a confidence interval with a margin of error of no more than 2 grams with \(99 \%\) confidence. The standard deviation of these jars is usually 4 grams. What do you recommend for his sample size?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.