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Teenage drivers An insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel in 91 of them. a. Create a \(95 \%\) confidence interval for the percentage of all auto accidents that involve teenage drivers. b. Explain what your interval means. c. Explain what "95\% confidence" means. d. A politician urging tighter restrictions on drivers' licenses issued to teens says, "In one of every five auto accidents, a teenager is behind the wheel." Does your confidence interval support or contradict this statement? Explain.

Short Answer

Expert verified
The solution involves calculating the sample proportion, standard error, and the 95% confidence interval. The interpretation of the interval revolves around the concept that if the survey were repeated many times, 95% of the times, the true population proportion would fall within this interval. The final interpretation depends on whether the proportion corresponding to the statement made by the politician is within our calculated interval. Please refer to the step-by-step solution for detailed calculations and interpretations.

Step by step solution

01

Calculating the Sample Proportion

Knowing the total number of cases (582) and the number of cases involving teen drivers (91), the sample proportion \(p\) can be calculated as \(p = \frac{91}{582}\). Calculate this value and it will be the sample proportion.
02

Calculating the Standard Error

The standard error of the sample proportion can be calculated using the formula \(SE = \sqrt{\frac{p(1-p)}{n}}\), where \(n\) is the number of accidents. Plug the values of \(p\) and \(n\) into the formula to get the standard error.
03

Calculating the Confidence Interval

The formula for the 95% confidence interval is \((p - 1.96SE, p + 1.96SE)\). Simply substitute the values of \(p\) and \(SE\) into the formula to find the confidence interval.
04

Explaining the Confidence Interval

This interval means that the insurance company can be 95% confident that the true percentage of auto accidents involving teen drivers lies within the interval calculated in step 3.
05

Explaining 95% Confidence Level

The phrase '95% confidence' implies that if the same sample survey were repeated many times under similar conditions, 95 out of 100 times the true population proportion would fall within the calculated interval.
06

Interpreting against the Given Statement

This step involves checking if the calculated interval encompasses the proportion represented by the politician's statement, i.e., 0.2 or 20%. If 20% lies within our interval, then the data does not contradict the statement. If it falls outside our interval, then the data does not support the statement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion represents the fraction of a sample that meets a certain criterion. It is essentially an estimate of the population proportion based on a smaller group. In our problem, the insurance company selected 582 random accidents and found that teenagers were behind the wheel in 91 of these incidents.

To find the sample proportion (\(p\)), we divide the number of accidents involving teenagers by the total number of accidents sampled. So, in this case, the calculation would be \(p = \frac{91}{582}\). This quotient gives us a straightforward estimate of how often teenagers are involved in accidents, as observed in the sampled accidents.

Understanding the sample proportion is crucial because it forms the base for further calculations like the standard error and the confidence interval.
Standard Error
Standard error is a measure of the variability of a sample statistic across different samples. It essentially tells us how much the sample proportion might vary from the true population proportion.

In the context of our problem, the standard error (\(SE\)) of the sample proportion is calculated using the formula \(SE = \sqrt{\frac{p(1-p)}{n}}\), where \(p\) is the sample proportion and \(n\) is the sample size.

By substituting the values we've calculated or found from our sample, we get a numerical value for the standard error. This value helps us understand the "margin of error" in our estimates and allows us to build a confidence interval around the sample proportion.
Population Proportion
Population proportion is the true proportion of the population that meets a certain criterion. Unlike the sample proportion, which is derived from a sample, the population proportion is what we are trying to estimate or infer through our analysis.

In our exercise, we are trying to estimate the proportion of all car accidents that involve teen drivers in the entire population. We use the sample proportion to make this estimation, recognizing that it is merely an approximation.

By using statistical methods like confidence intervals, we attempt to infer what the true population proportion might be, keeping in mind that it is not directly observable and carries a certain level of uncertainty.
95% Confidence Level
A 95% confidence level is a term used to indicate the degree of certainty we have about our statistical estimates. Specifically, it means that if we were to take many samples and build an interval estimate for each one, 95% of these intervals would contain the actual population proportion.

In simpler terms, when we say that we are 95% confident in our interval, it means that our method of interval creation is reliable and would be correct 95 times out of 100 in the long run.

For our problem, this definition helps us to understand that the interval we calculated for the percentage of accidents involving teenage drivers is likely to be an accurate reflection of reality based on our chosen confidence level. However, there is always a 5% chance that the true proportion lies outside of this interval, which we should also recognize.

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Most popular questions from this chapter

More conditions Consider each situation described. Identify the population and the sample, explain what \(p\) and \(\hat{p}\) represent, and tell whether the methods of this chapter can be used to create a confidence interval. a.A consumer group hoping to assess customer experiences with auto dealers surveys 167 people who recently bought new cars; \(3 \%\) of them expressed dissatisfaction with the salesperson. b. What percent of college students have cell phones? 2883 students were asked as they entered a football stadium, and 2430 said they had phones with them. c. Two hundred forty potato plants in a field in Maine are randomly checked, and only 7 show signs of blight. How severe is the blight problem for the U.S. potato industry? d. Twelve of the 309 employees of a small company suffered an injury on the job last year. What can the company expect in future years?

Gambling A city ballot includes a local initiative that would legalize gambling. The issue is hotly contested, and two groups decide to conduct polls to predict the outcome. The local newspaper finds that \(53 \%\) of 1200 randomly selected voters plan to vote "yes," while a college statistics class finds \(54 \%\) of 450 randomly selected voters in support. Both groups will create \(95 \%\) confidence intervals. a. Without finding the confidence intervals, explain which one will have the larger margin of error. b. Find both confidence intervals. c. Which group concludes that the outcome is too close to call? Why?

Send money When they send out their fundraising letters, a philanthropic organization typically gets a return from about \(5 \%\) of the people on their mailing list. To see what the response rate might be for future appeals, they did a simulation using samples of size \(20,50,100,\) and 200 . For each sample size, they simulated 1000 mailings with success rate \(p=0.05\) and constructed the histogram of the 1000 sample proportions, shown below. Explain what these histograms show about the sampling distribution model for sample proportions. Be sure to talk about shape, center, and spread.

Another pilot study During routine screening, a doctor notices that \(22 \%\) of her adult patients show higher than normal levels of glucose in their blood-a possible warning signal for diabetes. Hearing this, some medical researchers decide to conduct a large-scale study, hoping to estimate the proportion to within \(4 \%\) with \(98 \%\) confidence. How many randomly selected adults must they test?

Death penalty, again In the survey on the death penalty you read about in the Step-by-Step Example, the Gallup Poll actually split the sample at random, asking 510 respondents the question quoted earlier, "Generally speaking, do you believe the death penalty is applied fairly or unfairly in this country today?" The other 510 were asked, "Generally speaking, do you believe the death penalty is applied unfairly or fairly in this country today?" Seems like the same question, but sometimes the order of the choices matters. Suppose that for the second way of phrasing it, \(64 \%\) said they thought the death penalty was fairly applied. (Recall that \(53 \%\) of the original 510 thought the same thing.) a. What kind of bias may be present here? b. If we combine them, considering the overall group to be one larger random sample of 1020 respondents, what is a \(95 \%\) confidence interval for the proportion of the general public that thinks the death penalty is being fairly applied? c. How does the margin of error based on this pooled sample compare with the margins of error from the separate groups? Why?

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