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The paper referenced in the previous exercise also gave information on calorie content. For the sample of Burger King meal purchases, the mean number of calories was 1008 , and the standard deviation was 483 . For the sample of McDonald's meal purchases, the mean number of calories was \(908,\) and the standard deviation was 624 . Based on these samples, is there convincing evidence that the mean number of calories in McDonald's meal purchases is less than the mean number of calories in Burger King meal purchases? Use \(\alpha=0.01\).

Short Answer

Expert verified
Based on the samples, we performed a two-sample t-test to compare the means of calories in McDonald's and Burger King meal purchases. However, since the sample sizes and degrees of freedom are not provided, we cannot calculate the exact p-value and degrees of freedom, making it impossible to reach a definitive conclusion. With complete information, we would compare the p-value to the given significance level (伪 = 0.01) to determine if there is convincing evidence that the mean number of calories in McDonald's meal purchases is less than that in Burger King meal purchases.

Step by step solution

01

State the Null and Alternative Hypotheses

The null hypothesis (H鈧) assumes that there is no difference between the mean number of calories in McDonald's meal purchases and Burger King meal purchases: H鈧: 渭鈧 - 渭鈧 = 0 The alternative hypothesis (H鈧) claims that the mean number of calories in McDonald's meal purchases is less than that in Burger King meal purchases: H鈧: 渭鈧 - 渭鈧 < 0 Here, 渭鈧 represents the mean number of calories in McDonald's meal purchases and 渭鈧 represents the mean number of calories in Burger King meal purchases.
02

Calculate the Test Statistic

To calculate the t-test statistic, we use the following equation: t = \(\frac{(\bar{x}_{1}-\bar{x}_{2})-(渭_{1}-渭_{2})}{\sqrt{\frac{s鈧乛2}{n鈧亇+\frac{s鈧俕2}{n鈧倉}}\) We are given the sample means (\(\bar{x}_1\) = 908 and \(\bar{x}_2\) = 1008), sample standard deviations (s鈧 = 624 and s鈧 = 483), and sample sizes (n鈧 and n鈧). However, the sample sizes are not provided, so we will represent the test statistic in simplified form: t = \(\frac{(908-1008)-(0)}{\sqrt{\frac{624^2}{n鈧亇+\frac{483^2}{n鈧倉}}\) t = \(\frac{-100}{\sqrt{\frac{624^2}{n鈧亇+\frac{483^2}{n鈧倉}}\)
03

Determine the Degrees of Freedom

Since the sample sizes are not given (n鈧 and n鈧), we cannot calculate the exact degrees of freedom. However, to proceed with the t-test, we can assume that the degrees of freedom are the same for both samples, df = min(n鈧 - 1, n鈧 - 1).
04

Calculate the p-value

Although we don't know the exact degrees of freedom, we can still use a t-distribution calculator or a t-table to find the corresponding p-value for our calculated test statistic t. Since it is a left-tailed test (H鈧: 渭鈧 - 渭鈧 < 0), we find the area to the left of the t-value in the t-distribution table.
05

Compare the p-value to the Significance Level and Make a Conclusion

We compare the calculated p-value to the given significance level (伪 = 0.01). - If the p-value is less than 伪, we reject the null hypothesis (H鈧) and accept the alternative hypothesis (H鈧). In this case, there is convincing evidence that the mean number of calories in McDonald's meal purchases is less than that in Burger King meal purchases. - If the p-value is greater than 伪, we fail to reject the null hypothesis (H鈧). In this case, there is not enough evidence to claim that the mean number of calories in McDonald's meal purchases is less than that in Burger King meal purchases. Since we don't have the exact degrees of freedom and sample sizes, we can't provide a specific conclusion for this exercise. However, if we had this information, we would follow the steps above to reach a conclusion about the difference in means between McDonald's and Burger King meal purchases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
When conducting hypothesis testing, it is essential to start by stating the null and alternative hypotheses, which will guide the direction of our analysis.
The **null hypothesis** ( H鈧) is essentially a statement that assumes no effect or no difference exists between certain conditions or parameters we want to test. In our exercise, the null hypothesis maintains that there is no difference in the mean number of calories between McDonald's and Burger King meal purchases. Mathematically, this is expressed as: H鈧: 渭鈧 - 渭鈧 = 0.
  • **渭鈧** represents the mean calories for McDonald's meals
  • **渭鈧** represents the mean calories for Burger King's meals
The **alternative hypothesis** ( H鈧) represents what we are trying to provide evidence for. In our case, the alternative hypothesis suggests that McDonald's meals have fewer calories on average compared to Burger King's. This hypothesis is expressed as: H鈧: 渭鈧 - 渭鈧 < 0.
Remember, the alternative hypothesis is usually the conclusion researchers want to support, while the null hypothesis is the statement we try to disprove or reject.
t-test
The t-test is a statistical test used to compare the means of two groups, determining whether there is a significant difference between them. It is suitable for scenarios where the sample sizes are small and population variances are unknown. In our exercise, we perform a two-sample t-test to compare meal calorie means from two fast-food chains. To calculate the t-test statistic, use the formula:
\[ t = \frac{(\bar{x}_{1}-\bar{x}_{2})-(渭_{1}-渭_{2})}{\sqrt{\frac{s鈧乛2}{n鈧亇+\frac{s鈧俕2}{n鈧倉}} \]
This formula involves:
  • **\(\bar{x}_{1}, \bar{x}_{2}\)**: sample means (McDonald's and Burger King's)
  • **\(s鈧, s鈧俓)**: sample standard deviations
  • **\(n鈧, n鈧俓)**: sample sizes
For our exercise, we substitute the given means and standard deviations to obtain a simplified form:
\[ t = \frac{-100}{\sqrt{\frac{624^2}{n鈧亇+\frac{483^2}{n鈧倉}} \]
This test assesses if the observed differences in mean calories could have happened by random chance, or if they imply a real difference between McDonald's and Burger King's offerings.
p-value calculation
After determining the test statistic, the next step is to calculate the p-value. The p-value helps us understand how extreme our test statistic is under the assumption that the null hypothesis is true. It tells us the probability of observing a test statistic at least as extreme as the one calculated, purely by random chance if the null hypothesis holds.
  • A **small p-value** indicates strong evidence against the null hypothesis, suggesting that the observed data is unlikely under the null scenario.
  • A **large p-value** suggests weak evidence against the null hypothesis, supporting the idea that any observed difference is due to random variation.
Given our situation, we conduct a left-tailed test ( H鈧: 渭鈧 - 渭鈧 < 0) which requires finding the area to the left of the test statistic on the t-distribution. We can use statistical software or a t-distribution table to find this area, representing the p-value. Without the exact sample sizes, an exact numeric p-value can't be provided, but the logic remains consistent for p-value interpretation.
Significance Level
The significance level, denoted as \(伪\), is a threshold set by the researcher to decide whether the observed differences are statistically significant. It represents the risk we are willing to take in incorrectly rejecting the null hypothesis when it is true, known as a type I error.
Common significance levels are 0.05 or 0.01. In our exercise, \(伪 = 0.01\), which indicates a stricter criterion for rejecting the null hypothesis. The lower the \(伪\), the lesser the risk of false positive results.
  • If the **p-value** is less than \(伪\) (in this case, 0.01), we reject the null hypothesis, suggesting there is strong evidence for the alternative hypothesis that McDonald's meals average fewer calories than Burger King's.
  • If the **p-value** is greater than \(伪\), we fail to reject the null hypothesis, concluding insufficient evidence exists to claim one meal type has fewer calories than the other.
This framework helps make data-driven conclusions with a clear notion of risk management in statistical inference.

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