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Cars What fraction of cars made in Japan? The computer output below summarizes the results of a random sample of 50 autos. Explain carefully what it tells you. z-Interval for proportion With \(90.00 \%\) confidence, \(0.29938661<\mathrm{P}(\) japan \()<0.46984416\)

Short Answer

Expert verified
Based on the 90% confidence interval, it can concluded that between approximately 29.94% and 46.98% of cars are made in Japan.

Step by step solution

01

Understanding Confidence Interval

In probability and statistics, a confidence interval is a type of estimate computed from the statistics of the observed data. Here, a confidence interval of 90% is given which suggests that we can be 90% confident that the proportion of cars made in Japan lies within the given interval.
02

Interpret the Limits of the Interval

The given interval:\(0.29938661<\mathrm{P}(\) japan \()<0.46984416\) implies that the proportion of cars made in Japan, lies somewhere between 0.29938661 and 0.46984416.
03

Conclude the Findings

With a 90% confidence level, it can be stated that the proportion of cars made in Japan lies between approximately 29.94% and 46.98%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Inference
Statistical inference plays a critical role in analyzing data and drawing conclusions about a population based on a sample. It encompasses a range of techniques, including hypothesis testing, estimation, and prediction. Among these techniques, estimation is a fundamental concept. The process of inference involves making assumptions about the population and using sample data to estimate population parameters, such as means, proportions, or variances. When we talk about the proportion of cars made in Japan, we are attempting to infer about the entire population of cars based on the sample of 50 autos.

One key aspect of statistical inference is understanding the accuracy and precision of the estimates. This is where confidence intervals come into play. A confidence interval provides a range of values, derived from sample data, that is likely to contain the true population parameter. For instance, if we have a 90% confidence interval, we are saying that if we could repeat the sampling process an infinite number of times, 90% of the intervals would contain the true population proportion.

It is also important to note that the level of confidence one chooses affects the width of the confidence interval. Higher confidence levels lead to wider intervals, as they try to include the true parameter with greater certainty. Students often find it tricky to distinguish between confidence level (a measure of certainty in the estimation process) and the actual confidence interval (the range where the parameter likely falls). By understanding both concepts, one can make more informed decisions based on the data at hand.
Proportion Estimation
Proportion estimation is the process of determining the fraction of a population that has a certain characteristic, such as the fraction of cars made in Japan within the context of the exercise. Estimating proportions is particularly common in survey research and quality control settings. You need a random sample, like the 50 autos mentioned in the problem, to achieve fair estimation of the population proportion.

In the exercise, the estimation of the proportion is crucial because it offers insights into market share and manufacturing trends. The two values provided, 0.29938661 and 0.46984416, are the bounds of the interval within which the estimated population proportion likely falls. The intention is not to pinpoint an exact value, but to provide a range that is based on the sample data collected.

To make the concept of proportion estimation more understandable for students, consider using real-life analogies, such as estimating the percentage of students who prefer a particular cafeteria meal based on a survey of a few dozen students. It becomes easier to grasp the idea of generalizing from a sample to the whole population when one can relate the estimation to everyday situations.
z-Interval for Proportion
The z-interval for a proportion is a specific type of confidence interval used when estimating population proportions. To construct a z-interval, which is based on the z-distribution (or standard normal distribution), one must assume that the sample size is sufficiently large and the data follows a binomial distribution, which is roughly normal when the sample is large. The 'z' in the z-interval refers to the z-score, which you find using the standard normal distribution table corresponding to the chosen confidence level. In our case with a 90% confidence level, the z-score speaks to how many standard deviations away from the mean the proportion lies with 90% certainty.

For constructing a z-interval, the standard error of the proportion is also essential, calculated using the formula involving the sample proportion and sample size. The z-interval formula provides the estimated range within which the true proportion lies, in accordance with the predetermined confidence level. So when the exercise mentions the interval from approximately 29.94% to 46.98%, it's using a z-interval approach to estimate the population proportion.

To help simplify this concept for students, one might explain the z-interval in terms of measurements. For example, if measuring heights, a z-interval might show the range in which the average height of a population is expected to lie, based on sample measurements, also considering how confident we want to be about this range. Such analogies can make the abstract concept of z-intervals more tangible.

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Most popular questions from this chapter

Baseball fans In a poll taken in December 2012, Gallup asked 1006 national adults whether they were baseball fans; \(48 \%\) said they were. Almost five years earlier, in February \(2008,\) only \(35 \%\) of a similar-size sample had reported being baseball fans. a. Find the margin of error for the 2012 poll if we want \(90 \%\) confidence in our estimate of the percent of national adults who are baseball fans. b. Explain what that margin of error means. c. If we wanted to be \(99 \%\) confident, would the margin of error be larger or smaller? Explain. d. Find that margin of error. e. In general, if all other aspects of the situation remain the same, will smaller margins of error produce greater or less confidence in the interval?

30\. Parole A study of 902 decisions (to grant parole or not) made by the Nebraska Board of Parole produced the following computer output. Assuming these cases are representative of all cases that may come before the Board, what can you conclude? z-Interval for proportion With \(95.00 \%\) confidence, $$ 0.56100658<\mathrm{P}(\text { parole })<0.62524619 $$

Spanking In a 2015 Pew Research study on trends in marriage and family (www.pewsocialtrends.org/2015/12/17/1the-american-family-today/), \(53 \%\) of randomly selected parents said that they never spank their children. The \(95 \%\) confidence interval is from \(50.6 \%\) to \(55.4 \%(n=1807)\). a. Interpret the interval in this context. b. Explain the meaning of "95\% confident" in this context.

Marketing The proportion of adult women in the United States is approximately \(51 \%\). A marketing survey telephones 400 people at random. a. What proportion of the sample of 400 would you expect to be women? b. What would the standard deviation of the sampling distribution be? c. How many women, on average, would you expect to find in a sample of that size?

Teachers A 2011 Gallup Poll found that \(76 \%\) of Americans believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1002 Americans. a. Find a \(90 \%\) confidence interval for the proportion of Americans who would agree with this. b. Interpret your interval in this context. c. Explain what "90\% confidence" means. d. Do these data refute a pundit's claim that \(2 / 3\) of Americans believe this statement? Explain.

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