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91Ó°ÊÓ

Indicate whether the five number summary corresponds most likely to a distribution that is skewed to the left, skewed to the right, or symmetric. (100,110,115,160,220)

Short Answer

Expert verified
The distribution of the five number summary (100,110,115,160,220) is skewed to the right.

Step by step solution

01

Calculate Mean

Firstly, calculate the mean which is the sum of the given numbers (100,110,115,160,220) divided by the number of elements, which in this case is 5. The mean is: \((100+110+115+160+220)/5 = 141\).
02

Find Median

The median is given in the five-number summary. It is the middle number, which in this case is 115.
03

Identify Skewness

Now, compare the calculated mean (141) to the given median (115). Since the mean is greater than the median, you can determine that the distribution is skewed to the right.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Skewed Distribution
A skewed distribution is one in which the values of a dataset are not symmetrically distributed around the mean. The direction of the skewness is determined by the side of the distribution that has the longer tail. If the tail stretches out to the right, more towards the higher values, the distribution is said to be right-skewed or positively skewed. Conversely, if the tail extends to the left, more towards the lower values, it's considered left-skewed or negatively skewed.

In the context of the exercise, the five number summary provided: (100,110,115,160,220), hints at the distribution's shape. When a distribution is skewed to the right, the mean will typically be higher than the median because the longer tail of high-value outliers pulls the mean upwards. This is precisely what we observe in the step-by-step solution, where the mean is calculated to be 141, while the median, being the middle value, is identified as 115.
Mean and Median Comparison
The mean and median are both measures of central tendency, but they behave differently in the presence of skewed data. The mean is the arithmetic average, sensitive to extreme values or outliers. It's calculated by adding up all the numbers in a dataset and dividing by the count of those numbers. In contrast, the median is the middle value when the numbers are arranged in order, less affected by outliers or extreme values since it purely depends on the order of data points.

Comparing the mean and median can provide insight into the distribution's skewness. If the mean is significantly higher than the median, as in the exercise solution where the mean is 141 and the median is 115, it suggests a right-skewed distribution. Similarly, if the mean is lower than the median, it usually indicates a left-skewed distribution. This comparison is a quick and reliable method to gauge the asymmetry of a dataset.
Descriptive Statistics
Descriptive statistics summarize and describe the main features of a dataset. They offer a way to present large amounts of data in a simple and understandable format. The five number summary is a form of descriptive statistics that includes five critical values: the minimum, first quartile (Q1), median, third quartile (Q3), and maximum. These values give a quick overview of the data structure, showing its spread and central tendency.

The five number summary is instrumental in identifying the distribution's shape by illuminating the data's center, spread, and skewness. For instance, large gaps between quartiles and extremes can signal the presence of skewness. In our exercise, the five number summary of (100,110,115,160,220) suggests right-skewness — the median resides closer to the lower end of the dataset, and there's a significant jump from the third quartile (160) to the maximum (220). Descriptive statistics, such as the five number summary, are foundational in understanding the underlying characteristics of data in various fields, from academia to industry applications.

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Most popular questions from this chapter

In Exercise 2.120 on page \(92,\) we discuss a study in which the Nielsen Company measured connection speeds on home computers in nine different countries in order to determine whether connection speed affects the amount of time consumers spend online. \(^{69}\) Table 2.29 shows the percent of Internet users with a "fast" connection (defined as \(2 \mathrm{Mb}\) or faster) and the average amount of time spent online, defined as total hours connected to the Web from a home computer during the month of February 2011. The data are also available in the dataset GlobalInternet. (a) What would a positive association mean between these two variables? Explain why a positive relationship might make sense in this context. (b) What would a negative association mean between these two variables? Explain why a negative relationship might make sense in this context. $$ \begin{array}{lcc} \hline \text { Country } & \begin{array}{c} \text { Percent Fast } \\ \text { Connection } \end{array} & \begin{array}{l} \text { Hours } \\ \text { Online } \end{array} \\ \hline \text { Switzerland } & 88 & 20.18 \\ \text { United States } & 70 & 26.26 \\ \text { Germany } & 72 & 28.04 \\ \text { Australia } & 64 & 23.02 \\ \text { United Kingdom } & 75 & 28.48 \\ \text { France } & 70 & 27.49 \\ \text { Spain } & 69 & 26.97 \\ \text { Italy } & 64 & 23.59 \\ \text { Brazil } & 21 & 31.58 \\ \hline \end{array} $$ (c) Make a scatterplot of the data, using connection speed as the explanatory variable and time online as the response variable. Is there a positive or negative relationship? Are there any outliers? If so, indicate the country associated with each outlier and describe the characteristics that make it an outlier for the scatterplot. (d) If we eliminate any outliers from the scatterplot, does it appear that the remaining countries have a positive or negative relationship between these two variables? (e) Use technology to compute the correlation. Is the correlation affected by the outliers? (f) Can we conclude that a faster connection speed causes people to spend more time online?

Levels of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) in the atmosphere are rising rapidly, far above any levels ever before recorded. Levels were around 278 parts per million in 1800 , before the Industrial Age, and had never, in the hundreds of thousands of years before that, gone above 300 ppm. Levels are now over 400 ppm. Table 2.31 shows the rapid rise of \(\mathrm{CO}_{2}\) concentrations over the 50 years from \(1960-2010\), also available in CarbonDioxide. \(^{73}\) We can use this information to predict \(\mathrm{CO}_{2}\) levels in different years. (a) What is the explanatory variable? What is the response variable? (b) Draw a scatterplot of the data. Does there appear to be a linear relationship in the data? (c) Use technology to find the correlation between year and \(\mathrm{CO}_{2}\) levels. Does the value of the correlation support your answer to part (b)? (d) Use technology to calculate the regression line to predict \(\mathrm{CO}_{2}\) from year. (e) Interpret the slope of the regression line, in terms of carbon dioxide concentrations. (f) What is the intercept of the line? Does it make sense in context? Why or why not? (g) Use the regression line to predict the \(\mathrm{CO}_{2}\) level in \(2003 .\) In \(2020 .\) (h) Find the residual for 2010 . Table 2.31 Concentration of carbon dioxide in the atmosphere $$\begin{array}{lc}\hline \text { Year } & \mathrm{CO}_{2} \\ \hline 1960 & 316.91 \\ 1965 & 320.04 \\\1970 & 325.68 \\ 1975 & 331.08 \\\1980 & 338.68 \\\1985 & 345.87 \\\1990 & 354.16 \\ 1995 & 360.62 \\\2000 & 369.40 \\ 2005 & 379.76 \\\2010 & 389.78 \\ \hline\end{array}$$

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Give the correct notation for the mean. The average number of text messages sent in a day was 67 , in a sample of US smartphone users ages \(18-24\), according to a survey conducted by Experian. \(^{26}\)

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