/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Roulette is a game of chance tha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Roulette is a game of chance that involves spinning a wheel that is divided into 38 segments of equal size, as shown in the accompanying picture. A metal ball is tossed into the wheel as it is spinning, and the ball eventually lands in one of the 38 segments. Each segment has an associated color. Two segments are green. Half of the other 36 segments are red, and the others are black. When a balanced roulette wheel is spun, the ball is equally likely to land in any one of the 38 segments. a. When a balanced roulette wheel is spun, what is the probability that the ball lands in a red segment? b. In the roulette wheel shown, black and red segments alternate. Suppose instead that all red segments were grouped together and that all black segments were together. Does this increase the probability that the ball will land in a red segment? Explain. c. Suppose that you watch 1000 spins of a roulette wheel and note the color that results from each spin. What would be an indication that the wheel was not balanced?

Short Answer

Expert verified
The probability of the ball landing in a red segment is \( \frac{18}{38} \). Changing the arrangement of red and black segments does not change the probability, as it still remains \( \frac{18}{38} \). An indication that the wheel is not balanced can be observed if the empirical probability of landing in a red segment after 1000 spins is significantly different from the theoretical probability \( \frac{18}{38} \).

Step by step solution

01

Identifying the number of red segments

Out of the total 38 segments, 2 are green and the remaining 36 are red and black. Half of these 36 segments are red. So, there are 18 red segments.
02

Calculating the probability of landing in a red segment

Since there are 18 red segments and the wheel has a total of 38 segments, the probability of the ball landing in a red segment when the wheel is spun is the ratio of red segments to the total number of segments: \( P(\text{red}) = \frac{\text{number of red segments}}{\text{total segments}} = \frac{18}{38} \). #b. Does changing the arrangement of red and black segments affect the probability?#
03

Analyzing the new arrangement

Now, we need to analyze the scenario where all red segments are grouped together, and all black segments are together as well.
04

Calculating the probability with the new arrangement

Despite the change in the arrangement, there are still 18 red segments and 38 total segments. The probability of landing in a red segment would still be the ratio of red segments to the total number of segments: \( P(\text{red}) = \frac{\text{number of red segments}}{\text{total segments}} = \frac{18}{38} \).
05

Comparing the probabilities

The probability does not change even with the new arrangement of red and black segments. It remains the same because the total number of red segments and the total number of segments on the wheel are not affected by this change. #c. What could be an indication of an unbalanced wheel?#
06

Observing the number of red outcomes

After observing 1000 spins of the roulette wheel, we should count the number of times the ball lands in a red segment.
07

Comparing the observed probability with the theoretical probability

We already know that the theoretical probability of the ball landing in a red segment is \( \frac{18}{38} \). To check if the wheel is balanced, we need to compute the empirical, or observed, probability of the ball landing in a red segment after the 1000 spins, which is the ratio of the number of times the ball landed in a red segment to the total number of spins: \( P(\text{red})_{\text{observed}} = \frac{\text{number of red outcomes}}{1000} \).
08

Determining the balance

If the observed probability is significantly different from the theoretical probability, it could be an indication that the roulette wheel is not balanced. For example, if the empirical probability of landing in a red segment is much higher or lower than \( \frac{18}{38} \), then the wheel may be unbalanced, making the results less random than they should be.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Roulette Wheel
The roulette wheel is a classic example of a game of chance in casinos around the world. It consists of a wheel with 38 segments, each colored either red, black, or green. There are 18 red segments, 18 black segments, and 2 green segments. The idea is simple: a small ball is thrown onto the spinning wheel and eventually comes to rest in one of the segments.

Each spin of the roulette wheel is completely independent, meaning that previous outcomes do not affect future spins. This randomness makes roulette both exciting and unpredictable. When playing roulette, it's important to remember that the wheel is designed to provide an equal chance for the ball to land on any of the 38 segments. This is what makes it fair and balanced.
  • A balanced roulette wheel ensures each segment is equally likely.
  • Factors like layout or aesthetics don't alter the probabilities.
  • The fairness of the game relies on the mechanical consistency of the wheel.
Theoretical Probability
Theoretical probability is all about what we expect to happen in a perfect world. In the context of the roulette wheel, it's calculating the probability based on the known ratio of outcomes.

For example, if you want to know the likelihood of the ball landing on a red segment, you'd look at the total number of red segments compared to all segments on the wheel. Theoretical probability here is mathematically expressed as: \[ P(\text{red}) = \frac{18}{38} \]This fraction represents the proportion of the wheel that is red and, therefore, the chance that the ball will land on a red segment if the wheel is fair and balanced.
  • Theoretical probability is calculated using known quantities.
  • It assumes all outcomes are equally likely and doesn't change regardless of the arrangement.
  • The probability is unaffected by consecutive wins or losses.
Empirical Probability
Empirical probability, on the other hand, is based on actual experiments or observations. Imagine watching 1000 spins of a roulette wheel. Empirical probability uses the outcomes of these observations to calculate the probability of an event occurring.

Let's say you observe the ball land on a red segment 470 times in 1000 spins. The empirical probability would be:\[ P(\text{red})_{\text{observed}} = \frac{470}{1000} \]This real-world probability might differ from the theoretical one because of random variances that occur in practice.
  • Empirical probability is founded on observed data.
  • Sometimes, it deviates from the theoretical probability due to chance or potential biases.
  • By comparing empirical and theoretical probabilities, discrepancies can highlight issues, such as a potentially unbalanced wheel.
Game of Chance
Roulette is the quintessential game of chance. It's all about luck, with each spin producing an independent result. The thrill of the game lies in its unpredictability, making it a favorite in casinos.

Unlike games of skill, where players can influence the outcome through strategy, roulette outcomes are purely random. This is why it's crucial that the wheel is balanced, ensuring each outcome is equally probable, maintaining fairness for all players involved.
  • Games of chance rely entirely on random events.
  • The randomness ensures that no player can predict or control the outcome.
  • Having a mechanical balance is crucial for fairness in games of chance such as roulette.

Understanding these concepts can help you appreciate the delicate balance of chance in games like roulette. Knowledge of theoretical and empirical probabilities offers deeper insights into how these games are designed to be fair and exciting.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A college job placement center has requests from five students for employment interviews. Three of these students are math majors, and the other two students are statistics majors. Unfortunately, the interviewer has time to talk to only two of the students. These two will be randomly selected from among the five. a. What is the sample space for the chance experiment of selecting two students at random? (Hint: You can think of the students as being labeled \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D},\) and \(\mathrm{E}\). One possible selection of two students is \(\mathrm{A}\) and \(\mathrm{B}\). There are nine other possible selections to consider.) b. Are the outcomes in the sample space equally likely? c. What is the probability that both selected students are statistics majors? d. What is the probability that both students are math majors? e. What is the probability that at least one of the students selected is a statistics major? f. What is the probability that the selected students have different majors?

A single-elimination tournament with four players is to be held. A total of three games will be played. In Game 1 , the players seeded (rated) first and fourth play. In Game 2 , the players seeded second and third play. In Game \(3,\) the winners of Games 1 and 2 play, with the winner of Game 3 declared the tournament winner. Suppose that the following probabilities are known: $$ P(\text { Seed } 1 \text { defeats } \operatorname{Seed} 4)=0.8 $$ \(P(\) Seed 1 defeats \(\operatorname{Seed} 2)=0.6\) $$ P(\text { Seed } 1 \text { defeats } \operatorname{Seed} 3)=0.7 $$ \(P(\) Seed 2 defeats Seed 3\()=0.6\) \(P(\) Seed 2 defeats Seed 4\()=0.7\) \(P(\) Seed 3 defeats \(\operatorname{Seed} 4)=0.6\) a. How would you use random digits to simulate Game 1 of this tournament? b. How would you use random digits to simulate Game 2 of this tournament? c. How would you use random digits to simulate the third game in the tournament? (This will depend on the outcomes of Games 1 and \(2 .\) ) d. Simulate one complete tournament, giving an explanation for each step in the process. e. Simulate 10 tournaments, and use the resulting information to estimate the probability that the first seed wins the tournament. f. Ask four classmates for their simulation results. Along with your own results, this should give you information on 50 simulated tournaments. Use this information to estimate the probability that the first seed wins the tournament. g. Why do the estimated probabilities from Parts (e) and (f) differ? Which do you think is a better estimate of the actual probability? Explain.

A medical research team wishes to evaluate two different treatments for a disease. Subjects are selected two at a time, and one is assigned to Treatment 1 and the other to Treatment 2 . The treatments are applied, and each is either a success (S) or a failure (F). The researchers keep track of the total number of successes for each treatment. They plan to continue the experiment until the number of successes for one treatment exceeds the number of successes for the other by \(2 .\) For example, based on the results in the accompanying table, the experiment would stop after the sixth pair, because Treatment 1 has two more successes than Treatment \(2 .\) The researchers would conclude that Treatment 1 is preferable to Treatment \(2 .\) Suppose that Treatment 1 has a success rate of 0.7 and Treatment 2 has a success rate of \(0.4 .\) Use simulation to estimate the probabilities requested in Parts (a) and (b). (Hint: Use a pair of random digits to simulate one pair of subjects. Let the first digit represent Treatment 1 and use \(1-7\) as an indication of a success and \(8,9,\) and 0 to indicate a failure. Let the second digit represent Treatment 2 , with \(1-4\) representing a success. For example, if the two digits selected to represent a pair were 8 and \(3,\) you would record failure for Treatment 1 and success for Treatment 2 . Continue to select pairs, keeping track of the cumulative number of successes for each treatment. Stop the trial as soon as the number of successes for one treatment exceeds that for the other by \(2 .\) This would complete one trial. Now repeat this whole process until you have results for at least 20 trials [more is better]. Finally, use the simulation results to estimate the desired probabilities.) a. Estimate the probability that more than five pairs must be treated before a conclusion can be reached. (Hint: \(P(\) more than 5\()=1-P(5\) or fewer \() .)\) b. Estimate the probability that the researchers will incorrectly conclude that Treatment 2 is the better treatment.

The student council for a school of science and math has one representative from each of five academic departments: Biology (B), Chemistry (C), Mathematics (M), Physics (P), and Statistics (S). Two of these students are to be randomly selected for inclusion on a university-wide student committee. a. What are the 10 possible outcomes? b. From the description of the selection process, all outcomes are equally likely. What is the probability of each outcome? c. What is the probability that one of the committee members is the statistics department representative? d. What is the probability that both committee members come from laboratory science departments?

A deck of 52 cards is mixed well, and 5 cards are dealt. a. It can be shown that (disregarding the order in which the cards are dealt) there are 2,598,960 possible hands, of which only 1287 are hands consisting entirely of spades. What is the probability that a hand will consist entirely of spades? What is the probability that a hand will consist entirely of a single suit? b. It can be shown that exactly 63,206 of the possible hands contain only spades and clubs, with both suits represented. What is the probability that a hand consists entirely of spades and clubs with both suits represented?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.