/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 A researcher wants to estimate t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A researcher wants to estimate the proportion of property owners who would pay their property taxes one month early if given a \(\$ 50\) reduction in their tax bill. Would the standard error of the sample proportion \(\hat{p}\) be larger if the actual population proportion were \(p=0.2\) or if it were \(p=0.4\) ?

Short Answer

Expert verified
The standard error of the sample proportion \(\hat{p}\) would be larger if the actual population proportion were \(p=0.4\). This is because \(SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}}\), and comparing the numerators when \(p=0.2\) and \(p=0.4\), we have \(0.2(0.8) = 0.16\) and \(0.4(0.6) = 0.24\), with \(0.24 > 0.16\).

Step by step solution

01

Understand the concept of standard error

The standard error of the sample proportion \(\hat{p}\) is a measure of the variation of the sample proportion from the true population proportion. It can be thought of as an estimation of the precision of the sample proportion, with smaller standard errors indicating better precision.
02

Find the formula for the standard error of the sample proportion

The formula for the standard error of the sample proportion \(\hat{p}\) is given by: \[ SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}} \] where \(p\) is the true population proportion and \(n\) is the sample size.
03

Compare the standard error for \(p=0.2\) and \(p=0.4\)

To compare the standard error of the sample proportion under the two situations, we plug in the values for \(p\) in the formula: For \(p=0.2\): \[ SE(\hat{p}) = \sqrt{\frac{0.2(1-0.2)}{n}} = \sqrt{\frac{0.2(0.8)}{n}} \] For \(p=0.4\): \[ SE(\hat{p}) = \sqrt{\frac{0.4(1-0.4)}{n}} = \sqrt{\frac{0.4(0.6)}{n}} \] In both cases, we have the same denominator (sample size), so we can simply compare the numerators to determine which situation has a larger standard error. We have: \[ 0.2(0.8) = 0.16 \] and \[ 0.4(0.6) = 0.24 \] Since \(0.24 > 0.16\), the standard error of the sample proportion is larger when the actual population proportion is \(p=0.4\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
In statistics, the population proportion represents the fraction of individuals in a population who exhibit a particular attribute. For example, in the context of the exercise, the population proportion, denoted by the symbol \(p\), indicates the percentage of property owners who would pay their property taxes early for a \(\$50\) reduction. When conducting a survey, researchers often cannot reach the entire population, so they use a sample to estimate the population proportion. This estimate, noted as \(\hat{p}\), is calculated from the sample data and can be used to make inferences about the true proportion \(p\) in the entire population.

Understanding the population proportion is crucial when interpreting survey results or conducting hypothesis testing about proportions. It is the cornerstone for calculating related statistical metrics, such as the standard error of the sample proportion, which gauges how far off this estimation might be from the true population proportion.
Statistical Precision
Statistical precision refers to the closeness of the estimates from different samples to the actual population parameter. A highly precise estimate means that if the study were repeated with different samples, the result would be consistently similar to the real population value. In terms of the standard error of the sample proportion, a smaller standard error indicates greater precision because it suggests that the sample proportion is likely to be close to the true population proportion. Precision is affected by factors such as sample size and the variance in the population. Larger sample sizes and lower variability usually increase the precision of an estimate, making it a more reliable reflection of the population attribute.
Variation in Statistics
Variation is a fundamental concept in statistics that explains how data points in a set diverge from the average or expected value. When examining variations in the context of sample proportions, it refers to how much individual sample estimates might differ from the population proportion. Various sources can cause such variation, including natural fluctuations in the population, sampling methods, or measurement errors.

Understanding variation is integral to calculating statistical measures like the standard error, which specifically measures the standard deviation of the sampling distribution of the sample proportion. By acknowledging variation, researchers can estimate the reliability of their findings and determine the necessary sample size to achieve a desired level of precision.
Standard Error Formula
The standard error formula is a key equation used to quantify the variability of a statistic from a sample. For the sample proportion, the standard error (SE) formula is:\[SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}}\]where \(\hat{p}\) is the sample proportion, \(p\) is the true population proportion, and \(n\) is the sample size. This formula provides a standard measurement of how much the estimate derived from the sample, \(\hat{p}\), is expected to differ from the actual population proportion \(p\).

From this formula, we can see that the standard error decreases with larger sample sizes, leading to more precise estimates. Moreover, the formula includes the product of \(p\) and \((1-p)\), reflecting that the maximum variability occurs when the population proportion is at 0.5, and it decreases as the proportion approaches 0 or 1. The exercise given demonstrates how the standard error changes with different values of \(p\), providing a practical illustration of the formula's application.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An article in the Chicago Tribune (August 29,1999\()\) reported that in a poll of residents of the Chicago suburbs, \(43 \%\) felt that their financial situation had improved during the past year. The following statement is from the article: "The findings of this Tribune poll are based on interviews with 930 randomly selected suburban residents. The sample included suburban Cook County plus DuPage, Kane, Lake, McHenry, and Will Counties. In a sample of this size, one can say with \(95 \%\) certainty that results will differ by no more than \(3 \%\) from results obtained if all residents had been included in the poll." Give a statistical argument to justify the claim that the estimate of \(43 \%\) is within \(3 \%\) of the actual percentage of all residents who feel that their financial situation has improved.

A random sample will be selected from the population of all students enrolled at a large college. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all students who use public transportation to travel to campus. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) i. \(n=300, p=0.3\) ii. \(n=700, p=0.2\) iii. \(n=1000, p=0.1\)

The report "The 2016 Consumer Financial Literacy Survey" (The National Foundation for Credit Counseling, www.nfcc.org, retrieved October 28,2016 ) summarized data from a representative sample of 1668 adult Americans. Based on data from this sample, it was reported that over half of U.S. adults would give themselves a grade of \(\mathrm{A}\) or \(\mathrm{B}\) on their knowledge of personal finance. This statement was based on observing that 934 people in the sample would have given themselves a grade of \(\mathrm{A}\) or \(\mathrm{B}\). a. Construct and interpret a \(95 \%\) confidence interval for the proportion of all adult Americans who would give themselves a grade of \(\mathrm{A}\) or \(\mathrm{B}\) on their financial knowledge of personal finance. b. Is the confidence interval from Part (a) consistent with the statement that a majority of adult Americans would give themselves a grade of \(\mathrm{A}\) or \(\mathrm{B}\) ? Explain why or why not.

A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label. How many packages of ground beef should be tested in order to have a margin of error of \(0.05 ?\)

Will \(\hat{p}\) from a random sample of size 400 tend to be closer to the actual value of the population proportion when \(p=0.4\) or when \(p=0.7 ?\) Provide an explanation for your choice.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.