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The light bulbs used to provide exterior lighting for a large office building have an average lifetime of 700 hours. If lifetime is approximately normally distributed with a standard deviation of 50 hours, how often should all the bulbs be replaced so that no more than \(20 \%\) of the bulbs will have already burned out?

Short Answer

Expert verified
To ensure that no more than \(20\%\) of the light bulbs have burned out, they should be replaced every 658 hours. This is determined using the given normal distribution of lifetime hours with a mean of 700 hours and a standard deviation of 50 hours, and finding the number of hours corresponding to a cumulative probability of \(20\%\).

Step by step solution

01

Identifying the normal distribution parameters

The problem states that the lifetime of the light bulbs is normally distributed with a mean (µ) of 700 hours and a standard deviation (σ) of 50 hours. Thus, we have the following parameters: Mean (µ) = 700 hours Standard deviation (σ) = 50 hours
02

Finding the z-score corresponding to 20% probability

We need to find the z-score corresponding to the \(20\%\) cumulative probability. You can either look this up in a standard normal distribution table, use a calculator with a built-in function, or use a software tool. The z-score corresponding to \(P(z) = 0.20\) is approximately \(-0.84\).
03

Applying z-score to the normal distribution formula

Now, we apply the z-score we found to the normal distribution formula: \(z = \frac{x - \mu}{\sigma}\) Where \(x\) is the number of hours after which no more than \(20\%\) of the bulbs will have burned out, \(\mu\) is the mean, and \(\sigma\) is the standard deviation. Replace the formula with values: \(-0.84 = \frac{x - 700}{50}\)
04

Solving for x

Now solve for \(x\) using the equation from Step 3: \begin{align*} -0.84 \times 50 &= x - 700 \\ -42 &= x - 700 \\ x &= (-42) + 700 \\ x &= 658 \end{align*} So, \(x \approx 658\) hours.
05

Conclusion

To ensure that no more than \(20\%\) of the light bulbs have burned out, they should be replaced every 658 hours.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution Parameters
Understanding the normal distribution parameters is crucial when dealing with problems related to the likelihood of certain events, such as the lifetime of light bulbs in our example. The normal distribution is a symmetrical, bell-shaped curve that is defined by two parameters: the mean \( \( \mu \) \) and the standard deviation \( \( \sigma \) \).

The mean or average \( \( \mu \) \) is the center of the distribution, where the highest point of the bell curve lies. It tells us the average value around which the data points are clustered. In our bulb lifetime example, this is 700 hours. The standard deviation \( \( \sigma \) \) indicates how much the individual data points deviate from the mean on average. A smaller standard deviation means that the data points are close to the mean, while a larger one signifies more spread. For the light bulbs, this is 50 hours, showing moderate spread around the mean lifetime.

With these parameters, we can describe the entire distribution of bulb lifetimes and predict probabilities for different lifespans, which enables us to make decisions on maintenance schedules.
Z-Score
The z-score is a statistical measure that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. If a z-score is 0, it indicates that the data point's score is identical to the mean score.

In the case of the light bulb example, finding the z-score corresponding to the 20% cumulative probability required us to look it up in a standard normal distribution table or use a calculator with a statistical function. The z-score of approximately \( -0.84 \) suggests that the time by which 20% of the light bulbs fail is 0.84 standard deviations below the mean lifetime of 700 hours.

This value is critical for finding the exact time to replace the bulbs before reaching the 20% failure threshold. By converting a z-score back into raw score using the mean and standard deviation, we get the practical information to make decisions—like when to replace the bulbs.
Cumulative Probability
Cumulative probability refers to the likelihood that a random variable is less than or equal to a specified value. It's a fundamental concept in statistics and probability, often visualized on a graph as the area under the curve to the left of a z-score on the normal distribution curve.

Interpreting the cumulative probability helps in determining how often certain events will occur. For instance, in our light bulb problem, we aimed to determine how long the bulbs should last so that no more than 20% of them would fail. Using cumulative probability, we translated this percentage into a z-score and ultimately into the number of hours after which the bulbs should be replaced.

Cumulative probabilities are not only theoretical but have real-world applications in business, engineering, and other fields, guiding decision-making processes based on statistical evidence. In the light bulb example, using this concept ensures efficient maintenance and cost savings by minimizing premature replacements while avoiding a high frequency of bulb outages.

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Most popular questions from this chapter

The Wall Street Journal (February 15,1972 ) reported that General Electric was sued in Texas for sex discrimination over a minimum height requirement of 5 feet, 7 inches. The suit claimed that this restriction eliminated more than \(94 \%\) of adult females from consideration. Let \(x\) represent the height of a randomly selected adult woman. Suppose that \(x\) is approximately normally distributed with mean 66 inches (5 ft. 6 in.) and standard deviation 2 inches. a. Is the claim that \(94 \%\) of all women are shorter than \(5 \mathrm{ft}\). 7 in. correct? b. What proportion of adult women would be excluded from employment as a result of the height restriction?

Sophie is a dog who loves to play catch. Unfortunately, she isn't very good at this, and the probability that she catches a ball is only \(0.1 .\) Let \(x\) be the number of tosses required until Sophie catches a ball. a. Does \(x\) have a binomial or a geometric distribution? b. What is the probability that it will take exactly two tosses for Sophie to catch a ball? c. What is the probability that more than three tosses will be required?

You are to take a multiple-choice exam consisting of 100 questions with five possible responses to each question. Suppose that you have not studied and so must guess (randomly select one of the five answers) on each question. Let \(x\) represent the number of correct responses on the test. a. What kind of probability distribution does \(x\) have? b. What is your expected score on the exam? (Hint: Your expected score is the mean value of the \(x\) distribution.) c. Calculate the variance and standard deviation of \(x\). d. Based on your answers to Parts \((\mathrm{b})\) and \((\mathrm{c}),\) is it likely that you would score over 50 on this exam? Explain the reasoning behind your answer.

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1\). Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50)\)

Let \(x\) denote the duration of a randomly selected pregnancy (the time elapsed between conception and birth). Accepted values for the mean value and standard deviation of \(x\) are 266 days and 16 days, respectively. Suppose that the probability distribution of \(x\) is (approximately) normal. a. What is the probability that the duration of a randomly selected pregnancy is between 250 and 300 days? b. What is the probability that the duration is at most 240 days? c. What is the probability that the duration is within 16 days of the mean duration? d. A "Dear Abby" newspaper column dated January 20, 1973 , contained a letter from a woman who stated that the duration of her pregnancy was exactly 310 days. (She wrote that the last visit with her husband, who was in the navy, occurred 310 days before the birth of her child.) What is the probability that the duration of pregnancy is at least 310 days? Does this probability make you skeptical of the claim? e. Some insurance companies will pay the medical expenses associated with childbirth only if the insurance has been in effect for more than 9 months ( 275 days). This restriction is designed to ensure that benefits are only paid if conception occurred during coverage. Suppose that conception occurred 2 weeks after coverage began. What is the probability that the insurance company will refuse to pay benefits because of the 275 -day requirement?

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