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91Ó°ÊÓ

Which one provides the strongest evidence against \(\mathrm{H}_{0} ?\) p-value \(=0.007\) or \(\quad\) p-value \(=0.13\)

Short Answer

Expert verified
A p-value of 0.007 provides the strongest evidence against the null hypothesis.

Step by step solution

01

Comparing P-values

p-value of 0.007 and p-value of 0.13 are compared. Since 0.007 is smaller than 0.13, it indicates stronger evidence against the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, typically denoted as \(H_0\), is one of the core concepts in hypothesis testing. It represents the default or original claim that there is no effect or no difference in the context of the experiment or study being conducted. For instance, if researchers are testing a new drug, the null hypothesis might state that the drug has no effect on patients compared to a placebo.

In statistical terms, \(H_0\) serves as the assertion to be tested, and it's formulated in such a way that it allows for a clear decision to be made. The null hypothesis is paired with an alternative hypothesis, denoted as \(H_1\) or \(H_a\), which claims that there is indeed an effect or a difference. The objective of hypothesis testing is to make a decision about which hypothesis is supported by the sample data, keeping in mind that the test could potentially lead to a type I error (rejecting \(H_0\) when it's true) or a type II error (failing to reject \(H_0\) when it's false).
Evidence Against Null Hypothesis
Evidence against the null hypothesis arises in the form of statistically significant results, which can cast doubt on \(H_0\)'s validity. The primary tool used to measure this evidence is the p-value, which quantifies how likely the sample data is, assuming that the null hypothesis is true.

When the p-value falls below a pre-determined significance level, often set at 0.05, it suggests that the observed data would be very unlikely if the null hypothesis were true. This is considered strong evidence against \(H_0\), leading researchers to reject the null and consider the alternative hypothesis as more likely. It's important to understand that a low p-value doesn't prove that \(H_0\) is false or that \(H_1\) is true; it merely indicates that the sample data is inconsistent with what we would expect to see if \(H_0\) were correct.
Comparing P-values
Comparing p-values is an integral part of hypothesis testing, as it informs researchers which of the results presents the stronger evidence against the null hypothesis. A smaller p-value indicates that the observed effect is less likely to be due to random chance and therefore is more convincing evidence against \(H_0\).

In the context of the given exercise, a p-value of 0.007 is substantially smaller than a p-value of 0.13. This indicates that the evidence against the null hypothesis is stronger when the p-value is 0.007. Essentially, it means there's a 0.7% chance of the sample data occurring by random variation if \(H_0\) were true, compared to a 13% chance for the larger p-value. In practical applications, comparing p-values can help prioritize findings and determine which hypotheses are worth rejecting and investigating further.

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Most popular questions from this chapter

A study suggests that exposure to UV rays through the car window may increase the risk of skin cancer. \(^{52}\) The study reviewed the records of all 1,050 skin cancer patients referred to the St. Louis University Cancer Center in 2004\. Of the 42 patients with melanoma, the cancer occurred on the left side of the body in 31 patients and on the right side in the other 11 . (a) Is this an experiment or an observational study? (b) Of the patients with melanoma, what proportion had the cancer on the left side? (c) A bootstrap \(95 \%\) confidence interval for the proportion of melanomas occurring on the left is 0.579 to \(0.861 .\) Clearly interpret the confidence interval in the context of the problem. (d) Suppose the question of interest is whether melanomas are more likely to occur on the left side than on the right. State the null and alternative hypotheses. (e) Is this a one-tailed or two-tailed test? (f) Use the confidence interval given in part (c) to predict the results of the hypothesis test in part (d). Explain your reasoning. (g) A randomization distribution gives the p-value as 0.003 for testing the hypotheses given in part (d). What is the conclusion of the test in the context of this study? (h) The authors hypothesize that skin cancers are more prevalent on the left because of the sunlight coming in through car windows. (Windows protect against UVB rays but not UVA rays.) Do the data in this study support a conclusion that more melanomas occur on the left side because of increased exposure to sunlight on that side for drivers?

A study \(^{20}\) conducted in June 2015 examines ownership of tablet computers by US adults. A random sample of 959 people were surveyed, and we are told that 197 of the 455 men own a tablet and 235 of the 504 women own a tablet. We want to test whether the survey results provide evidence of a difference in the proportion owning a tablet between men and women. (a) State the null and alternative hypotheses, and define the parameters. (b) Give the notation and value of the sample statistic. In the sample, which group has higher tablet ownership: men or women? (c) Use StatKey or other technology to find the pvalue.

Exercises 4.59 to 4.64 give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p>0.5\) Sample data: \(\hat{p}=30 / 50=0.60\) with \(n=50\)

For each situation described, indicate whether it makes more sense to use a relatively large significance level (such as \(\alpha=0.10\) ) or a relatively small significance level (such as \(\alpha=0.01\) ). Testing a new drug with potentially dangerous side effects to see if it is significantly better than the drug currently in use. If it is found to be more effective, it will be prescribed to millions of people.

You roll a die 60 times and record the sample proportion of 5 's, and you want to test whether the die is biased to give more 5 's than a fair die would ordinarily give. To find the p-value for your sample data, you create a randomization distribution of proportions of 5 's in many simulated samples of size 60 with a fair die. (a) State the null and alternative hypotheses. (b) Where will the center of the distribution be? Why? (c) Give an example of a sample proportion for which the number of 5 's obtained is less than what you would expect in a fair die. (d) Will your answer to part (c) lie on the left or the right of the center of the randomization distribution? (e) To find the p-value for your answer to part (c), would you look at the left, right, or both tails? (f) For your answer in part (c), can you say anything about the size of the p-value?

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