/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Drawing more cards A standard de... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Drawing more cards A standard deck of poker playing cards contains four suits (clubs, diamonds, hearts, and spades) and 13 different cards of each suit. During a hand of poker, 5 of the 52 cards have been exposed. Of the exposed cards, 3 were diamonds. Tony will have the opportunity to draw two more cards, and he has surmised that to win the hand, each of those two cards will need to be diamonds. What is Tony's probability of winning the hand? (Assume the two unexposed cards are not diamonds.)

Short Answer

Expert verified
Tony's probability of drawing two diamonds is \( \frac{1}{22} \).

Step by step solution

01

Identify Total Cards

A standard deck consists of 52 cards. Since 5 cards have already been exposed during the hand, there are 52 - 5 = 47 cards remaining in the deck.
02

Determine Remaining Diamonds

Initially, there are 13 diamonds in a deck. Since 3 diamonds have already been exposed, there are 13 - 3 = 10 diamonds remaining in the unexposed deck.
03

Determine Non-Diamonds

If two unexposed cards are known not to be diamonds, consider how this impacts remaining cards. With 47 cards, 47 - 2 = 45 cards remain eligible for drawing, as those 2 non-diamond cards must be excluded to calculate the probability of Tony's two draws being diamonds.
04

Calculate Probability First Draw

The probability that Tony's first card is a diamond is the number of remaining diamonds (10) divided by the number of cards left that could be drawn from (45): \( P(\text{First draw is a diamond}) = \frac{10}{45} \).
05

Calculate Probability Second Draw

If the first card drawn is a diamond, there are now 9 diamonds left among 44 remaining draw-worthy cards. Therefore, the probability of drawing another diamond on the second draw is \( P(\text{Second draw is a diamond}) = \frac{9}{44} \).
06

Combine Probabilities for Both Draws

The probability that Tony draws two diamonds in succession is the product of the probabilities for each of those draws: \( P(\text{Both draws are diamonds}) = \frac{10}{45} \times \frac{9}{44} = \frac{90}{1980} = \frac{1}{22} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Poker Probability
Playing poker involves more than just luck; understanding the probabilities can sharpen your game. Probability in poker helps determine the likelihood of drawing certain cards that can affect the outcome of a hand. In the scenario provided, we are dealing with the probability of Tony drawing two diamonds. These calculations are essential for making informed decisions about whether to fold, call, or raise during a game.

In this particular example, it's about understanding how the remaining unexposed cards can increase or decrease your chances of winning. Since only two cards out of the remaining deck are necessary, calculating these odds becomes straightforward using the probability rules learned through steps outlined in the solution.
Combinatorics in Card Games
Combinatorics is the branch of mathematics that deals with combinations and permutations. It is vital in card games like poker because it helps players calculate the different ways cards can be dealt or drawn. When figuring out poker probability, combinatorics allows us to determine how many possible hands there are and the combinations of suits and values that can appear.

In the exercise, we utilized combinatorics to figure out how many diamonds remain in the deck and how they could be drawn in sequence. This understanding allows players to foresee the best possible scenarios in a game and to adjust strategies accordingly. A firm grasp of combinatorics gives you a mathematical edge to assess the game's possibilities accurately.
Conditional Probability
Conditional probability refers to the likelihood of an event occurring given that another event has already occurred. In poker, this concept is frequently used to modify the probabilities based on the current situation. For example, the probability changes once you have more information about the cards already exposed.

In Tony's case, since three diamonds have already been exposed, the probability of drawing additional diamonds changes. Moreover, with the information about the two non-diamonds among the unexposed cards, our probability calculation considers only the eligible cards, demonstrating how initial conditions affect the final outcome.
Probability Calculation Steps
Calculating probability in card games requires breaking down the process into simple steps. As seen in the exercise, these steps allow us to systematically determine the chance of Tony drawing two diamonds.
  • First, identify the total number of possible outcomes, which starts with knowing how many cards are in the deck and how many remain available to be drawn.
  • Next, understand the specific outcomes necessary for success — in this case, the remaining diamonds.
  • Follow the sequence of draws, calculating the probability of each event individually before combining them to find the overall probability.
This approach makes calculating complex probabilities manageable by organizing them into logical steps, ensuring accuracy and clarity in your understanding of card probabilities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identifying spam An article \(^{4}\) on www.networkworld.com about evaluating e-mail filters that are designed to detect spam described a test of MailFrontier's Anti-Spam Gateway (ASG). In the test, there were 7840 spam messages, of which ASG caught \(7005 .\) Of the 7053 messages that \(\mathrm{ASG}\) identified as spam, they were correct in all but 48 cases. a. Set up a contingency table that cross classifies the actual spam status (with the rows "spam" and "not spam") by the ASG filter prediction (with the columns "predict message is spam" and "predict message is not spam"). Using the information given, enter counts in three of the four cells. b. For this test, given that a message is truly spam, estimate the probability that ASG correctly detects it. c. Given that ASG identifies a message as spam, estimate the probability that the message truly was spam.

A local downtown arts and crafts shop found from past observation that \(20 \%\) of the people who enter the shop actually buy something. Three potential customers enter the shop. a. How many outcomes are possible for whether the clerk makes a sale to each customer? Construct a tree diagram to show the possible outcomes. (Let \(Y=\) sale \(, \mathbf{N}=\) nosale. \()\) b. Find the probability of at least one sale to the three customers. c. What did your calculations assume in part b? Describe a situation in which that assumption would be unrealistic.

E-Comm, British Columbia's emergency communications center, provides communication services and support systems to two million residents of southwest British Columbia, Canada. On any given day, the probability a randomly selected resident decides to call E-Comm is \(1.37 / 1000\). a. Assuming calls are made independently, find the probability that they all decide to call tomorrow. b. Is the assumption of independence made in part a realistic? Explain.

Out of 100 songs on a playlist, 15 are of your favorite artist. You decide to randomly play one track from this playlist. a. State the sample space for the possible outcomes. b. State the probability for each possible outcome. c. What is the probability that the track chosen randomly from the playlist is of your favorite artist? d. What is the probability that the track chosen randomly from the playlist is not of your favorite artist?

Airplane safety has been improving over the years. From 2000 to \(2010,\) the average number of global airline deaths per year was over 1000 , even when excluding the nearly 3000 deaths in the United States on September 11,2001 . The number of global airline deaths declined in 2011 , again in \(2012,\) and then hit a low of only 265 in \(2013 .\) In \(2013,\) there were a total of 825 million passengers globally. Sources: en.wikipedia.org and www.transtats.bts.gov1. a. Can you consider the 2013 data as a long run or short run of trials? Explain. b. Estimate the probability of dying on a flight in \(2013 .\) (Note, the probability of dying from a 1000 -mile automobile trip is about 1 in 42,000 by contrast.) c. Raul is considering flying on an airplane. He noticed that over the past two months, there have been no fatal airplane crashes around the world. This raises his concern about flying because the airlines are "due for an accident." Comment on his reasoning.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.