/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 The accompanying data on \(x=\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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The accompanying data on \(x=\) student-teacher ratio is for a random sample of 20 high schools in Maine selected from a population of 85 high schools. The data are consistent with summary values for the state of Maine that appeared in an article in the Bangor Daily News (September \(22,2016,\) bangordailynews.com/2016/09/22/mainefocus/we-discovered-a-surprise-when-we- looked-deeper-into-our-survey-of-maine-principals/?ref=morelnmidcoast, retrieved May 2, 2017). The corresponding normal scores are also shown. $$ \begin{array}{|cc|} \hline \text { Student-Teacher Ratio }(x) & \text { Normal Score } \\ \hline 9.0 & -1.868 \\ 10.0 & -1.403 \\ 11.0 & -1.128 \\ 11.2 & -0.919 \\ 11.6 & -0.744 \\ 11.7 & -0.589 \\ 11.8 & -0.448 \\ 11.9 & -0.315 \\ 12.0 & -0.187 \\ 12.1 & -0.062 \\ 12.5 & 0.062 \\ 12.6 & 0.187 \\ 13.0 & 0.315 \\ 13.2 & 0.448 \\ 13.6 & 0.589 \\ 13.7 & 0.744 \\ 14.0 & 0.919 \\ 14.5 & 1.128 \\ 14.9 & 1.403 \\ 15.0 & 1.868 \\ \hline \end{array} $$ a. Construct a normal probability plot. b. Calculate the correlation coefficient for the (normal score, \(x\) ) pairs. Compare this value to the appropriate critical \(r\) value from Table 6.2 to determine if it is reasonable to think that the distribution of student-teacher ratios for high schools in Maine is approximately normal.

Short Answer

Expert verified
In summary, to determine if the distribution of student-teacher ratios for high schools in Maine is approximately normal, construct a normal probability plot and calculate the correlation coefficient (r) for the given data. Then, compare the calculated r value with the critical r value from Table 6.2. If the calculated r value is greater than or equal to the critical r value, it is reasonable to think that the distribution is approximately normal.

Step by step solution

01

Construct a normal probability plot

To construct the normal probability plot, we can plot the given normal scores on the horizontal axis and student-teacher ratios on the vertical axis. Each point on the plot will represent a pair (normal score, student-teacher ratio). You can do this using graph paper or graphing software.
02

Calculate the correlation coefficient (r) for the pairs

We're given the normal scores and student-teacher ratios in a table. To calculate the correlation coefficient, we'll first need to find the mean and standard deviation for both sets of data. 1. Compute the mean of normal scores (\( \bar{y} \)) and student-teacher ratios (\( \bar{x} \)) 2. Compute the standard deviation of normal scores (\( s_y \)) and student-teacher ratios (\( s_x \)) 3. Calculate the correlation coefficient using the formula: \(r = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sqrt{\sum (x_i - \bar{x})^2}\sqrt{\sum (y_i - \bar{y})^2}}\)
03

Compare the calculated correlation coefficient (r) with the critical value

Once we have the correlation coefficient, we can compare it with the critical r value from Table 6.2. If the calculated r value is greater than or equal to the critical r value, we can conclude that it is reasonable to think that the distribution of student-teacher ratios for high schools in Maine is approximately normal. If the calculated r value is less than the critical r value, the distribution is not normal, and we cannot make any conclusions about the normality of the data. By following the steps above, you can calculate the correlation coefficient for the given data and compare it with the critical r value to determine if the distribution of student-teacher ratios for high schools in Maine is approximately normal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Student-Teacher Ratio
The student-teacher ratio in schools is a simple but valuable indicator, reflecting the number of students for every teacher in an educational institution. A lower ratio often suggests that students might receive more personal attention and tailored instruction, whereas a higher ratio can imply less individualized attention. In the context of our data from Maine high schools, the ratios give insight into the educational environment and can be used to draw comparisons or correlations with educational outcomes.
When analyzing the significance of the student-teacher ratio, one can look at several factors. For instance, data on student-teacher ratios may correlate with student performance, availability of resources, and overall educational quality. Therefore, a thorough understanding of these ratios and their implications on education can be very helpful for policymakers, administrators, and educators who aim to improve the learning experience.
Deciphering the Correlation Coefficient
The correlation coefficient, denoted as 'r', quantifies the strength and direction of a linear relationship between two variables. It's a statistic that can take a value from -1 to +1. A value closer to +1 indicates a strong positive correlation, meaning as one variable increases, so does the other. Conversely, a value closer to -1 indicates a strong negative correlation, where one variable increases as the other decreases. A value around 0 suggests little to no linear relationship.
In the given exercise, calculating the correlation coefficient between normal scores and student-teacher ratios can reveal if the relationship between these two variables is linear and positive, linear and negative, or nonexistent. This calculation involves summing the products of each pair's deviations from their respective means and normalizing this sum by the product of both variables' standard deviations. The conclusion drawn from the correlation coefficient is crucial since it determines whether the assumption of normality in the student-teacher ratios can be reasonably accepted.
Analyzing Normal Distribution
Normal distribution analysis is a critical part of statistical data interpretation. It assumes that the data points are spread in a pattern where most of the observations cluster around the mean, creating a bell-shaped curve when plotted. This distribution is symmetrical, with the mean, median, and mode being equal.
In our case, a normal probability plot is used to assess whether the sample data on student-teacher ratios follow a normal distribution. On this plot, the data points should form roughly a straight line if the distribution is normal. Deviations from this line could indicate skewness or outliers in the data. By comparing the plot with the correlation coefficient, we can draw more conclusive evidence about the normalcy of our data. If the distribution is normal, this can streamline further statistical analyses, such as hypothesis testing or regression models, since many statistical methods assume normality of the data.

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Most popular questions from this chapter

The paper referenced in Example 6.24 ("Estimating Waste Transfer Station Delays Using GPS," Waste Management [2008]: 1742-1750) describing processing times for garbage trucks also provided information on processing times at a second facility. At this second facility, the mean total processing time was 9.9 minutes and the standard deviation of the processing times was 6.2 minutes. Explain why a normal distribution with mean 9.9 and standard deviation 6.2 would not be an appropriate model for the probability distribution of the variable \(x=\) total processing time of a randomly selected truck entering this second facility.

Women's Health Magazine surveyed 1187 readers to find out how often people wash their sheets. They found that even though microbiologists recommend that you wash your sheets at least once a week, only \(44 \%\) said that they wash their sheets that often. Suppose this group is representative of adult Americans and define the random variable \(x\) to be the number of adult Americans you would have to ask before you found someone that washes his or her sheets at least once a week. a. Is the probability distribution of \(x\) binomial or geometric? Explain. b. What is the probability that you would have to ask three people before finding one who washes sheets at least once a week? c. What is the probability that fewer than four people would have to be asked before finding one who washes sheets at least once a week? d. What is the probability that more than three people would have to be asked before finding one who washes sheets at least once a week?

A restaurant has four bottles of a certain wine in stock. The wine steward does not know that two of these bottles (Bottles 1 and 2 ) are bad. Suppose that two bottles are ordered, and the wine steward selects two of the four bottles at random. Consider the random variable \(x=\) the number of good bottles among these two. a. When two bottles are selected at random, one possible outcome is (1,2) (Bottles 1 and 2 are selected) and another is (2,4). List all possible outcomes. b. What is the probability of each outcome in Part (a)? c. The value of \(x\) for the (1,2) outcome is 0 (neither selected bottle is good), and \(x=1\) for the outcome (2,4) . Determine the \(x\) value for each possible outcome. Then use the probabilities in Part (b) to determine the probability distribution of \(x\). (Hint: See Example \(6.5 .)\)

Let \(z\) denote a random variable that has a standard normal distribution. Determine each of the following probabilities: a. \(P(z<2.36)\) b. \(P(z \leq 2.36)\) c. \(P(z<-1.23)\) d. \(P(1.142)\) g. \(P(z \geq-3.38)\) h. \(P(z<4.98)\)

Suppose that fuel efficiency (miles per gallon, mpg) for a particular car model under specified conditions is normally distributed with a mean value of \(30.0 \mathrm{mpg}\) and a standard deviation of \(1.2 \mathrm{mpg}\). a. What is the probability that the fuel efficiency for a randomly selected car of this model is between 29 and \(31 \mathrm{mpg}\) ? b. Would it surprise you to find that the efficiency of a randomly selected car of this model is less than \(25 \mathrm{mpg} ?\) c. If three cars of this model are randomly selected, what is the probability that each of the three have efficiencies exceeding \(32 \mathrm{mpg}\) ? d. Find a number \(x^{*}\) such that \(95 \%\) of all cars of this model have efficiencies exceeding \(x^{*}\) (i.e., \(P\left(x>x^{*}\right)=0.95\) ).

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