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In the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, testing samples of several different brands of each type. Suppose the study tested the null hypothesis that top- and front-loading machines don't differ in their mean costs, and the test had a P-value of 0.32 . Would a \(95 \%\) confidence interval for \(\mu_{t o p}-\mu_{\text {front }}\) contain 0 ? Explain.

Short Answer

Expert verified
Yes, a 95% confidence interval for \(\mu_{top}-\mu_{front}\) would contain 0 because the p-value of 0.32 suggests that there's not enough evidence to reject the null hypothesis, which states that the mean difference is zero.

Step by step solution

01

Understanding the null hypothesis

The null hypothesis for this situation indicates that the difference in the mean costs of top- and front-loading machines is zero. Meaning, \(\mu_{top}-\mu_{front} =0\), implying there is no difference in the mean costs.
02

Understanding P-value and its implications

The provided p-value for the test is 0.32 which is greater than 0.05, a commonly accepted threshold for rejecting the null hypothesis. When the p-value is greater than 0.05, it suggests there's not enough evidence to reject the null hypothesis and the true population mean difference could be zero.
03

Establishing the connection with confidence intervals

A 95% confidence interval for the mean difference between top- and front-loading machines gives us a range of plausible values the true population difference could take. Given the high p-value, in this scenario, it is likely that this confidence interval includes zero, supporting the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values used to estimate an unknown population parameter, like the mean difference between two types of washing machines. When you calculate a confidence interval, such as a 95% confidence interval, it essentially means you're 95% confident the true mean difference lies within this range. This does not guarantee the true difference is within the interval, but rather it's based on repeated sampling from the population.

In the context of hypothesis testing, a confidence interval can help verify the results. If a confidence interval for the mean difference includes zero, it suggests there's no significant difference in the costs. In our example, the high p-value hints that the interval likely captures zero, reinforcing the idea that there's no meaningful cost difference.

Confidence intervals provide visual and quantitative insights into the reliability of an estimate.
Null Hypothesis
The null hypothesis acts as a starting assumption in statistical tests. It's the statement of no effect or no difference, and is symbolized as \(H_{0}\). In our example, the null hypothesis suggests the costs between top-loading and front-loading washing machines are the same, or \( \mu_{top} - \mu_{front} = 0 \).

Testing it involves determining if the observed sample data provides enough evidence to reject this assumption. When no such evidence is found, as indicated by a large p-value, the null hypothesis remains plausible.

Understanding and testing the null hypothesis are crucial in making informed decisions based on statistical data.
P-value
A p-value helps decide the strength of evidence against the null hypothesis. It reveals the probability of observing data at least as extreme as the sample data, assuming the null hypothesis is true. In more straightforward terms, it's the measure of how incompatible the data is with the null hypothesis.

In our example, the p-value is 0.32. A value greater than 0.05 often means the evidence is not strong enough to reject the null hypothesis. This signifies that the observed mean cost difference between top-loading and front-loading machines is likely due to random variation rather than a real effect.

P-values serve as a guide in hypothesis testing, helping to draw conclusions about whether to accept or reject the null hypothesis.
Mean Difference
Mean difference quantifies how different two groups are from one another in terms of their averages. In hypothesis testing, it often represents \( \mu_{top} - \mu_{front} \), the mean cost difference of washing machine types in our case. This measure helps understand whether one group's average surpasses the other's by a significant amount.

Identifying the mean difference helps in comparing the effectiveness or cost between two groups. A substantial graphical or numerical difference suggests a notable contrast.In the scenario discussed, a mean difference of zero implies no real cost disparity exists between top-loading and front-loading machines. The confidence interval and p-value further validate this by showing zero plausibility.

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Most popular questions from this chapter

At the end of \(2013,\) the Pew Project for Excellence in Journalism investigated where people are getting their news. In the study \(22 \%\) of people \(18-29\) years old said they still read newspapers as one of their sources of news, while only \(18 \%\) of people \(30-49\) said the same. What does it mean to say that the difference is not significant?

A presidential candidate fears he has a problem with women voters. His campaign staff plans to run a poll to assess the situation. They'll randomly sample 300 men and 300 women, asking if they have a favorable impression of the candidate. Obviously, the staff can't know this, but suppose the candidate has a positive image with \(59 \%\) of males but with only \(53 \%\) of females. a. What kind of sampling design is his staff planning to use? b. What difference would you expect the poll to show? c. Of course, sampling error means the poll won't reflect the difference perfectly. What's the standard deviation for the difference in the proportions? d. Sketch a sampling model for the size difference in proportions of men and women with favorable impressions of this candidate that might appear in a poll like this. e. Could the campaign be misled by the poll, concluding that there really is no gender gap? Explain.

When a random sample of 935 parents were asked about rules in their homes, \(77 \%\) said they had rules about the kinds of TV shows their children could watch. Among the 790 of those parents whose teenage children had Internet access, \(85 \%\) had rules about the kinds of Internet sites their teens could visit. That looks like a difference, but can we tell? Explain why a two-sample \(z\) -test would not be appropriate here.

The Consumer Reports article described in Exercise 51 also listed the fat content (in grams) for samples of beef and meat hot dogs. The resulting \(90 \%\) confidence interval for \(\mu_{M e a t}-\mu_{B e e f}\) is (-6.5,-1.4) a. The endpoints of this confidence interval are negative numbers. What does that indicate? b. What does the fact that the confidence interval does not contain 0 indicate? c. If we use this confidence interval to test the hypothesis that \(\mu_{M e a t}-\mu_{B e e f}=0\) what's the corresponding alpha level?

You are a consultant to the marketing department of a business preparing to launch an ad campaign for a new product. The company can afford to run ads during one TV show, and has decided not to sponsor a show with sexual content. You read the study described in Exercise 75 , then use a computer to create a confidence interval for the difference in mean number of brand names remembered between the groups watching violent shows and those watching neutral shows. TWO-SAMPLET \(95 \%\) CI FOR MUviol - MUneut : (-1.578,-0.602) a. At the meeting of the marketing staff, you have to explain what this output means. What will you say? b. What advice would you give the company about the upcoming ad campaign?

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