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For the following pairs, indicate which do not comply with the rules for setting up hypotheses, and explain why: a. \(H_{0}: \mu=15, H_{a}: \mu=15\) b. \(H_{0}: p=.4, H_{a}: p>.6\) c. \(H_{0}: \mu=123, H_{a}: \mu<123\) d. \(H_{0}: \mu=123, H_{d}: \mu=125\) e. \(\quad H_{0}: \hat{p}=.1, H_{a}: \hat{p} \neq .1\)

Short Answer

Expert verified
Pairs a, d, and e do not comply with the rules for setting up hypotheses. Pair a violates rule because null and alternative hypotheses are the same. Pair d violates rule because the symbol of alternative hypothesis is not properly written. Pair e violates rule because estimative \(\hat{p}\) is used instead of the parameter, p.

Step by step solution

01

Analyze the first pair: \(H_{0}: \mu = 15, H_{a}: \mu = 15\)

This pair does not comply with the hypothesis testing rules because the null and alternative hypotheses are the same, which means that there is no effect to test.
02

Analyze the second pair: \(H_{0}: p = .4, H_{a}: p > .6\)

This pair complies with the hypothesis testing rules. The null hypothesis represents the status quo (the probability is 0.4), while the alternative hypothesis suggests a different state (the probability is greater than 0.6).
03

Analyze the third pair: \(H_{0}: \mu = 123, H_{a}: \mu < 123\)

This pair complies with the hypothesis testing rules. The null hypothesis represents the status quo (the mean is 123), while the alternative hypothesis suggests a different state (the mean is less than 123).
04

Analyze the fourth pair: \(H_{0}: \mu = 123, H_{d}: \mu = 125\)

This pair does not comply with the hypothesis testing rules because the alternative hypothesis is denoted by \(H_{d}\) instead of \(H_{a}\), which is the standard notational convention.
05

Analyze the fifth pair: \(H_{0}: \hat{p} = .1, H_{a}: \hat{p} \neq .1\)

This pair does not comply with the hypothesis testing rules. The estimative, \(\hat{p}\), is used instead of parameter, p, which should be used in the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, often denoted as \(H_0\), is a statement in hypothesis testing that assumes no effect or no difference in a given situation. It's like saying "nothing is happening here," or "there is no change." For example, if you're testing whether a new drug is effective, the null hypothesis would state that this drug has no effect compared to a placebo.
Understanding the null hypothesis is crucial because it serves as the baseline against which the alternative hypothesis is tested. In many cases, researchers seek to reject the null hypothesis to provide evidence that the alternative hypothesis is more likely correct.
Remember, in hypothesis testing, we never "prove" the null hypothesis. We either reject it or fail to reject it, which means we found enough evidence against it, or we didn't.
  • The null hypothesis is commonly expressed as \(H_0: \mu = \text{value}\) or \(H_0: p = \text{value}\).
  • It represents the status quo or a baseline assumption.
  • Rejection of \(H_0\) implies supporting the alternative hypothesis.
Alternative Hypothesis
The alternative hypothesis, denoted as \(H_a\) or sometimes \(H_1\), represents what the researcher aims to prove. It suggests that there is an effect or a difference, challenging the initial claim made by the null hypothesis.
In research, we're often motivated by the alternative hypothesis because it suggests new insights or findings. For example, in a drug test study, the alternative hypothesis would state that the new drug does, indeed, have an effect compared to a placebo.
If the evidence supports the alternative hypothesis, it can lead to new scientific understandings or advances.
  • The alternative hypothesis can take various forms like \(H_a: \mu eq \text{value}\), \(H_a: \mu > \text{value}\), or \(H_a: \mu < \text{value}\).
  • It suggests there is a significant effect or difference present.
  • The goal of many tests is to determine if there's enough evidence to support \(H_a\) over \(H_0\).
Statistical Hypothesis
In hypothesis testing, a statistical hypothesis is a claim or an assumption about a population parameter that we aim to test. It usually comes in pairs: the null hypothesis (\(H_0\)) and the alternative hypothesis (\(H_a\)).
These paired hypotheses provide a framework for conducting statistical tests and drawing conclusions about the data. The null hypothesis states a specific condition or standard, while the alternative hypothesis contradicts that condition, proposing a new direction or finding.
Statistical hypotheses are crucial for ensuring that research findings are backed by solid evidence and sound statistical reasoning.
  • Statistical hypotheses provide a structured method for problem-solving.
  • They guide the decision-making process in hypothesis testing.
  • Clear definition of both \(H_0\) and \(H_a\) is essential for valid conclusions.
Notation in Hypothesis Testing
Notation in hypothesis testing is vital for clear communication of the statistical test being conducted. In the exercise above, correct notation helps identify what is being tested and how the hypotheses are structured.
Here are some standard notations used:
  • \(H_0\) represents the null hypothesis.
  • \(H_a\) or \(H_1\) indicates the alternative hypothesis.
  • \(\mu\) is used for the population mean.
  • \(p\) signifies the population proportion.
Using these notations correctly is critical. For instance, in the step-by-step solution, pairs like \(H_0: \mu = 15\) and \(H_a: \mu = 15\) failed because they didn't express a different condition; thus, no testing could be performed. Also, using incorrect symbols or notations like \(H_d\) instead of \(H_a\) can render hypotheses invalid.
Accurate notation ensures that your hypotheses are properly constructed and that statistical tests can be correctly interpreted and performed.

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Most popular questions from this chapter

Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most \(150^{\circ} \mathrm{F}\), there will be no negative effects on the river's ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above \(150^{\circ} \mathrm{F}\), a scientist will take 50 water samples at randomly selected times and will record the water temperature of each sample. She will then use a \(z\) statistic $$ z=\frac{\bar{x}-150}{\frac{\sigma}{\sqrt{n}}} $$ to decide between the hypotheses \(H_{0}: \mu=150\) and \(H_{a}: \mu>150,\) where \(\mu\) is the mean temperature of discharged water. Assume that \(\sigma\) is known to be 10 . a. Explain why use of the \(z\) statistic is appropriate in this setting. b. Describe Type I and Type II errors in this context. \(c\). The rejection of \(H_{0}\) when \(z \geq 1.8\) corresponds to what value of \(\alpha\) ? (That is, what is the area under the \(z\) curve to the right of \(1.8 ?\) ) d. Suppose that the actual value for \(\mu\) is 153 and that \(H_{0}\) is to be rejected if \(z \geq 1.8 .\) Draw a sketch (similar to that of Figure 10.5 ) of the sampling distribution of \(\bar{x},\) and shade the region that would represent \(\beta\), the probability of making a Type II error. e. For the hypotheses and test procedure described, compute the value of \(\beta\) when \(\mu=153\). f. For the hypotheses and test procedure described, what is the value of \(\beta\) if \(\mu=160\) ? g. What would be the conclusion of the test if \(H_{0}\) is rejected when \(z \geq 1.8\) and \(\bar{x}=152.4\) ? What type of error might have been made in reaching this conclusion?

Many consumers pay careful attention to stated nutritional contents on packaged foods when making purchases. It is therefore important that the information on packages be accurate. A random sample of \(n=12\) frozen dinners of a certain type was selected from production during a particular period, and the calorie content of each one was determined. (This determination entails destroying the product, so a census would certainly not be desirable!) Here are the resulting observations, along with a boxplot and normal probability plot: \(\begin{array}{llllllll}255 & 244 & 239 & 242 & 265 & 245 & 259 & 248\end{array}\) \(\begin{array}{llll}225 & 226 & 251 & 233\end{array}\) a. Is it reasonable to test hypotheses about mean calorie content \(\mu\) by using a \(t\) test? Explain why or why not. b. The stated calorie content is \(240 .\) Does the boxplot suggest that true average content differs from the stated value? Explain your reasoning. c. Carry out a formal test of the hypotheses suggested in Part (b).

The Economist collects data each year on the price of a Big Mac in various countries around the world. The price of a Big Mac for a sample of McDonald's restaurants in Europe in May 2009 resulted in the following Big Mac prices (after conversion to U.S. dollars): \(\begin{array}{llllll}3.80 & 5.89 & 4.92 & 3.88 & 2.65 & 5.57\end{array}\) \(\begin{array}{ll}6.39 & 3.24\end{array}\) The mean price of a Big Mac in the U.S. in May 2009 was \(\$ 3.57\). For purposes of this exercise, assume it is reasonable to regard the sample as representative of European McDonald's restaurants. Does the sample provide convincing evidence that the mean May 2009 price of a Big Mac in Europe is greater than the reported U.S. price? Test the relevant hypotheses using \(\alpha=.05\).

According to a survey of 1000 adult Americans conducted by Opinion Research Corporation, 210 of those surveyed said playing the lottery would be the most practical way for them to accumulate \(\$ 200,000\) in net wealth in their lifetime ("One in Five Believe Path to Riches Is the Lottery," San Luis Obispo Tribune, January 11, 2006 ). Although the article does not describe how the sample was selected, for purposes of this exercise, assume that the sample can be regarded as a random sample of adult Americans. Is there convincing evidence that more than \(20 \%\) of adult Americans believe that playing the lottery is the best strategy for accumulating \(\$ 200,000\) in net wealth?

The article "Theaters Losing Out to Living Rooms" (San Luis Obispo Tribune, June 17,2005\()\) states that movie attendance declined in \(2005 .\) The Associated Press found that 730 of 1000 randomly selected adult Americans preferred to watch movies at home rather than at a movie theater. Is there convincing evidence that the majority of adult Americans prefer to watch movies at home? Test the relevant hypotheses using a .05 significance level.

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