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Use the formula for the standard error of \(\hat{p}\) to explain why increasing the sample size decreases the standard error.

Short Answer

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In summary, increasing the sample size decreases the standard error of the sample proportion, \(SE(\hat{p})\), because the formula for the standard error is: \[ SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}} \] As the sample size, \(n\), increases, the denominator of the fraction also increases, reducing the overall value of the fraction. As the fraction decreases, the standard error also decreases, making our estimate of the population proportion more precise.

Step by step solution

01

Define the formula for the standard error of the sample proportion

The formula for the standard error of the sample proportion, denoted as SE(\(\hat{p}\)), is given by: \[ SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}} \] where \(p\) is the true population proportion, \(n\) is the sample size, and \(\hat{p}\) is the sample proportion. Notice that the sample size, \(n\), is in the denominator of the fraction.
02

Understand the relationship between the sample size and the standard error

As the sample size, \(n\), increases, the value of the fraction: \[ \frac{p(1-p)}{n} \] decreases because the denominator is getting larger.
03

Explain the impact of increasing the sample size on the standard error

As the value of the fraction \(\frac{p(1-p)}{n}\) decreases, the value of the standard error, \(SE(\hat{p})\), also decreases. This is because the square root of a smaller number results in a smaller number. To summarize, when the sample size increases, the standard error of the sample proportion decreases due to the inverse relationship between the sample size and the value of the fraction in the formula. This means that our estimate of the population proportion becomes more precise as we increase the sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
A sample proportion, denoted as \( \hat{p} \), is a way of estimating the proportion of a particular characteristic or outcome in a population by examining a sample. Suppose you're interested in knowing how many people in a town like chocolate ice cream. Instead of asking every single person, you might select a group of 100 people and find that 60 of them like chocolate ice cream. Here, your sample proportion \( \hat{p} \) would be \( \frac{60}{100} = 0.6 \).

Sample proportions are useful because they provide insight into the whole population without needing to analyze everyone. However, since it's based on a sample, there can be variations or uncertainty in the estimate. This is where the standard error comes into play, indicating how much the sample proportion \( \hat{p} \) might differ from the actual population proportion \( p \).
  • The closer the sample proportion is to the true population proportion, the more accurate your inferences become.
  • While the sample proportion provides an estimate, keep in mind that it's dependent on the sample size, \( n \), and the data collected.
Sample Size
Sample size \( n \) is a critical factor in statistical analysis. It refers to the number of observations or data points collected in a study. In any research, choosing an appropriate sample size is crucial for obtaining reliable results. The larger the sample size, the more information you have, and generally, the more reliable your results will be.

When it comes to estimating proportions, the sample size directly influences the precision of your estimate. Larger sample sizes tend to produce more stable and accurate estimates. This is directly related to the standard error of the sample proportion \( \hat{p} \), which decreases as \( n \) increases.
  • For instance, a sample size of 100 will give you a clearer picture than a sample size of 10.
  • However, larger sample sizes require more resources, so there's often a balance to be found between precision and practicality.

The formula \( SE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}} \) shows that the sample size \( n \) is in the denominator, illustrating its role in reducing the standard error. As \( n \) grows, the denominator becomes larger, thus shrinking the fraction under the square root and resulting in a smaller standard error.
Inverse Relationship
In the context of the standard error of a sample proportion, an inverse relationship is the concept that as one factor increases, another decreases. Here, the sample size \( n \) and the standard error \( SE(\hat{p}) \) exhibit such a relationship. As you increase \( n \), the standard error decreases, making your estimate more accurate.

This inverse relationship is crucial because it underscores why large sample sizes are valued in research. A decrease in standard error means less variability in your sample estimates, which translates to a more precise estimate of the population proportion.
  • This relationship also highlights the diminishing returns effect: as the sample size gets very large, the improvements in precision from adding more data points become smaller.
  • Understanding this relationship helps researchers in planning. They know that bigger samples are beneficial up to a point, beyond which the cost and effort may not justify the gain in accuracy.

In summary, recognizing the inverse relationship between sample size and standard error is essential for designing efficient studies. It helps balance between having enough data to ensure precision without overextending resources.

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Most popular questions from this chapter

Will \(\hat{p}\) from a random sample of size 400 tend to be closer to the actual value of the population proportion when \(p=0.4\) or when \(p=0.7 ?\) Provide an explanation for your choice.

Suppose that a campus bookstore manager wants to know the proportion of students at the college who purchase some or all of their textbooks online. Two different people independently selected random samples of students at the college and used their sample data to construct the following confidence intervals for the population proportion: Interval 1:(0.54,0.57) Interval 2:(0.46,0.62) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals have a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

Based on data from a survey of 1200 randomly selected Facebook users (USA TODAY, March 24, 2010), a \(98 \%\) confidence interval for the proportion of all Facebook users who say it is OK to ignore a coworker's "friend" request is \((0.35,0.41) .\) What is the meaning of the confidence level of \(98 \%\) that is associated with this interval?

Data from a representative sample were used to estimate that \(32 \%\) of all computer users in 2011 had tried to get on a Wi-Fi network that was not their own in order to save money (USA TODAY, May 16,2011 ). You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of \(0.05 ?\) Calculate the required sample size first using 0.32 as a preliminary estimate of \(p\) and then using the conservative value of \(0.5 .\) How do the two sample sizes compare? What sample size would you recommend for this study?

The article "Kids Digital Day: Almost 8 Hours" (USA TODAY, January 20,2010 ) summarized a national survey of 2002 Americans age 8 to \(18 .\) The sample was selected to be representative of Americans in this age group. a. Of those surveyed, 1321 reported owning a cell phone. Use this information to construct and interpret a \(90 \%\) confidence interval for the proportion of all Americans ages 8 to 18 who owned a cell phone in 2010 . b. Of those surveyed, 1522 reported owning an MP3 music player. Use this information to construct and interpret a \(90 \%\) confidence interval for the proportion of all Americans ages 8 to 18 who owned an MP3 music player in 2010 c. Explain why the confidence interval from Part (b) is narrower than the confidence interval from Part (a) even though the confidence levels and the sample sizes used to calculate the two intervals were the same.

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