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USA TODAY reported that the proportion of Americans who prefer cheese on their burgers is 0.84 (USA TODAY, September 7,2016 ). This estimate was based on a survey of a representative sample of 1000 adult Americans. Calculate and interpret a margin of error for the reported proportion.

Short Answer

Expert verified
SE = \(\sqrt{\frac{(0.84)(0.16)}{1000}}\) SE ≈ 0.0137 #tag_title#Step 3: Calculate the Margin of Error#tag_content# Now that we have the standard error, we can calculate the margin of error. We will use a 95% confidence level, which corresponds to a z-score of 1.96. The formula for the margin of error is: Margin of Error (ME) = z * SE ME = 1.96 * 0.0137 ME ≈ 0.0268 #tag_title#Step 4: Interpret the Margin of Error#tag_content# The margin of error is 0.0268, or 2.68%. This means that we can be 95% confident that the true proportion of Americans who prefer cheese on their burgers lies between 0.84 - 0.0268 (81.32%) and 0.84 + 0.0268 (86.68%).

Step by step solution

01

Identify the Key Variables

In this problem, the key variables are: 1. The proportion (p) of Americans who prefer cheese on their burgers: 0.84 2. The sample size (n): 1000
02

Calculate the Standard Error

To find the margin of error, we need first to calculate the standard error of the proportion. The formula for the standard error is given by: Standard Error (SE) = \(\sqrt{\frac{p(1-p)}{n}}\) Let's plug in the given values. SE = \(\sqrt{\frac{(0.84)(1-0.84)}{1000}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error of the Proportion
When dealing with survey data analysis, one of the pivotal concepts to understand is the 'standard error of the proportion.' It serves as a measure of the variability or uncertainty around an estimated population proportion that results from only surveying a sample of that population. In other words, it gauges how much we would expect the calculated proportion to vary if we were to conduct different samplings from the same population.

For example, in the case of the USA TODAY report regarding Americans' preference for cheese on burgers, we calculated the standard error using the provided survey data where 84% of respondents from a sample of 1000 adults preferred cheese. The formula is: \[ SE = \sqrt{\frac{p(1-p)}{n}} \]We plug in the proportion \( p = 0.84 \) and the sample size \( n = 1000 \) to find the standard error. This calculation grants us the key to unlocking how reliable this sample proportion is as an estimate of the true population proportion.
Survey Data Analysis
Survey data analysis is a critical component of interpreting what the collected data represents regarding an entire population. When only a fraction of the population is surveyed—as is often the case for practicality and resource management—we need statistical tools to project our findings onto the greater group. To comprehend a specific phenomenon, like the preference for cheese on burgers among all Americans, we don't survey every individual, we survey a representative sample.

Within this analysis, we not only calculate the proportion of interest but also assess how representative our sample is. This assessment includes the understanding of the possible margin of error, confidence levels, and standard error. The margin of error, in this context, offers an estimation of the range within which the true population parameter is expected to lie. Proper survey data analysis ensures that such estimates are made with high statistical confidence and accuracy.
Statistical Inference
Statistical inference is like the bridge that connects our sample data to the broader population. It's the process of drawing conclusions about a population's characteristics based on a sample taken from it. Two primary aspects of statistical inference are estimation and hypothesis testing. In the exercise about burger preferences, we're concerned with estimation—specifically, using the sample data to estimate a population parameter (proportion of Americans who prefer cheese on burgers).

Statistical inference relies on the idea that the sample data can give us good, but not perfect, information about the population. The margin of error plays a crucial role here. It tells us how close our sample estimate likely is to the true population value. By calculating the margin of error from the standard error, as done in the burger preference example, we're able to qualify our estimations and give them context, making our statistical inferences much more robust and meaningful.

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Most popular questions from this chapter

A researcher wants to estimate the proportion of city residents who favor spending city funds to promote tourism. Would the standard error of the sample proportion \(\hat{p}\) be smaller for random samples of size \(n=100\) or random samples of size \(n=200 ?\)

The article "Kids Digital Day: Almost 8 Hours" (USA TODAY, January 20,2010 ) summarized a national survey of 2002 Americans age 8 to \(18 .\) The sample was selected to be representative of Americans in this age group. a. Of those surveyed, 1321 reported owning a cell phone. Use this information to construct and interpret a \(90 \%\) confidence interval for the proportion of all Americans ages 8 to 18 who owned a cell phone in 2010 . b. Of those surveyed, 1522 reported owning an MP3 music player. Use this information to construct and interpret a \(90 \%\) confidence interval for the proportion of all Americans ages 8 to 18 who owned an MP3 music player in 2010 c. Explain why the confidence interval from Part (b) is narrower than the confidence interval from Part (a) even though the confidence levels and the sample sizes used to calculate the two intervals were the same.

In spite of the potential safety hazards, some people would like to have an Internet connection in their car. A preliminary survey of adult Americans has estimated the proportion of adult Americans who would like Internet access in their car to be somewhere around 0.30 (USA TODAY, May 1 , 2009). Use the given preliminary estimate to determine the sample size required to estimate this proportion with a margin of error of 0.02

Suppose that 935 smokers each received a nicotine patch, which delivers nicotine to the bloodstream at a much slower rate than cigarettes do. Dosage was decreased to 0 over a 12 -week period. Of these 935 people, 245 were still not smoking 6 months after treatment. Assume this sample is representative of all smokers. a. Use the given information to estimate the proportion of all smokers who, when given this treatment, would refrain from smoking for at least 6 months. b. Verify that the conditions needed in order for the margin of error formula to be appropriate are met. c. Calculate the margin of error. d. Interpret the margin of error in the context of this problem.

Will \(\hat{p}\) from a random sample from a population with \(60 \%\) successes tend to be closer to 0.6 for a sample size of \(n=400\) or a sample size of \(n=800 ?\) Provide an explanation for your choice.

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