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Salmon A specialty food company sells whole King Salmon to various customers. The mean weight of these salmon is 35 pounds with a standard deviation of 2 pounds. The company ships them to restaurants in boxes of 4 salmon, to grocery stores in cartons of 16 salmon, and to discount outlet stores in pallets of 100 salmon. To forecast costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. a. Find the standard deviations of the mean weight of the salmon in each type of shipment. b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets? Explain.

Short Answer

Expert verified
a. The standard deviations of the mean weight of the salmon in boxes, cartons and pallets are 1 pound, 0.5 pound, and 0.2 pound respectively. b. The distribution of shipping weights for larger samples (pallets) would likely be more accurately characterized by a Normal model due to the Central Limit Theorem.

Step by step solution

01

Understanding the problem

We know the mean weight (\( \mu \)) of the salmon is 35 pounds and standard deviation (\( \sigma \)) is 2 pounds. We need to calculate standard deviation of mean weights (\( \sigma_\bar{x} \)) for shipment sizes of 4 (n1), 16 (n2) and 100 (n3) salmons. The standard error of the mean, or standard deviation of sampling distribution, is given by the formula: \( \sigma_\bar{x} = \frac{\sigma}{\sqrt{n}} \). We apply this formula for each shipment size separately.
02

Calculation for boxes (4 salmons)

For boxes of 4 salmons, apply the standard deviation formula: \( \sigma_{\bar{x}_{n1}} = \frac{2}{\sqrt{4}} = 1 \) pound.
03

Calculation for cartons (16 salmons)

For cartons of 16 salmons, use the standard deviation formula: \( \sigma_{\bar{x}_{n2}} = \frac{2}{\sqrt{16}} = 0.5 \) pound.
04

Calculation for pallets (100 salmons)

For pallets of 100 salmons, substitute the values into the formula: \( \sigma_{\bar{x}_{n3}} = \frac{2}{\sqrt{100}} = 0.2 \) pound.
05

Applying the Central Limit Theorem

According to the Central Limit Theorem, as the sample size increases, the sampling distribution of the mean approaches a normal distribution regardless of the shape of the population distribution. However, for smaller samples, the shape of the population distribution becomes more important. Given that the salmon weight distribution is skewed to the high end, the distribution for smaller shipments (boxes) would most likely be similarly skewed, whereas the distribution for larger samples (pallets) would be more likely to be approximated by a Normal model.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
The concept of sampling distribution is crucial to understanding how the variation within a sample of data points relates to the entire population from which the sample is drawn. Imagine you're at a party where there's a bowl filled with differently colored candies. Each time you take a small handful of candies, that's like taking a sample. Now, if you were to take multiple handfuls, each time recording the proportion of colors, the collection of those proportions represents a sampling distribution. In our salmon weight scenario, the sampling distribution refers to different possible outcomes for the average weights of salmon if we repeatedly took shipments of 4, 16, or 100 salmon, and exactly that helps us to estimate the expected range or spread around the mean weight.

When we compute the standard deviation of the mean weight for different shipment sizes, what we're essentially doing is finding out how much variability we can expect from the average weight of salmon per shipment. It gives the shipping department a sense of certainty—or uncertainty—about how much a shipment is expected to weigh, which is crucial for logistical and cost planning. For shipment sizes of 4 salmons, 16 salmons, and 100 salmons, we can apply the formula \( \sigma_\bar{x} = \frac{\sigma}{\sqrt{n}} \) to deduce that larger shipments will, on average, be closer to the mean weight, indicating less variability and a more reliable forecast.
Central Limit Theorem
Physical laws are pretty consistent — an apple will fall downwards from a tree, not sideways. Similarly, in the world of statistics, we have the Central Limit Theorem (CLT), which provides a steadfast rule for understanding how the averages from those samples (our candy handfuls or salmon shipments) will behave.

The CLT tells us an amazing fact: no matter what the original distribution of the population (be it lopsided, uniform, or even lumpy), as long as the sample size is sufficiently large, the sampling distribution of its mean will resemble a normal distribution. That's like saying if you took enough handfuls of candy, eventually, the proportion of colors in your handfuls would settle into a predictable pattern, even if the bowl's mixture was quite wacky to start with. Hence, when computing the standard deviation of the mean for those salmon shipments, the CLT reassures us that for the larger shipments, the distribution of shipping weights is more predictable and generally normal. Even when the salmon weights themselves are skewed, larger shipment sizes (such as pallets of 100 salmon) become less sensitive to the original skewness and are more likely to align with a normal distribution, simplifying statistical forecasting and planning.
Statistical Forecasting
Now that we've netted the concepts of sampling distribution and the Central Limit Theorem, let's set sail into the deep waters of statistical forecasting. Picture this as the captain’s wheel, helping the company navigate through the uncertainties of the future.

Armed with the data on standard deviations for the mean weights of salmon shipments, the seafood company can predict not just the average weight, but also prepare for the variation they might encounter. In the case of fish, like salmon, which can vary in size, this knowledge is extremely valuable. For instance, our calculations for smaller shipments will lead to a wider range for the forecast, owing to the higher standard deviation. In contrast, larger shipments, with a lower standard deviation, will have a much tighter forecast range. This enables the shipping department to better allocate resources, manage cost implications, and ultimately steer the company towards smoother logistical waters.

In essence, statistical forecasting is the practical application of statistical methods to predict future data points. It hinges on historical data and statistical principles like the sampling distribution and CLT, and involves understanding variability and uncertainty to make informed business decisions — how many trucks are needed, what's the probable shipping cost, and how much buffer stock is required, to name a few. Surely, knowing what might lie ahead is a boon for any captain of industry!

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