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91Ó°ÊÓ

Consider taking a random sample from a population with \(p=0.25\) a. What is the standard error of \(\hat{p}\) for random samples of size \(400 ?\) b. Would the standard error of \(\hat{p}\) be smaller for random samples of size 200 or samples of size \(400 ?\) c. Does cutting the sample size in half from 400 to 200 double the standard error of \(\hat{p} ?\)

Short Answer

Expert verified
a. The standard error of \(\hat{p}\) for a sample size of 400 is approximately 0.02165. b. The standard error of \(\hat{p}\) would be smaller for random samples of size 400 compared to samples of size 200. c. No, cutting the sample size in half from 400 to 200 does not double the standard error of \(\hat{p}\).

Step by step solution

01

a. Find the Standard Error for n = 400

To find the standard error for a sample size of 400, we can plug the given values into the standard error formula: \[ SE(\hat{p}) = \sqrt{\frac{0.25(1-0.25)}{400}} \] This simplifies to: \[ SE(\hat{p}) = \sqrt{\frac{0.25(0.75)}{400}} = \sqrt{\frac{0.1875}{400}} = 0.02165 \] So, the standard error for a sample size of 400 is approximately 0.02165.
02

b. Compare Standard Error for n = 200 and n = 400

Now, let's find the standard error for a sample size of 200: \[ SE(\hat{p}) = \sqrt{\frac{0.25(1-0.25)}{200}} \] This simplifies to: \[ SE(\hat{p}) = \sqrt{\frac{0.25(0.75)}{200}} = \sqrt{\frac{0.1875}{200}} = 0.03056 \] So, the standard error for a sample size of 200 is approximately 0.03056. Since 0.02165 (SE for n = 400) < 0.03056 (SE for n = 200), the standard error of \(\hat{p}\) would be smaller for random samples of size 400 compared to samples of size 200.
03

c. Check if Decreasing Sample Size Doubles the Standard Error

Lastly, let's check if reducing the sample size from 400 to 200 doubles the standard error: SE for n = 200 is approximately 0.03056 (found in part b) SE for n = 400 is approximately 0.02165 (found in part a) \[ \frac{SE_{n=200}}{SE_{n=400}} = \frac{0.03056}{0.02165} ≈ 1.41 \] Since the ratio of the standard errors is approximately 1.41 and not 2, cutting the sample size in half from 400 to 200 does not double the standard error of \(\hat{p}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
Understanding the sampling distribution is crucial when working with statistical data. Essentially, it's a probability distribution of a statistic obtained from a larger number of samples drawn from a specific population. Here's how it's useful: imagine you're trying to determine the average height of trees in a vast forest. You can't measure every single tree, so you take multiple random samples instead. Each sample will give you an average height - these averages form a distribution, which is named the sampling distribution of the mean.

The more samples you take, the more the sampling distribution of the sample mean will resemble a normal distribution, regardless of the shape of the population distribution, thanks to the Central Limit Theorem. This concept is extremely handy because it allows us to use the properties of the normal distribution to make inferences about the population based on the sample.

For the case of estimating proportions, the sampling distribution follows the binomial distribution, which becomes approximately normal when the sample size is large enough, and that's when we can start using the standard error to understand variability.
Sample Size
The sample size, denoted as 'n' in statistical notation, significantly affects the accuracy and reliability of the statistics derived from a sample. A larger sample size often leads to a smaller standard error, which indicates a more precise estimate of the population parameter. Why is this important? Consider shooting arrows at a target. The more arrows you shoot, the more likely you are to hit the bullseye, or in statistical terms, the true population parameter.

In our specific example, we found that the standard error for a sample size of 400 was smaller than that of a sample size of 200. Intuitively, this makes sense as a larger sample size gives us more information and typically a more robust estimate. When conducting an analysis or an experiment, one crucial step is to determine the appropriate sample size needed to ensure reliable results without wasting resources.
Estimation of Proportions
Estimation of proportions involves inferring the ratio of a particular attribute in a population, like estimating the proportion of left-handed students in a school. In the context of standard error calculations, the proportion, or 'p', represents the probability of success in a binomial experiment. The term 'success' here doesn't imply a positive outcome; it simply means the attribute or outcome you're focused on.

Given that the true population proportion is often unknown, we use a sample to estimate this proportion. The standard error of the estimated proportion, \(SE(\hat{p})\), gives us a sense of how much variation exists between the true population proportion and our estimate from the sample. Hence, a smaller standard error means a more accurate estimate of the population proportion. To demonstrate this, an example was worked out based on a population with \(p=0.25\). We see that as the sample size increased from 200 to 400, the standard error decreased, meaning the estimate for population proportion became more precise. It's also noted that halving the sample size did not exactly double the standard error, which contradicts a common misconception.

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Most popular questions from this chapter

Based on data from a survey of 1200 randomly selected Facebook users (USA TODAY, March 24, 2010), a \(98 \%\) confidence interval for the proportion of all Facebook users who say it is OK to ignore a coworker's "friend" request is \((0.35,0.41) .\) What is the meaning of the confidence level of \(98 \%\) that is associated with this interval?

A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label. How many packages of ground beef should be tested in order to have a margin of error of \(0.05 ?\)

A random sample will be selected from the population of all students enrolled at a large college. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all students who use public transportation to travel to campus. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) i. \(n=300, p=0.3\) ii. \(n=700, p=0.2\) iii. \(n=1000, p=0.1\)

A random sample will be selected from the population of all adult residents of a particular city. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all adult residents who are registered to vote. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) I. \(\quad n=1000, p=0.5\) II. \(\quad n=200, p=0.6\) III. \(n=100, p=0.7\)

The formula used to calculate a large-sample confidence interval for \(p\) is $$ \hat{p} \pm(z \text { critical value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} $$ What is the appropriate \(z\) critical value for each of the following confidence levels? a. \(90 \%\) b. \(99 \%\) c. \(80 \%\)

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