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E-Comm, British Columbia's emergency communications center, provides communication services and support systems to two million residents of southwest British Columbia, Canada. On any given day, the probability a randomly selected resident decides to call E-Comm is \(1.37 / 1000\). a. Assuming calls are made independently, find the probability that they all decide to call tomorrow. b. Is the assumption of independence made in part a realistic? Explain.

Short Answer

Expert verified
(0.00137)^{2000000} ≈ 0 (practically impossible). Independence assumption is unrealistic in real-world contexts.

Step by step solution

01

Understanding the Problem

We need to find the probability that every resident in a population of two million will make a call to E-Comm tomorrow. Each resident has an independent probability of making a call, which is \(1.37 / 1000\).
02

Probability for One Resident

First, convert the probability of one resident making a call from a fraction to a decimal. The probability is \( \frac{1.37}{1000} = 0.00137 \).
03

Probability for All Residents

Since each resident independently decides to call, the combined probability that every one of the two million residents calls is given by raising the probability of one calling to the power of 2,000,000 (the total number of residents). Therefore, the probability is \( (0.00137)^{2000000} \).
04

Evaluating the Probability Value

Calculate \( (0.00137)^{2000000} \), which is an extraordinarily small number, effectively making it zero for practical purposes since the base is much less than 1 and is raised to a large power.
05

Interpreting the Independence Assumption

The assumption of independence means each resident's decision to call is unaffected by others. In reality, this might not be true as events or external circumstances can influence multiple residents simultaneously.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence Assumption
When we talk about the independence assumption in probability, we're essentially saying that the occurrence of one event does not affect the occurrence of another. More formally, two events, A and B, are independent if the probability of A occurring, given that B occurs, is the same as the probability of A occurring without any information about B. Mathematically, this is expressed as:
  • \( P(A \mid B) = P(A) \)
In the context of our exercise, each resident's decision to call E-Comm is assumed to be independent. This means that if Resident A decides to make a call, it does not influence Resident B's decision to do the same. However, is this assumption realistic? Often in real-life scenarios, external factors can influence the decisions of many individuals at once. For example, a sudden emergency or news might increase the likelihood of many residents calling E-Comm. Therefore, while the independence assumption simplifies calculations, it may not always reflect true human behavior.
Calculating Probability
Calculating probability requires converting fractional representations to decimals to simplify the computation. Once probabilities are expressed in decimal form, you can perform various operations like multiplication or exponentiation. In the exercise, the probability that a single resident calls E-Comm is given as a fraction:
  • \( \frac{1.37}{1000} \)
This can be converted to a decimal to become 0.00137. When dealing with multiple independent events, knowing how to manipulate these figures becomes essential. Probability calculations can help determine the likelihood of specific outcomes, providing valuable insights for planning and decision-making under uncertainty. By mastering these foundational skills, students can navigate more complex problems with confidence.
Probability for Multiple Events
When attempting to find the probability of multiple independent events, you multiply the probabilities of each event. For the situation where we want all two million residents to call, we elevate the probability of one resident calling, 0.00137, to the power of two million. This means:
  • \( (0.00137)^{2000000} \)
Exponentiation is used here because each additional event (resident calling) compounds the initial probability. Since 0.00137 is much less than 1 and is raised to a very high power, the resulting probability is incredibly small. Practically, it approaches zero. This illustrates the nature of exponential growth or decay - small probabilities decrease significantly when combined over many events. Hence, for everyday situations, understanding how to calculate probabilities for multiple events can help in anticipating outcomes under various scenarios. Learning these techniques empowers students to better interpret and analyze real-world probabilities.

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