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Crawling Data collected by child development scientists produced this confidence interval for the average age (in weeks) at which babies begin to crawl: t-Interval for \(\mu\). \(30.65<\mu(\) age \()<32.89\) \((95.00 \%\) Confidence) a. Explain carefully what the software output means. b. What is the margin of error for this interval? c. If the researcher had calculated a \(90 \%\) confidence interval, would the margin of error be larger or smaller? Explain.

Short Answer

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The output means that based on the data, we are 95% confident that the average age (in weeks) at which babies begin to crawl lies between 30.65 weeks and 32.89 weeks. The margin of error for this interval is approximately 1.12 weeks. A reduction in confidence level to 90% would result in a smaller margin of error.

Step by step solution

01

Understanding Confidence Interval

The output specifies a 95% confidence interval for the average age (in weeks) at which babies begin to crawl. It states that, within a 95% confidence level, the average age at which babies initiate to crawl falls between 30.65 weeks and 32.89 weeks. This indicates the likelihood that the parameter \( \mu \) (population mean) lies within this interval.
02

Calculate Margin of Error

The margin of error in a confidence interval is half the range of the interval. In this instance, it's obtained by subtracting the lower limit from the upper limit and then dividing by 2. Hence, margin of error = (32.89 - 30.65) / 2 = 1.12 weeks approximately.
03

Comparing Confidence Intervals

In case the researcher had calculated a 90% confidence interval, the margin of error would be smaller. This is because a lower confidence level produces a narrower confidence interval, hence decreasing the margin of error. A lower confidence level is less strict, allowing for less range and hence a smaller margin of error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error plays a crucial role in understanding confidence intervals. It tells us how much we can expect our sample mean to deviate from the population mean. To compute it, you take the range of the confidence interval, which is the difference between the upper limit and the lower limit, and divide it by 2. For instance, if we have a confidence interval for the average age babies start crawling of 30.65 to 32.89 weeks, the range is calculated as: 32.89 - 30.65. By taking half of this range, we find the margin of error, which in this case is approximately 1.12 weeks. A smaller margin of error suggests that the sample mean is a more precise estimate of the population mean.
Population Mean
The population mean, denoted by the Greek letter \( \mu \), represents the average value of a characteristic across an entire population. In our example, it is the average age at which all babies within the population begin to crawl. Since it's often impractical to measure every single member of a population, we use sample data to estimate the mean. Confidence intervals help us understand where the true population mean likely lies. In our crawling babies exercise, the confidence interval was from 30.65 to 32.89 weeks. This interval estimates that the true population mean of crawling age falls somewhere in this range.
Confidence Level
Confidence level is the percentage that reflects how certain we are that the true population mean lies within our calculated confidence interval. For example, a 95% confidence level implies that if we were to take 100 different samples and compute confidence intervals for each, we would expect about 95 of those intervals to contain the population mean. Higher confidence levels give more assurance that the interval includes the population mean, but this comes at the cost of a wider interval. In contrast, a 90% confidence level would result in a narrower confidence interval and hence a smaller margin of error than a 95% confidence level.
Statistical Interpretation
Statistical interpretation involves making sense of data, such as interpreting the meaning of a confidence interval. It requires understanding that a 95% confidence interval of 30.65 to 32.89 weeks for the average crawling age does not mean all babies will begin to crawl within this timeframe. Instead, it's an estimate that reflects our certainty level about where the true population mean lies. Proper statistical interpretation involves recognizing the influence of factors like sample size, variability in data, and chosen confidence level, all of which affect the precision and reliability of our confidence intervals. Each factor must be analyzed to derive meaningful and accurate conclusions from statistical results.

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Most popular questions from this chapter

Speed of light In \(1882,\) Michelson measured the speed of light (usually denoted \(c\) as in Einstein's famous equation \(E=m c^{2}\) ). His values are in \(\mathrm{km} / \mathrm{sec}\) and have 299,000 subtracted from them. He reported the results of 23 trials with a mean of 756.22 and a standard deviation of 107.12 . a. Find a \(95 \%\) confidence interval for the true speed of light from these statistics. b. State in words what this interval means. Keep in mind that the speed of light is a physical constant that, as far as we know, has a value that is true throughout the universe. c. What assumptions must you make in order to use your method?

LSAT The LSAT (a test taken for law school admission) has a mean score of 151 with a standard deviation of 9 and a unimodal, symmetric distribution of scores. A test preparation organization teaches small classes of 9 students at a time. A larger organization teaches classes of 25 students at a time. Both organizations publish the mean scores of all their classes. a. What would you expect the sampling distribution of mean class scores to be for each organization? b. If either organization has a graduating class with a mean score of 160 , they'll take out a full-page ad in the local school paper to advertise. Which organization is more likely to have that success? Explain. c. Both organizations advertise that if any class has an average score below \(145,\) they'll pay for everyone to retake the LSAT. Which organization is at greater risk to have to pay?

\(t\) -models, part II Using the \(t\) -tables, software, or a calculator, estimate a. the critical value of \(t\) for a \(95 \%\) confidence interval with \(d f=7\) b. the critical value of \(t\) for a \(99 \%\) confidence interval with \(d f=102\)

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