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A particular heart disease is said to have a prevalence of \(1 / 1000\) in a specific population. In a sample of 50 people chosen randomly, what is the probability that at least two people have this disease?

Short Answer

Expert verified
The probability is approximately 0.0011 or 0.11\%.

Step by step solution

01

Determine Distribution Type

We are dealing with a scenario where we either have success (a person has the disease) or failure (a person does not have the disease) for each individual in a given sample. This means we are working with a binomial distribution, where we need to calculate the probability of a certain number of successes in a given number of trials.
02

Define Variables

In this problem, let \( n = 50 \) be the number of trials (people in the sample), and let \( p = \frac{1}{1000} = 0.001 \) be the probability of success (a person having the disease). We want to find the probability of having at least 2 people with the disease.
03

Calculate Probability of At Least Two

The probability of having at least 2 people with the disease is given by \( P(X \geq 2) \), where \( X \) is the number of people with the disease. We can find this by determining \( 1 - P(X < 2) \), which is \( 1 - (P(X = 0) + P(X = 1)) \).
04

Calculate Probability for Zero People

Using the binomial probability formula \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \), we have \( P(X = 0) = \binom{50}{0} (0.001)^0 (0.999)^{50} = 1 \times 1 \times 0.999^{50} \). This evaluates to approximately \( 0.9512 \).
05

Calculate Probability for One Person

Similarly for one person, \( P(X = 1) = \binom{50}{1} (0.001)^1 (0.999)^{49} = 50 \times 0.001 \times 0.999^{49} \). This evaluates to approximately \( 0.0477 \).
06

Calculate Final Probability

Substitute the values calculated into \( 1 - (P(X = 0) + P(X = 1)) \), which is \( 1 - (0.9512 + 0.0477) = 1 - 0.9989 = 0.0011 \).
07

Conclusion

The probability that at least two people in the sample have the disease is approximately \( 0.0011 \) or \( 0.11\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
In probability theory, the binomial distribution is a discrete probability distribution that describes the number of successes in a fixed number of trials, where each trial is identical and independent. A success is defined in the context of a problem, such as having a disease. Consider each person in a sample as a trial, and whether they have the disease as a success or failure. For our exercise, this scenario can be described using a binomial distribution because:
  • Each person (trial) has the same probability of having the disease (success).
  • The trials are independent of each other.
  • We are interested in counting the total number of successes (people with the disease) over all trials.
Using the binomial distribution, you can calculate the probability of having exactly a certain number of successes or more within a sample. It is widely used in statistics when you have scenarios involving multiple trials with two possible outcomes.
Prevalence
Prevalence refers to the proportion of a population found to have a particular condition at a specific point in time. In public health, it's often used to understand how widespread a disease is. In our problem, the prevalence of the heart disease is given as \( \frac{1}{1000} \). This means that out of 1,000 people in the population, on average, 1 person is expected to have the disease. Understanding prevalence is crucial because it helps in assessing the likelihood and predicting the spread of diseases. In this scenario, knowing the prevalence allowed us to set the probability \( p = 0.001 \) for each individual having the disease within the binomial distribution framework.
Statistical Calculation
Statistical calculations are essential for determining probabilities in many real-world scenarios. In our exercise, the process involves using the binomial probability formula to calculate the probability of specific outcomes.The binomial probability formula is:\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Where:
  • \( n \) is the number of trials (people in our sample, which is 50).
  • \( k \) is the number of successes (people with the disease).
  • \( p \) is the probability of success in a single trial (having the disease, which is 0.001).
This formula is essential to calculate the probability for 0 or 1 person having the disease, which then helps in finding the probability of at least two people being affected by subtracting these probabilities from 1.
Sample Size
Sample size refers to the number of individual observations used in a statistical sample. It’s an important component of statistical analysis because it affects the precision and reliability of the results. In this problem, our sample size is 50, which means we are assessing 50 individual trials (people). A larger sample size generally provides more reliable results since it tends to better represent the population. However, the choice of sample size depends on practical limitations, such as available resources and the required precision level for studies. Given a fixed prevalence rate, increasing the sample size makes it more likely to observe occurrences of rare events, such as our specific heart disease case. Therefore, sample size directly influences how closely the sample results mirror the actual characteristics of the population, impacting our confidence in the study’s findings.

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