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Fast food The global survey we learned about in Exercise 35 also asked respondents how they felt about the statement "I try to avoid eating fast foods." The random sample of 800 included 411 people 35 years old or younger, and of those, 197 agreed (completely or somewhat) with the statement. Of the 389 people over 35 years old, 246 people agreed with the statement. Is there evidence that the percentage of people avoiding fast food is different in the two age groups?

Short Answer

Expert verified
Yes, there is significant evidence of a difference in proportions between the age groups.

Step by step solution

01

Define Hypotheses

First, we need to establish our null and alternative hypotheses. We are testing if there is a difference in the percentage of people avoiding fast food between two age groups. Let \( p_1 \) be the proportion of people 35 years old or younger who agree with the statement, and \( p_2 \) be the proportion of people over 35 who agree. Our null hypothesis \( H_0 \) is that \( p_1 = p_2 \), meaning there is no difference in the proportions. The alternative hypothesis \( H_a \) is that \( p_1 eq p_2 \).
02

Calculate Sample Proportions

Calculate the sample proportion of people 35 years or younger who agree with the statement: \( \hat{p}_1 = \frac{197}{411} \approx 0.479 \). For people over 35: \( \hat{p}_2 = \frac{246}{389} \approx 0.632 \).
03

Compute the Standard Error

The standard error of the difference between two proportions is given by the formula: \[ SE = \sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \frac{\hat{p}_2(1-\hat{p}_2)}{n_2}} \]Substituting the given values:\[ SE = \sqrt{\frac{0.479(1-0.479)}{411} + \frac{0.632(1-0.632)}{389}} \approx 0.035 \]
04

Calculate the Z-Score

The Z-score is calculated to compare the difference in sample proportions to the hypothesized difference of zero:\[ Z = \frac{\hat{p}_1 - \hat{p}_2}{SE} = \frac{0.479 - 0.632}{0.035} \approx -4.371 \]
05

Find the P-Value

We use the Z-score to determine the p-value. A Z-score of -4.371 corresponds to a very small p-value, much less than 0.05, when using standard normal distribution tables or a calculator. This p-value indicates a statistically significant difference.
06

Interpret the Results

Since the p-value is less than the typical significance level of 0.05, we reject the null hypothesis. This suggests there is strong evidence of a difference in the percentage of people avoiding fast food between the two age groups.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
In hypothesis testing, sample proportions help to summarize the data gathered from a sample in terms of how many observations fit a particular characteristic or trait. The sample proportion is calculated by dividing the number of favorable responses by the total number of respondents in the sample.

For instance, in the given exercise, we have two age groups with distinct sample proportions.
  • For individuals 35 years old or younger, the sample proportion (\(\hat{p}_1\) is 0.479. This means about 47.9% of this age group agrees with avoiding fast food.
  • For individuals over 35, the sample proportion (\(\hat{p}_2\)) is 0.632, signifying that 63.2% agree with avoiding fast food.
Both proportions help us understand how each group perceives the statement regarding fast food, and to analyze if there's a significant age-based difference.
Standard Error
The standard error (SE) is a measure that reflects the variability of a statistic, like the difference between two proportions, within repeated sampling.It's crucial when comparing sample proportions because it takes into account the sample size and variability into a single statistic.

Calculating the standard error for the difference between two proportions requires the formula:\[SE = \sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \frac{\hat{p}_2(1-\hat{p}_2)}{n_2}} \]
In our case, this formula reflects the uncertainty around the observed difference between the two age groups. With the calculated standard error of approximately 0.035, it allows us to reasonably gauge the difference between the proportion of young people and older people who try to avoid fast food. A smaller standard error indicates a more reliable estimate of this difference.
Z-score
The Z-score helps us determine how far, in terms of standard deviations, our observed proportion difference is from the hypothesized difference, typically zero.This score tells us whether the differences observed in sample proportions are significant or not.

To compute the Z-score, we use the formula:\[Z = \frac{\hat{p}_1 - \hat{p}_2}{SE}\]
In this scenario, the calculated Z-score is approximately -4.371.This negative value indicates that the sample proportion of younger people agreeing with the statement is less than that of the older group.An absolute Z-score significantly larger than 2, as in this example, often indicates a strong deviation, raising the suspicion that the null hypothesis might not be true.
P-value
The p-value is a crucial part of hypothesis testing, used to measure the probability of observing test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is true. The smaller the p-value, the greater the evidence against the null hypothesis.

In the exercise, we use the Z-score to find the p-value. A Z-score of about -4.371 corresponds to a very small p-value. This implies that the probability of observing such a substantial difference by random chance is very low.
If the p-value is less than the chosen significance level, often 0.05, we reject the null hypothesis. Here, since the p-value is much less than 0.05, it strongly indicates a real difference in the avoidance of fast food between the two age groups, signifying that age impacts people's likelihood to avoid fast food.

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Most popular questions from this chapter

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