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The report referenced in the previous exercise also gave data for representative samples of 250 adults in Canada and 250 adults in England. The sample mean amount of sleep on a work night was 423 minutes for the Canada sample and 409 minutes for the England sample. Suppose that the sample standard deviations were 35 minutes for the Canada sample and 42 minutes for the England sample. a. Construct and interpret a \(95 \%\) confidence interval estimate of the difference in the mean amount of sleep on a work night for adults in Canada and adults in England. b. Based on the confidence interval from Part (a), would you conclude that there is evidence of a diflerence in the mean amount of sleep on a work night for the two countries? Explain why or why not.

Short Answer

Expert verified
The 95% confidence interval for the difference in mean amount of sleep on a work night for adults in Canada and England is (7.25, 20.75) minutes. Since this interval does not contain 0, there is evidence of a difference in the mean amount of sleep on a work night for the two countries, with adults in Canada tending to sleep more on work nights compared to those in England.

Step by step solution

01

Identify the given information

We are given the following information: 1. Sample size for Canada (n1) = 250 2. Sample size for England (n2) = 250 3. Sample mean for Canada (\(\bar{x}_1\)) = 423 minutes 4. Sample mean for England (\(\bar{x}_2\)) = 409 minutes 5. Sample standard deviation for Canada (s1) = 35 minutes 6. Sample standard deviation for England (s2) = 42 minutes 7. Confidence level = 95%
02

Calculate the standard error of the difference

Calculate the standard error (SE) of the difference in means using the following formula: \[SE = \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}\] Plugging in the given values: \[SE = \sqrt{\frac{35^2}{250} + \frac{42^2}{250}} = \sqrt{\frac{1225}{250} + \frac{1764}{250}} = \sqrt{4.9 + 7.056} = 3.45\]
03

Calculate the margin of error

Calculate the margin of error (ME) for the 95% confidence level using the following formula: \[ME = t * SE\] We need to find the t-value for a 95% confidence interval and degrees of freedom (df). Since the sample sizes are large (n1 = n2 = 250), we can use the z-value for a 95% confidence interval instead. The z-value for a 95% confidence interval is 1.96. Thus: \[ME = 1.96 * 3.45 = 6.75\]
04

Calculate the confidence interval

Calculate the confidence interval using the difference in means (\(\bar{x}_1 - \bar{x}_2\)) and the margin of error: \[CI = (\bar{x}_1 - \bar{x}_2) \pm ME\] Plugging in the values: \[CI = (423 - 409) \pm 6.75 = 14 \pm 6.75\] Thus, the 95% confidence interval for the difference in mean amount of sleep on a work night for adults in Canada and England is (7.25, 20.75).
05

Interpret the confidence interval and answer part (b)

The confidence interval (7.25, 20.75) means that we are 95% confident that the difference in mean amount of sleep on a work night for adults in Canada and adults in England lies between 7.25 and 20.75 minutes. Since this interval does not contain 0, we can conclude that there is evidence of a difference in the mean amount of sleep on a work night for the two countries. In this case, it seems that adults in Canada tend to sleep more on work nights than those in England.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Understanding "standard deviation" is crucial in determining the variability within a set of data. It measures how much individual data points differ from the mean or average of the data set. In simpler terms, it's a measure of how "spread out" numbers are. For example, in the sleep study exercise, Canada's sample standard deviation is 35 minutes, while England's sample standard deviation is 42 minutes.

These values tell us that England's data is more variable as compared to Canada's. A higher standard deviation implies more variation, and it indicates that the sleep durations differ more from the average in the England sample. This spread influences how wide a confidence interval might be, since larger standard deviations typically result in larger margins of error when constructing confidence intervals.
Sample Size
Sample size, often represented as "n," is the number of observations within a sample. It's a core element in statistics, significantly impacting how reliable and accurate a statistical inference might be. In our exercise, both Canadian and English sample sizes are 250.

Larger sample sizes tend to produce more reliable results. More data points typically mean your estimates, including means and standard deviations, more closely represent the entire population. They also lead to narrower confidence intervals, suggesting a more precise estimate of the population parameter. In the context of the sleep study, a sample size of 250 is relatively robust, providing good reliability for the confidence interval constructed for the difference in mean sleep durations between Canadians and English adults.
Margin of Error
The margin of error is essentially the "wiggle room" around the parameter estimate - in this case, the difference in mean sleep durations. It reflects the uncertainty associated with a sample estimate and is crucial for constructing confidence intervals. The formula used to calculate it involves multiplying the standard error of the difference in means by a critical value, like the z-value in our scenario.

From our exercise, the margin of error is computed as 6.75 minutes. This means the actual difference in the population means could vary by up to 6.75 minutes from our calculated difference of 14 minutes. A larger margin of error suggests a less precise estimate, thus making smaller margins of error typically more desirable as they indicate a more accurate approximation of the true population difference.
Z-value
The z-value is a statistical term that measures the number of standard deviations an element is from the mean. In the context of confidence intervals, it helps determine the critical value used when the sample size is large.

For our exercise, since both sample sizes are 250, which is considered relatively large, the normal distribution is applicable. For a 95% confidence level, the z-value is fixed at 1.96.

This z-value signifies there is a 95% probability that the true population parameter will fall within a calculated range based on this critical value, accounting for variability in the data. Thus, the 1.96 multiplier scales the standard error to obtain the margin of error, shaping the confidence interval around the difference in means.
Difference in Means
The difference in means focuses on the contrast between two average values from different samples. In our problem, the distinct means being evaluated are the average sleep durations of Canadian and English adults during work nights.

The formula for finding this difference is straightforward: subtract the mean of one sample from the mean of the other. In this case, it indicates a 14-minute difference, with Canadians reportedly sleeping more than the English.

Understanding this difference is pivotal for statistical analysis, as it serves as the fundamental basis for constructing confidence intervals and inferring whether the observed discrepancy is statistically significant. By examining the confidence interval derived from the difference in means, statisticians can make conclusions about whether this observed differentiation is likely due to actual differences or random chance.

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Most popular questions from this chapter

An individual can take either a scenic route to work or a nonscenic route. She decides that use of the nonscenic route can be justified only if it reduces the mean travel time by more than 10 minutes. a. If \(\mu_{1}\) refers to the mean travel time for nonscenic route and \(\mu_{2}\) to the mean travel time for scenic route, what hypotheses should be tested? b. If \(\mu_{1}\) refers to the mean travel time for scenic route and \(\mu_{2}\) to the mean travel time for nonscenic route, what hypotheses should be tested?

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