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A sample of \(n=10,000(x, y)\) pairs resulted in \(r=.022 .\) Test \(H_{0}: \rho=0\) versus \(H_{a}: \rho \neq 0\) at significance level .05. Is the result statistically significant? Comment on the practical significance of your analysis.

Short Answer

Expert verified
Without having computed the exact value of t, it can't be stated definitively whether the correlation is statistically significant. The p-value is what would determine this, comparing it to our 0.05 significance level. If p < 0.05, then it is statistically significant, else it's not. But, in practice, such a small correlation coefficient (r = 0.022) is very weak and unlikely to be of practical significance, even if it were to be statistically significant.

Step by step solution

01

Calculate Test Statistic

Let's calculate the value of the test statistic (t) using the formula: t = r * sqrt((n-2) / (1 - r^2)) = 0.022*sqrt((10000-2) / (1-0.022^2)).
02

Calculate Critical t-value

With n = 10,000, the degrees of freedom are (n-2) = 9998. Using a t-table and a significance level of 0.05, the critical values for a two-tailed test are approximately -1.96 and +1.96 (as for large degrees of freedom, the t-distribution is close to the standard normal distribution).
03

Compare Test Statistic and Critical Value

We compare the absolute value of the test statistic (t) you calculated in Step 1 to the critical t-value obtained from the t-table to make a decision about the null hypothesis. If the absolute value of t is greater than the critical value, we reject the null hypothesis (H0). If the absolute value of t is less than the critical value, we fail to reject the null hypothesis (H0).
04

Practical Significance

Even if the result is statistically significant, whether it has practical significance is another question. The actual value of r (=0.022) is a very weak correlation, which suggests it may not have strong practical significance even if it is statistically significant. The final determination of practical significance would depend upon the particular context and application, taking into account also the large sample size used.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient
The correlation coefficient, symbolized as \( r \), is a key concept in statistics that measures the degree of relationship between two variables. It ranges from -1 to 1.
  • When \( r = 1 \), it implies a perfect positive linear relationship.
  • If \( r = 0 \), there is no linear relationship.
  • A value of \( r = -1 \) shows a perfect negative linear relationship.
In the context of our exercise, the correlation coefficient is \( r = 0.022 \).
This is quite close to 0, indicating an exceedingly weak linear relationship between the variables \( x \) and \( y \).
Calculating \( r \) gives us a first glimpse into how the data behaves but should be interpreted cautiously, especially in large datasets.
It's vital to remember that correlation does not imply causation.
Even though there is a statistically significant value of \( r \), the weak correlation points towards minimal association in practical terms.
Null Hypothesis Testing
Null hypothesis testing is an essential statistical procedure used to decide if a result can be attributed to chance or some actual effect.
The null hypothesis (\( H_0 \)) suggests that there is no effect or no difference; in our case, \( \rho = 0 \).
The alternative hypothesis (\( H_a \)) posits that there is an effect or a difference; here, \( \rho eq 0 \).
After defining these hypotheses, we use a selected statistic to test if evidence is strong enough to reject \( H_0 \).
In our example, we conducted a hypothesis test using \( r \) and resulted in calculating the \( t \)-statistic.
The goal was to determine if the observed correlation could happen by random chance.
By using a significance level of 0.05, we set the standard threshold for accepting or rejecting \( H_0 \). This means we are 95% confident in our decision, minimizing Type I errors.
t-distribution
The t-distribution is a probability distribution that is used in hypothesis testing when sample sizes are small and/or when the population standard deviation is unknown.
In this exercise, the t-distribution was used to determine the critical t-value for a sample size of 10,000 (df = 9998).
  • As the sample size increases, the t-distribution becomes more like the normal distribution.
  • With large degrees of freedom, such as 9998, the t-distribution closely resembles a standard normal distribution, simplifying the process of locating critical values.
Here, critical values were approximately \(-1.96\) and \(+1.96\) for a two-tailed test.
An important aspect of the t-distribution is how it provides a margin for understanding sampling errors, offering a more accurate test in hypothesis testing with fewer assumptions than a normal distribution.
Using the t-distribution makes our results more reliable and valid in interpreting significance levels.
Practical Significance
Practical significance refers to the real-world importance or relevance of a statistical finding.
Unlike statistical significance, which simply indicates whether an effect exists, practical significance assesses the magnitude and utility of that effect.
In our given problem, the correlation coefficient of \( 0.022 \) is statistically significant due to the large sample size, but offers minimal practical significance.
Role of context: Practical significance is determined by the context and application.
Even if data shows statistical significance, it may not translate to impactful or meaningful changes in practical scenarios.
Consider the context: larger sample sizes can make trivial effects appear statistically significant, so it's crucial to evaluate outcomes thoughtfully.
Always balance between statistical results and their actual impact or utility in real-world applications.

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Most popular questions from this chapter

The data of Exercise 13.25 milk temperature and \(y=\) milk \(\mathrm{pH},\) yield $$ \begin{array}{lrlr} n=16 & \bar{x} & =42.375 & S_{x x} & =7325.75 \\ b & =-.00730608 & a=6.843345 & s_{e}=.0356 \end{array} $$ a. Obtain a \(95 \%\) confidence interval for \(\alpha+\beta(40)\), the mean milk \(\mathrm{pH}\) when the milk temperature is \(40^{\circ} \mathrm{C}\) b. Calculate a \(99 \%\) confidence interval for the mean milk \(\mathrm{pH}\) when the milk temperature is \(35^{\circ} \mathrm{C}\). c. Would you recommend using the data to calculate a \(95 \%\) confidence interval for the mean \(\mathrm{pH}\) when the temperature is \(90^{\circ} \mathrm{C}\) ? Why or why not?

Explain the difference between \(r\) and \(\rho\).

A simple linear regression model was used to describe the relationship between \(y=\) hardness of molded plastic and \(x=\) amount of time elapsed since the end of the molding process. Summary quantities included \(n=\) \(15,\) SSResid \(=1235.470,\) and \(\mathrm{SSTo}=25,321.368 .\) a. Calculate a point estimate of \(\sigma .\) On how many degrees of freedom is the estimate based? b. What percentage of observed variation in hardness can be explained by the simple linear regression model relationship between hardness and elapsed time?

The authors of the paper "Weight-Bearing Activity during Youth Is a More Important Factor for Peak Bone Mass than Calcium Intake" (Journal of Bone and Mineral Research \([1994] .1089-1096)\) studied a number of variables they thought might be related to bone mineral density (BMD). The accompanying data on \(x=\) weight at age 13 and \(y=\) bone mineral density at age 27 are consistent with summary quantities for women given in the paper. A simple linear regression model was used to describe the relationship between weight at age 13 and \(\mathrm{BMD}\) at age 27\. For this data: $$ a=0.558 \quad b=0.009 \quad n=15 $$ SSTo \(=0.356 \quad\) SSResid \(=0.313\) a. What percentage of observed variation in \(\mathrm{BMD}\) at age 27 can be explained by the simple linear regression model? b. Give a point estimate of \(\sigma\) and interpret this estimate. c. Give an estimate of the average change in BMD associated with a \(1 \mathrm{~kg}\) increase in weight at age 13 . d. Compute a point estimate of the mean BMD at age 27 for women whose age 13 weight was \(60 \mathrm{~kg}\).

Give a brief answer, comment, or explanation for each of the following. a. What is the difference between \(e_{1}, e_{2}, \ldots, e_{n}\) and the \(n\) residuals? b. The simple linear regression model states that \(y=\alpha+\beta x .\) c. Does it make sense to test hypotheses about \(b\) ? d. SSResid is always positive. e. A student reported that a data set consisting of \(n=6\) observations yielded residuals \(2,0,5,3,0,\) and 1 from the least-squares line. f. A research report included the following summary quantities obtained from a simple linear regression analysis: \(\sum(y-\bar{y})^{2}=615 \quad \sum(y-\hat{y})^{2}=731\)

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