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Percentages of public school students in fourth grade in 1996 and in eighth grade in 2000 who were at or above the proficient level in mathematics were given in the article 鈥淢ixed Progress in Math鈥 (USA Today, August 3, 2001) for eight western states: $$ \begin{array}{lcc} \text { State } & (1996) & \text { (2000) } \\ \hline \text { Arizona } & 15 & 21 \\ \text { California } & 11 & 18 \\ \text { Hawaii } & 16 & 16 \\ \text { Montana } & 22 & 37 \\ \text { New Mexico } & 13 & 13 \\ \text { Oregon } & 21 & 32 \\ \text { Utah } & 23 & 26 \\ \text { Wyoming } & 19 & 25 \\ \hline \end{array} $$ a. Construct a scatterplot, and comment on any interesting features. b. Find the equation of the least-squares line that summarizes the relationship between \(x=1996\) fourth-grade math proficiency percentage and \(y=2000\) eighth-grade math proficiency percentage. c. Nevada, a western state not included in the data set, had a 1996 fourth- grade math proficiency of \(14 \%\). What would you predict for Nevada's 2000 eighth-grade math proficiency percentage? How does your prediction compare to the actual eighth-grade value of 20 for Nevada?

Short Answer

Expert verified
Based on the steps above, one can visualize the data using the scatter plot, find the least-square line equation and finally predict Nevada's 2000 eighth-grade math proficiency and compare it with the actual value. The scatterplot is an important tool for understanding the relationship between the variables, the equation of the line helps predict future data and the comparison validates the model.

Step by step solution

01

Constructing Scatterplot

To create a scatterplot, each 1996 percentage is plotted on the x-axis and its correspondent 2000 percentage on the y-axis. Once all the states' data are plotted, observation for any patterns, clusters or outliers is done.
02

Finding Least Squares Line

This step involves using the least squares method to find the best fitting line in the scatterplot. The equation of a linear regression is given by \(y = a + bx\), where `b` is the slope or the change rate and `a` is the y-intercept. The slope, \(b = \frac{N\sum xy - \sum x \sum y}{N\sum x^2 - (\sum x)^2}\) and the y-intercept, \(a = \frac{\sum y - b\sum x}{N}\).`N` is the number of points, `x` and `y` are the values from the data. After the calculations, the least-squares line or line of best fit is found.
03

Prediction and Comparison

With the equation from the above step, prediction of the 2000 math proficiency for Nevada which had a 1996 fourth-grade math proficiency of 14\% is done by substituting \(x = 14\) in the equation. The predicted value is then compared to the actual value, which is 20.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scatterplot
A scatterplot is a type of graph that helps visualize the relationship between two variables by displaying them as a collection of points in a two-dimensional space. In this exercise, each state's 1996 fourth-grade math proficiency percentage is plotted on the x-axis, while the corresponding 2000 eighth-grade math proficiency percentage is plotted on the y-axis. Each state provides one point on the graph. By plotting all eight states, you can observe potential patterns such as trends, clusters of points, or outliers.
Understanding the scatterplot is crucial because it offers a visual summary of the data's distribution and relationship. For example, you might notice whether there's a positive association where higher proficiency percentages in 1996 coincide with higher percentages in 2000. Such observations are foundational before moving to more complex analytical steps like fitting a line.
Least Squares Line
The least squares line, also known as the line of best fit, is a straight line that best represents the data points on a scatterplot. It minimizes the total distance between the data points and the line itself, which is why it's called the "least squares" method.

To find this line, the least squares formula is applied, where the slope (\(b\)) and y-intercept (\(a\)) are calculated using specific formulas:
  • The slope (\(b\)) is calculated as: \[ b = \frac{N\sum xy - \sum x \sum y}{N\sum x^2 - (\sum x)^2} \]
  • The y-intercept (\(a\)) is calculated as: \[ a = \frac{\sum y - b\sum x}{N} \]
Where \(N\) is the number of data points, \(x\) and \(y\) are the values from your dataset. Calculating these provides the equation of the line (\(y = a + bx\)), which can be used to predict future values and understand the overall relationship between the variables.
Linear Regression
Linear regression involves creating a statistical model that describes the relationship between two variables, fitting the data with a straight line. This method is particularly useful for understanding how the dependent variable (\(y\), in this case, the 2000 proficiency percentage) changes as the independent variable (\(x\), the 1996 proficiency percentage) changes.
By calculating the best fit line (as addressed in the least squares section), linear regression not only describes the current data but also allows for predictions. For example, given the percent proficiency in 1996 for a state not originally in your data, like Nevada, you can estimate what their 2000 proficiency percentage might be if trends remain consistent. Linear regression is a foundational statistical tool used frequently to describe relationships and predict outcomes.
Data Interpretation
Interpreting data accurately is as essential as gathering it. Once you have your scatterplot and least squares line, it鈥檚 time to make sense of them. Observations from such an analysis can provide insights into progress, discrepancies, and predict future outcomes. For instance, by examining the plot, you can see which states improved significantly or remained constant in their proficiency over the years.
Furthermore, using the linear regression model, predictions can be made for other states. In this exercise, we used the regression line to predict Nevada's 2000 proficiency from their 1996 value. The prediction can then be compared to known data to verify accuracy or investigate deviations. Interpreting discrepancies between the predicted and actual values aids in understanding underlying factors affecting the change in student proficiency.

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Most popular questions from this chapter

Explain why the slope \(b\) of the least-squares line always has the same sign (positive or negative) as does the sample correlation coefficient \(r\).

An auction house released a list of 25 recently sold paintings. Eight artists were represented in these sales. The sale price of each painting appears on the list. Would the correlation coefficient be an appropriate way to summarize the relationship between artist \((x)\) and sale price \((y)\) ? Why or why not?

An accurate assessment of oxygen consumption provides important information for determining energy expenditure requirements for physically demanding tasks. The paper "Oxygen Consumption During Fire Suppression: Error of Heart Rate Estimation" (Ergonomics [1991]: \(1469-1474\) ) reported on a study in which \(x=\) oxygen consumption (in milliliters per kilogram per minute) during a treadmill test was determined for a sample of 10 firefighters. Then \(y=\) oxygen consumption at a comparable heart rate was measured for each of the 10 individuals while they performed a fire-suppression simulation. This resulted in the following data and scatterplot: $$ \begin{array}{lrrrrr} \text { Firefighter } & 1 & 2 & 3 & 4 & 5 \\ x & 51.3 & 34.1 & 41.1 & 36.3 & 36.5 \\ y & 49.3 & 29.5 & 30.6 & 28.2 & 28.0 \\ \text { Firefighter } & 6 & 7 & 8 & 9 & 10 \\ x & 35.4 & 35.4 & 38.6 & 40.6 & 39.5 \\ y & 26.3 & 33.9 & 29.4 & 23.5 & 31.6 \end{array} $$ a. Does the scatterplot suggest an approximate linear relationship? b. The investigators fit a least-squares line. The resulting MINITAB output is given in the following:. Predict fire-simulation consumption when treadmill consumption is 40 . c. How effectively does a straight line summarize the relationship? d. Delete the first observation, \((51.3,49.3)\), and calculate the new equation of the least-squares line and the value of \(r^{2}\). What do you conclude? (Hint: For the original data, \(\sum x=388.8, \Sigma y=310.3, \sum x^{2}=15,338.54, \sum x y=\) \(12,306.58\), and \(\sum y^{2}=10,072.41\).)

Explain why it can be dangerous to use the leastsquares line to obtain predictions for \(x\) values that are substantially larger or smaller than those contained in the sample.

Some straightforward but slightly tedious algebra shows that $$ \text { SSResid }=\left(1-r^{2}\right) \sum(y-\bar{y})^{2} $$ from which it follows that $$ s_{e}=\sqrt{\frac{n-1}{n-2}} \sqrt{1-r^{2}} s_{y} $$ Unless \(n\) is quite small, \((n-1) /(n-2) \approx 1\), so $$ s_{e} \approx \sqrt{1-r^{2}} s_{y} $$ a. For what value of \(r\) is \(s\), as large as \(s_{y} ?\) What is the least- squares line in this case? b. For what values of r will se be much smaller than \(s_{y} ?\) c. A study by the Berkeley Institute of Human Development (see the book Statistics by Freedman et al., listed in the back of the book) reported the following summary data for a sample of n 5 66 California boys: \(r \approx .80\) At age 6 , average height \(\approx 46\) in., standard deviation \(\approx\) \(1.7\) in. At age 18 , average height \(\approx 70\) in., standard deviation \(\approx\) \(2.5\) in. What would \(s_{e}\) be for the least-squares line used to predict 18-year-old height from 6-year-old height? d. Referring to Part (c), suppose that you wanted to predict the past value of 6 -year-old height from knowledge of 18 -year-old height. Find the equation for the appropriate least-squares line. What is the corresponding value of \(s_{e} ?\)

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