/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 The light bulbs used to provide ... [FREE SOLUTION] | 91Ó°ÊÓ

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The light bulbs used to provide exterior lighting for a large office building have an average lifetime of 700 hours. If lifetime is approximately normally distributed with a standard deviation of 50 hours, how often should all the bulbs be replaced so that no more than \(20 \%\) of the bulbs will have already burned out?

Short Answer

Expert verified
In order to ensure no more than 20% of bulbs have burned out, all bulbs should be replaced every 658 hours.

Step by step solution

01

Identify the percentiles

Given that no more than 20% of the bulbs should burn out before replacement, it essentially means that we need to find out the 20th percentile of the normal distribution as at that point, 20% of the bulbs would have burned out.
02

Calculate the Z-Score for the 20th percentile

The z-score related to the 20th percentile (from a standard normal distribution table or calculator) typically equates to -0.84. Note, the negative value indicates a percentile below the mean (50th percentile in this case).
03

Calculate the corresponding lifetime

Use the formula of z-score to calculate the corresponding value in hours for this z-score. The formula is: \( Z = \frac{X - \mu}{\sigma} \), where X is the value we want to find, \( \mu \) is the mean (700 hours), and \( \sigma \) is the standard deviation (50 hours). Rearranging the formula to find X gives \( X = Z\sigma + \mu \), substituting the known values into the formula results in \( X = -0.84*50 + 700 = 658 \) hours.

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