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A gasoline tank for a certain car is designed to hold 15 gallons of gas. Suppose that the random variable \(x=\) actual capacity of a randomly selected tank has a distribution that is well approximated by a normal curve with mean 15.0 gallons and standard deviation 0.1 gallon. a. What is the probability that a randomly selected tank will hold at most 14.8 gallons? b. What is the probability that a randomly selected tank will hold between 14.7 and 15.1 gallons? c. If two such tanks are independently selected, what is the probability that both hold at most 15 gallons?

Short Answer

Expert verified
a) The probability that a randomly selected tank will hold at most 14.8 gallons is 0.02275. b) The probability that a randomly selected tank will hold between 14.7 and 15.1 gallons is 0.83999. c) The probability that both independently selected tanks hold at most 15 gallons is 0.25.

Step by step solution

01

Calculating the Z-score for part a

First, let's calculate the Z-score, which is the number of standard deviations from the mean, for a tank capacity of 14.8 gallons using the given mean μ and standard deviation σ. The Z-score is calculated through the formula \(Z = (X - μ) / σ\). In this case, \(Z = (14.8 - 15.0) / 0.1 = -2\).
02

Finding the Probability for part a

Using the standard normal distribution table or a z-table, find the probability that corresponds to a Z-score of -2. This probability represents the chance of a randomly selected tank holding at most 14.8 gallons. The probability associated with a Z-score of -2.00 is 0.02275.
03

Calculating the Z-scores for part b

Here, we need to calculate the Z-score for both 14.7 gallons and 15.1 gallons. Using the Z-score formula again, \(Z1 = (14.7 - 15) / 0.1 = -3\) for the lower limit and \(Z2 = (15.1 - 15) / 0.1 = 1\) for the upper limit.
04

Finding the Probability for part b

We look up both Z-scores in the Z-table. The probability associated with a Z-score of -3.00 is 0.00135 and with a Z-score of 1.00 is 0.84134. We subtract the probability of Z1 from the probability of Z2 to find the probability that a randomly selected tank will hold between 14.7 and 15.1 gallons: \(P = 0.84134 - 0.00135 = 0.83999\).
05

Finding the Probability for part c

First, we find the probability for one such tank holding at most 15 gallons. In the z-score context, 15 is the mean, which corresponds to a z-score of 0 with a probability of 0.5. As the tanks are filled independently, the total probability is the product of the individual probabilities. Hence, the probability that both tanks hold at most 15 gallons is \(0.5 * 0.5 = 0.25\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score calculation
Calculating a Z-score is a fundamental step when working with normal distributions. It helps you understand how far away a specific value is from the mean, in terms of standard deviations.
To calculate the Z-score, use the formula:
  • \( Z = \frac{X - \mu}{\sigma} \)
Here:
  • \(X\) is the value in question, such as the tank capacity of 14.8 gallons.
  • \(\mu\) is the mean, the average capacity, given as 15.0 gallons.
  • \(\sigma\) is the standard deviation, which measures the spread, specified as 0.1 gallon.
For example, to find the Z-score for a tank holding 14.8 gallons:
  • Substitute into the formula: \( Z = \frac{14.8 - 15}{0.1} = -2\).
This calculation shows that 14.8 gallons is 2 standard deviations below the mean.
Probability
Once you've calculated the Z-score, the next step involves determining the probability. This involves looking up the Z-score in the standard normal distribution table, or alternatively using statistical software. This table tells you the probability that a value is less than or equal to the given Z-score.
For instance, with a Z-score of -2:
  • The probability corresponds to 0.02275.
This indicates that there is a 2.275% chance that a randomly selected tank will hold at most 14.8 gallons.
To find the probability that a tank holds between two values (e.g., between 14.7 and 15.1 gallons), calculate the Z-scores for both values.
The difference between their respective probabilities from the standard normal distribution provides the probability of seeing a value within that range.
Hence, the difference between probabilities for Z-scores \(Z1 = -3\) and \(Z2 = 1\) results in a probability of 0.83999, or about 83.999%.
Standard normal distribution
The standard normal distribution is an essential concept in statistics. It's a normal distribution with a mean of 0 and a standard deviation of 1. Every normal distribution, regardless of its mean or standard deviation, can be converted into the standard normal distribution using the Z-score.
This allows for easier calculation of probabilities.
  • It helps us determine how likely a particular outcome is.
  • It simplifies comparing different data sets or variables since they can be analyzed on the same scale.
When working with Z-scores, probabilities can be quickly deduced by referencing the standard normal distribution table.
The conversion of any normal distribution to a standard form eliminates the variability associated with different scales, offering a standardized method to approach problems in statistics.
Applying it to our exercise, any tank's capacity can be transformed into a Z-score, which can then be used to determine probabilities effortlessly using the standard normal distribution.

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