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Do You Own a Smartphone? A study \(^{19}\) conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and the study shows that 688 of the 989 men own a smartphone and 671 of the 1012 women own a smartphone. We want to test whether the survey results provide evidence of a difference in the proportion owning a smartphone between men and women. (a) State the null and alternative hypotheses, and define the parameters. (b) Give the notation and value of the sample statistic. In the sample, which group has higher smartphone ownership: men or women? (c) Use StatKey or other technology to find the pvalue.

Short Answer

Expert verified
The null hypothesis (\(H_0\)) is that there is no difference between the proportion of men and women owning a smartphone. The alternative hypothesis (\(H_a\)) is that there is a difference. The sample proportions are approximately 0.696 for men and 0.663 for women, with men having a higher rate of ownership. Using a statistical software tool, the P-value can be computed providing evidence against the null hypothesis.

Step by step solution

01

Formulate the Hypotheses

The null hypothesis (\(H_0\)) refers to the situation where there is no difference in the proportion of men and women owning a smartphone. The alternative hypothesis (\(H_a\)) refers to there being a difference in the proportions. So, \(H_0: p_m = p_w\) and \(H_a: p_m ≠ p_w\) where \(p_m\) is the proportion of men that own a smartphone and \(p_w\) is the proportion of women that own a smartphone.
02

Calculate the Sample Statistics

The sample proportions for men and women owning a smartphone are computed. For men, it’s 688 out of 989, giving a sample statistic of approximately 0.696. For women, it’s 671 out of 1012, giving a sample statistic of approximately 0.663. The notation to represent these would be \(\hat{p}_m\) for men and \(\hat{p}_w\) for women. Comparing these, it can be observed that men have a higher smartphone ownership than women in the sample.
03

Calculate the P-value

To calculate the P-value, a statistical software or calculator would be needed. The function in the software would require the sample size and the number of successful outcomes for each group. In this case, the sample sizes are 989 and 1012 for men and women respectively, and the successful outcomes (owning a smartphone) are 688 and 671. After inputting the appropriate values, the P-value obtained gives the strength of evidence against the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
Understanding the null and alternative hypotheses is crucial to hypothesis testing in statistics. In the context of our exercise, the null hypothesis (\(H_0\)) is that there is no significant difference in the proportions of men and women owning smartphones. Mathematically, this is expressed as \(p_m = p_w\), where \(p_m\) and \(p_w\) are the population proportions of smartphone ownership among men and women, respectively. The alternative hypothesis (\(H_a\)), on the other hand, posits that there is a difference in these proportions (\(p_m eq p_w\)).

It might seem counterintuitive, but in hypothesis testing, we actually assume the null hypothesis is true and then look for evidence to disprove it. If sufficient evidence is found (usually through calculating the p-value), we might reject the null hypothesis in favor of the alternative. It's a bit like a courtroom where the null hypothesis is 'innocent until proven guilty'.
Sample Proportion
The sample proportion is a statistic that estimates the equivalent population parameter. In our example, the sample proportion is the number of individuals with a certain characteristic (owning a smartphone) divided by the total number of individuals in the sample. To denote the sample proportions, we use \(\hat{p}\).

Here's how you would calculate it: For men, \(\hat{p}_m = \frac{688}{989}\), and for women, \(\hat{p}_w = \frac{671}{1012}\). When working with sample proportions, it's important to understand that these are only estimations of the true population proportions. The sample values can help us infer about the population, but they themselves are prone to varying from one sample to another—a concept known as sampling variability. Furthermore, the accuracy of the sample proportion as an estimator depends on the sample size and how representative the sample is of the population.
P-value Calculation
The p-value is a crucial component in hypothesis testing, as it helps determine the strength of the evidence against the null hypothesis. It's calculated by assessing the probability of obtaining sample results as extreme as the ones observed if the null hypothesis were true.

In our smartphone ownership example, to find the p-value, we would need to use statistical software or a calculator. The software would take into account both the observed sample proportions and the sizes of the samples. Generally, if this calculated p-value is less than a predetermined significance level (often \(\alpha = 0.05\)), we reject the null hypothesis. A low p-value indicates that the observed data would be highly unlikely if the null hypothesis were true, suggesting that the alternative hypothesis may be a more plausible explanation. Conversely, a high p-value implies that the observed data are consistent with a true null hypothesis, so we wouldn't reject \(H_0\) in this scenario.

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Most popular questions from this chapter

It is well established that exercise is beneficial for our bodies. Recent studies appear to indicate that exercise can also do wonders for our brains, or, at least, the brains of mice. In a randomized experiment, one group of mice was given access to a running wheel while a second group of mice was kept sedentary. According to an article describing the study, "The brains of mice and rats that were allowed to run on wheels pulsed with vigorous, newly born neurons, and those animals then breezed through mazes and other tests of rodent IQ"9 compared to the sedentary mice. Studies are examining the reasons for these beneficial effects of exercise on rodent (and perhaps human) intelligence. High levels of BMP (bonemorphogenetic protein) in the brain seem to make stem cells less active, which makes the brain slower and less nimble. Exercise seems to reduce the level of BMP in the brain. Additionally, exercise increases a brain protein called noggin, which improves the brain's ability. Indeed, large doses of noggin turned mice into "little mouse geniuses," according to Dr. Kessler, one of the lead authors of the study. While research is ongoing in determining how strong the effects are, all evidence points to the fact that exercise is good for the brain. Several tests involving these studies are described. In each case, define the relevant parameters and state the null and alternative hypotheses. (a) Testing to see if there is evidence that mice allowed to exercise have lower levels of BMP in the brain on average than sedentary mice. (b) Testing to see if there is evidence that mice allowed to exercise have higher levels of noggin in the brain on average than sedentary mice. (c) Testing to see if there is evidence of a negative correlation between the level of BMP and the level of noggin in the brains of mice.

Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \mu=15\) vs \(H_{a}: \mu \neq 15\) (a) \(95 \%\) confidence interval for \(\mu: \quad 13.9\) to 16.2 (b) \(95 \%\) confidence interval for \(\mu: \quad 12.7\) to 14.8 (c) \(90 \%\) confidence interval for \(\mu: \quad 13.5\) to 16.5

An article noted that it may be possible to accurately predict which way a penalty-shot kicker in soccer will direct his shot. \({ }^{27}\) The study finds that certain types of body language by a soccer player \(-\) called "tells"-can be accurately read to predict whether the ball will go left or right. For a given body movement leading up to the kick, the question is whether there is strong evidence that the proportion of kicks that go right is significantly different from one-half. (a) What are the null and alternative hypotheses in this situation? (b) If sample results for one type of body movement give a p-value of 0.3184 , what is the conclusion of the test? Should a goalie learn to distinguish this movement? (c) If sample results for a different type of body movement give a p-value of \(0.0006,\) what is the conclusion of the test? Should a goalie learn to distinguish this movement?

Income East and West of the Mississippi For a random sample of households in the US, we record annual household income, whether the location is east or west of the Mississippi River, and number of children. We are interested in determining whether there is a difference in average household income between those east of the Mississippi and those west of the Mississippi. (a) Define the relevant parameter(s) and state the null and alternative hypotheses. (b) What statistic(s) from the sample would we use to estimate the difference?

Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p<0.5\) Sample data: \(\hat{p}=38 / 100=0.38\) with \(n=100\)

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