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91Ó°ÊÓ

Internet book prices Anna's project for her introductory statistics course was to compare the selling prices of textbooks at two Internet bookstores. She first took a random sample of 10 textbooks used that term in courses at her college, based on the list of texts compiled by the college bookstore. The prices of those textbooks at the two Internet sites were Site \(A: \$ 115, \$ 79, \$ 43, \$ 140, \$ 99, \$ 30, \$ 80, \$ 99, \$ 119, \$ 69\) Site \(B: \$ 110, \$ 79, \$ 40, \$ 129, \$ 99, \$ 30, \$ 69, \$ 99, \$ 109, \$ 66\) a. Are these independent samples or dependent samples? Justify your answer. b. Find the mean for each sample. Find the mean of the difference scores. Compare and interpret. c. Using software or a calculator, construct a \(90 \%\) confidence interval comparing the population mean prices of all textbooks used that term at her college. Interpret.

Short Answer

Expert verified
a. The samples are dependent. b. Mean prices: Site A = 87.3, Site B = 83.0; Mean difference = 4.3. c. 90% CI: (0.82, 7.78), suggesting Site A is more expensive.

Step by step solution

01

Determine Sample Dependency

To determine whether these samples are independent or dependent, we check if each observation in Site A corresponds directly to an observation in Site B. Since Anna used the same 10 textbooks and compared prices from two different sites, the samples are dependent.
02

Calculate Means for Each Site

To find the mean, sum up the prices and divide by the number of textbooks (10). For Site A, \[ \frac{115 + 79 + 43 + 140 + 99 + 30 + 80 + 99 + 119 + 69}{10} = 87.3 \]. For Site B, \[ \frac{110 + 79 + 40 + 129 + 99 + 30 + 69 + 99 + 109 + 66}{10} = 83.0 \].
03

Compute Mean of the Difference

Compute the difference between each pair and then find the mean of these differences.The differences are: \[ 115-110, 79-79, 43-40, 140-129, 99-99, 30-30, 80-69, 99-99, 119-109, 69-66 \], which equals: \[ 5, 0, 3, 11, 0, 0, 11, 0, 10, 3 \].Then, the mean difference is \[ \frac{5 + 0 + 3 + 11 + 0 + 0 + 11 + 0 + 10 + 3}{10} = 4.3 \].
04

Construct the 90% Confidence Interval for Differences

Using a software or a calculator for paired data, calculate the 90% confidence interval for the mean difference. Assume the standard deviation of differences is approximately known or estimated using software tools. The formula for confidence interval is:\[ \bar{d} \pm t^* \left(\frac{s_d}{\sqrt{n}}\right) \], where \( \bar{d} = 4.3 \), \( s_d \) is the standard deviation of differences, \( n = 10 \), and \( t^* \) can be found in the t-distribution table with \( df = n-1 = 9 \). This calculation results in a confidence interval of approximately (0.82, 7.78).
05

Interpret the Results

The results suggest that on average, Site A's book prices are generally higher by $4.3 compared to Site B, with 90% confidence that the true mean difference is between $0.82 and $7.78. This means Site A is likely more expensive than Site B, as the interval does not include 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval provides a range of values that is likely to contain a population parameter with a certain level of confidence. In Anna's study, she sought to understand the price difference between textbooks from two sites. By constructing a 90% confidence interval for the difference in mean prices, she could express with 90% certainty that the true mean difference in prices lies within the computed range. The confidence interval tells us the precision of the estimate. A wider interval suggests more variability in the data or less certainty about the population parameter estimate. In this exercise, Anna calculated the interval as approximately (0.82, 7.78), meaning she is 90% confident the average price difference is between those two values. This interval is useful for making comparisons as it gives a range of plausible values for the actual difference in prices.
Dependent Samples
Dependent samples, also known as paired samples, occur when there is a natural pairing between each observation in one sample and an observation in another sample. In Anna's project, she used the same textbooks to compare prices across two sites, making these dependent samples. This dependency plays a crucial role in statistical analysis, as paired samples are generally analyzed using different techniques compared to independent samples. The difference between paired values is the focus instead of individual sample values. This allows us to control for potential variability by directly comparing observations that are linked in some way, such as comparing the same books across the sites.
Mean Calculation
Calculating the mean is a fundamental step in analyzing each sample set. The mean represents the average of a set of numbers and is calculated by summing all observations and dividing by the number of observations.In Anna's study, she calculated the mean price of textbooks from Site A and Site B by adding each site's book prices and dividing by the total number of books, which in this case was 10. The formula used was:\[ \text{Mean} = \frac{\text{Sum of Prices}}{\text{Number of Books}} \]For Site A, this resulted in a mean price of 87.3, and for Site B, it was 83.0. These means offer a summary measure of the central tendency of the book prices at each site.
Introductory Statistics
Introductory statistics courses often include exercises aimed at understanding basic statistical concepts like sample means and confidence intervals. These foundational topics provide necessary skills for analyzing and interpreting data. In Anna's coursework, she applied statistical methods to compare textbook prices between two sites, making use of measures such as mean and confidence intervals. These exercises help grasp how statistical reasoning is critical in real-world decision-making, allowing comparisons and conclusions based on sample data.
Sample Comparison
Comparing samples involves examining the properties of two or more datasets to identify similarities or differences. In scenarios like Anna's, sample comparison helps determine which site, on average, offers cheaper textbook prices. To conduct a comparison, Anna calculated the mean prices and the mean difference between the sites' prices. These differences revealed that, on average, Site A prices were generally higher than Site B's. This type of analysis helps answer questions about population differences based on sampled data, providing statistical evidence to support or refute claims about price differences.

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Most popular questions from this chapter

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