/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 157 Hypotheses for a statistical tes... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \mu=15\) vs \(H_{a}: \mu \neq 15\) (a) \(95 \%\) confidence interval for \(\mu: \quad 13.9\) to 16.2 (b) \(95 \%\) confidence interval for \(\mu: \quad 12.7\) to 14.8 (c) \(90 \%\) confidence interval for \(\mu: \quad 13.5\) to 16.5

Short Answer

Expert verified
For samples (a) and (c), we do not reject the null hypothesis at 5% and 10% significance levels respectively while for sample (b), we reject the null hypothesis at a 5% significance level.

Step by step solution

01

Analyze the first confidence interval

For part (a), the confidence interval ranges from 13.9 to 16.2. Since the hypothesized population mean of 15 lies within this interval, we do not reject the null hypothesis at a 5% significance level (we are using a 95% confidence interval).
02

Analyze the second confidence interval

For part (b), the confidence interval ranges from 12.7 to 14.8. The hypothesized population mean of 15 does not fall within this interval, so we reject the null hypothesis at a 5% significance level.
03

Analyze the third confidence interval

For part (c), the confidence interval ranges from 13.5 to 16.5. Since the hypothesized population mean of 15 is within this range, we do not reject the null hypothesis at a 10% significance level (because we are using a 90% confidence interval).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values, derived from the sample data, that is likely to contain the population parameter of interest. When we calculate, for example, a 95% confidence interval, we are saying that we are 95% confident that the true population mean falls within this range.

In the context of the exercise, the confidence intervals are given for the population mean \( \mu \). When the sample mean falls within the confidence interval, such as in parts (a) and (c), we do not have sufficient evidence to reject the null hypothesis. This is because the hypothesized value of \( \mu=15 \) is within the range that we're 95% or 90% confident contains the true mean.

However, for part (b), the hypothesized mean does not fall within the 95% confidence interval. This suggests that the true mean is likely different from 15, and we would reject the null hypothesis in this scenario. Confidence intervals are an essential part of statistical hypothesis testing because they provide a range of plausible values for the parameter, allowing for a decision on the null hypothesis based on the data at hand.
Null Hypothesis
The null hypothesis, denoted as \( H_0 \), is a statement that there is no effect or no difference, and it generally represents a skeptical perspective or a claim to be tested. In hypothesis testing, we seek to determine whether the evidence suggests that we should reject this null hypothesis in favor of an alternative hypothesis, denoted as \( H_a \).

For instance, in the given exercise, \( H_0: \mu=15 \) asserts that the population mean is 15. The alternative hypothesis \( H_a: \mu eq 15 \) posits that the population mean is not 15. The null hypothesis is the starting assumption for the test, and the hypothesis testing procedure examines whether the data collected provides enough evidence to conclude if the null hypothesis can be rejected or not.

As we can see from the solutions, a confidence interval that does not include the value stated in the null hypothesis (as in part (b)) is an indicator that the null hypothesis may not hold. Conversely, when the confidence interval includes the null hypothesis value, we lack evidence to reject it (as seen in parts (a) and (c)).
Significance Level
The significance level, often denoted by \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true, known as a Type I error. It represents the researcher's tolerance for such errors and is a critical value in hypothesis testing that helps determine the threshold for rejecting the null hypothesis.

Common significance levels are 5% (0.05), 1% (0.01), or 10% (0.10), which corresponds inversely to 95%, 99%, and 90% confidence levels, respectively. Demonstrated in our exercise, when we reject the null hypothesis for part (b), it's because the 95% confidence interval does not include the hypothesized mean of 15, thus surpassing the 5% significance level criterion for rejection.

Alternatively, for parts (a) and (c), the hypothesized mean lies within the confidence intervals, indicating that we do not have significant evidence at the 5% and 10% levels, respectively, to reject the null hypothesis. Deciding on the appropriate significance level is a crucial step in the design of an experiment or study as it can influence the conclusions drawn from the statistical test.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using the definition of a p-value, explain why the area in the tail of a randomization distribution is used to compute a p-value.

The null and alternative hypotheses for a test are given as well as some information about the actual sample(s) and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered. In addition, indicate whether the test is a left-tail test, a right-tail test, or a twotailed test. Hypotheses: \(H_{0}: \mu=10\) vs \(H_{a}: \mu>10\) Sample: \(\bar{x}=12, s=3.8, n=40\)

Indicate whether it is best assessed by using a confidence interval or a hypothesis test or whether statistical inference is not relevant to answer it. (a) What proportion of people using a public restroom wash their hands after going to the bathroom? (b) On average, how much more do adults who played sports in high school exercise than adults who did not play sports in high school? (c) In \(2010,\) what percent of the US Senate voted to confirm Elena Kagan as a member of the Supreme Court? (d) What is the average daily calorie intake of 20 year-old males?

Influencing Voters Exercise 4.39 on page 272 describes a possible study to see if there is evidence that a recorded phone call is more effective than a mailed flyer in getting voters to support a certain candidate. The study assumes a significance level of \(\alpha=0.05\) (a) What is the conclusion in the context of thisstudy if the p-value for the test is \(0.027 ?\) (b) In the conclusion in part (a), which type of error are we possibly making: Type I or Type II? Describe what that type of error means in this situation. (c) What is the conclusion if the p-value for the test is \(0.18 ?\)

Scientists studying lion attacks on humans in Tanzania \(^{32}\) found that 95 lion attacks happened between \(6 \mathrm{pm}\) and \(10 \mathrm{pm}\) within either five days before a full moon or five days after a full moon. Of these, 71 happened during the five days after the full moon while the other 24 happened during the five days before the full moon. Does this sample of lion attacks provide evidence that attacks are more likely after a full moon? In other words, is there evidence that attacks are not equally split between the two five-day periods? Use StatKey or other technology to find the p-value, and be sure to show all details of the test. (Note that this is a test for a single proportion since the data come from one sample.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.