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When the GSS recently asked subjects whether it should or should not be the government's responsibility to impose strict laws to make industry do less damage to the environment (variable GRNLAWS), 1403 of 1497 subjects said yes. a. What assumptions are made to construct a \(95 \%\) confidence interval for the population proportion who would say yes? Do they seem satisfied here? b. Construct the \(95 \%\) confidence interval. Interpret in context. Can you conclude whether or not a majority or minority of the population would answer yes?

Short Answer

Expert verified
A 95% confidence interval is approximately [0.926, 0.948], indicating the majority would say yes.

Step by step solution

01

Assumptions for Confidence Interval

To construct a 95% confidence interval for a population proportion, we assume that the sample is randomly selected, the sample size is sufficiently large, and the sampling distribution of the sample proportion is approximately normal. The sample size should typically meet the rule of thumb where both \(np\) and \(n(1-p)\) are greater than 5, where \(n\) is the sample size and \(p\) is the sample proportion.
02

Verify Assumptions

For this data, we have a sample size \(n = 1497\) and the number of affirmative responses is 1403. The sample proportion \(\hat{p}\) is \(\frac{1403}{1497} \approx 0.937\). Checking the conditions: \(n\hat{p} = 1497 \times 0.937 = 1403\), and \(n(1-\hat{p}) = 1497 \times (1-0.937) = 94\), both of which are greater than 5. Thus, the normal approximation is valid.
03

Calculate Standard Error

The standard error (SE) of the sample proportion \(\hat{p}\) is given by \( \text{SE} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.937 \times 0.063}{1497}} \). Compute this value for the exact standard error.
04

Determine Critical Value for 95% Confidence Interval

For a 95% confidence interval, we use a critical z-value of approximately 1.96, which corresponds to the 2.5% tails of the standard normal distribution.
05

Construct the Confidence Interval

The formula for the confidence interval is \( \hat{p} \pm (z_{\alpha/2} \times \text{SE}) \). Substitute \(\hat{p} = 0.937\), \(z_{\alpha/2} = 1.96\), and the computed standard error to obtain the confidence interval bounds.
06

Calculation and Interpretation

Calculate the interval bounds and conclude. If the interval bounds are entirely above 0.5, it suggests that a majority of the population would answer yes. Substituting the values, the interval is approximately \([0.926, 0.948]\). This interval indicates that the majority of the population supports stricter environmental laws.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a fundamental concept when dealing with confidence intervals, especially in surveys and polls. It represents the fraction of the entire population that possesses a particular attribute or responds positively to a specific question. In the context of the GSS survey on stricter environmental laws, the population proportion is the fraction of all individuals who would agree that strict laws should be imposed.

Calculating the population proportion involves gathering sample data and making inferences about the entire population. First, we find the sample proportion, denoted as \( \hat{p} \), by dividing the number of affirmative responses by the sample size. In our example, \( \hat{p} = \frac{1403}{1497} \approx 0.937 \). This figure indicates that approximately 93.7% of the sample supports stricter environmental laws.
  • Note: The sample proportion \( \hat{p} \) serves as an estimate of the population proportion \( p \).
Standard Error
Standard error (SE) is a measure of the variability of the sample proportion \, \( \hat{p} \, \) when we estimate the population proportion \( p \). It quantifies the precision of \( \hat{p} \) as an estimate of \( p \).

The formula for standard error of a sample proportion \( \hat{p} \) is given by:\[ \text{SE} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \]Where:
  • \( \hat{p} \) is the sample proportion.
  • \( n \) is the sample size.
In our example, substituting the given values yields:\[ \text{SE} = \sqrt{\frac{0.937 \times 0.063}{1497}} \approx 0.0069 \]This small standard error suggests that the sample proportion is a reliable estimate of the population proportion.

Understanding the standard error is crucial because it directly impacts the width of the confidence interval. A smaller SE results in a narrower confidence interval, indicating more precise estimation.
Normal Approximation
Normal approximation is a statistical technique used to determine the probability of various outcomes within a population, based on a sample. This approach leverages the normal distribution to approximate the sampling distribution of the sample proportion.

For normal approximation to be valid, certain conditions must be met:
  • The sample should be randomly selected and sufficiently large.
  • Both \( np \) and \( n(1-p) \) should exceed 5, ensuring a bell-shaped distribution of possible sample proportions.
In our case, with \( n = 1497 \) and \( \hat{p} = 0.937 \):
  • \( n\hat{p} = 1403 \) and \( n(1-\hat{p}) = 94 \).
Since both values are greater than 5, the normal approximation applies. This justifies using the standard normal distribution, which simplifies calculations and aids in constructing confidence intervals.
Critical Value
The critical value is part of constructing a confidence interval, representing the threshold at which we separate "likely" sample proportions from "unlikely" ones.

For a 95% confidence interval, we typically use a critical z-value of \( 1.96 \), derived from the standard normal distribution, to cover 95% of possibilities within \( \pm 1.96 \) standard deviations from the mean.
  • This critical value marks the boundaries where only 2.5% of sample proportions fall in each tail of the normal distribution.
We use the critical value to complete the confidence interval formula:\[ \hat{p} \pm (z_{\alpha/2} \times \text{SE}) \]Here, \( z_{\alpha/2} = 1.96 \) for a 95% confidence interval, making it a key factor in determining the precision and reliability of the interval. In our case, the resulting interval \( [0.926, 0.948] \) indicates a high confidence that the population proportion of support lies within these values, suggesting a majority favors stricter laws.

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