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Twins In \(2001,\) one county reported that, among 3132 white women who had babies, 94 were multiple births. There were also 20 multiple births to 606 black women. Does this indicate any racial difference in the likelihood of multiple births? a) Test an appropriate hypothesis and state your conclusion in context. b) If your conclusion is incorrect, which type of error did you commit?

Short Answer

Expert verified
There is no evidence of a racial difference. If incorrect, it's a Type II error.

Step by step solution

01

Formulate Hypotheses

We need to test whether there is a racial difference in the likelihood of multiple births between white and black women. We will set up the null and alternative hypotheses. \( H_0: p_1 = p_2 \) (there is no difference in the proportion of multiple births), and \( H_a: p_1 eq p_2 \) (there is a difference in the proportion of multiple births). Here, \( p_1 \) is the proportion of multiple births among white women, and \( p_2 \) is the proportion of multiple births among black women.
02

Calculate Sample Proportions

Calculate the proportion of multiple births for each group. For white women, \( \hat{p}_1 = \frac{94}{3132} \approx 0.03 \). For black women, \( \hat{p}_2 = \frac{20}{606} \approx 0.033 \).
03

Calculate the Pooled Proportion

Since we assume the null hypothesis, calculate the pooled proportion \( \hat{p} \): \( \hat{p} = \frac{94 + 20}{3132 + 606} = \frac{114}{3738} \approx 0.0305 \).
04

Calculate the Test Statistic

Use the formula for the test statistic for two proportions: \[ z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_1} + \frac{1}{n_2})}} \] where \( n_1 = 3132 \), \( n_2 = 606 \). Substituting the values, \( z \approx \frac{0.03 - 0.033}{\sqrt{0.0305(1-0.0305)(\frac{1}{3132} + \frac{1}{606})}} \approx -0.3 \).
05

Determine Significance Level and Critical Value

Choose a significance level, commonly \( \alpha = 0.05 \). For a two-tailed test, the critical z-value is \( \pm 1.96 \).
06

Make a Decision

Since the calculated \( z \) value (-0.3) does not exceed the critical value of \( \pm 1.96 \), we fail to reject the null hypothesis. There is no statistical evidence of a racial difference in the likelihood of multiple births.
07

Identify Potential Error

As we did not reject the null hypothesis but potentially commit an error, the error could be a Type II error (failing to reject a false null hypothesis).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
A proportion is a statistical metric that represents the fraction of the total that possesses a certain characteristic or attribute. In the context of hypothesis testing, proportions are often used to compare groups.

For example, if we are interested in the likelihood of multiple births among different races, we first calculate the proportion of those events in each group:
  • For white women: the proportion is calculated as the number of multiple births divided by the total number of births, which is \( \hat{p}_1 = \frac{94}{3132} \approx 0.03 \).
  • For black women: \( \hat{p}_2 = \frac{20}{606} \approx 0.033 \).
This proportion helps to understand what fraction of births is multiple for each racial group, allowing for direct comparison between the two.
Pooled Proportion
The pooled proportion is an essential concept when testing hypotheses between two groups with respect to their proportions. It essentially combines the data from both groups to create a weighted average proportion.

This is particularly useful under the null hypothesis assumption that both groups share the same "true" proportion. The formula for the pooled proportion, \( \hat{p} \), is:\[ \hat{p} = \frac{x_1 + x_2}{n_1 + n_2} \]where:
  • \(x_1\) and \(x_2\) are the number of successful outcomes (here, multiple births) in groups 1 and 2, respectively.
  • \(n_1\) and \(n_2\) are the total numbers of trials (births in this context) in groups 1 and 2, respectively.
Combining the data for white and black women gives us:\[ \hat{p} = \frac{94 + 20}{3132 + 606} \approx 0.0305 \]This result indicates that about 3.05% of all births in this combined sample were multiple, serving as a benchmark in our hypothesis test.
Null Hypothesis
The null hypothesis is a baseline assumption that there is no effect or difference between groups being tested. In hypothesis testing, it provides a starting point for statistical inference.

For the exercise at hand, we formed the null hypothesis \( H_0: p_1 = p_2 \), meaning that the proportion of multiple births among white women is equal to that among black women.

We use the null hypothesis to evaluate our sample data against the claim that no racial difference exists in the likelihood of multiple births. The objective is to test whether the sample provides sufficient evidence to reject this hypothesis. If our calculated statistics show a statistically significant result, we may reject the null hypothesis in favor of the alternative hypothesis, indicating a potential difference in proportions.
Type II Error
In hypothesis testing, a Type II error occurs when the null hypothesis is not rejected even though it is false. This error indicates a failure to detect an actual effect or difference when one exists.

In the scenario described, we concluded that there is no difference in the proportion of multiple births between white and black women, which aligns with the null hypothesis. However, if this conclusion is incorrect, we may have committed a Type II error.

This type of error is especially relevant in contexts where failing to recognize a true difference could have significant implications. The potential for Type II errors is influenced by several factors, including sample size, variance, and the significance level. Careful consideration of these factors and potentially increasing sample size could help reduce the risk of committing a Type II error.

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