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What happens to the standard deviation of \(\hat{p}\) as the sample size increases? If the sample size is increased by a factor of 4 what happens to the standard deviation of \(\hat{p} ?\)

Short Answer

Expert verified
The standard deviation of \hat{p} decreases as the sample size increases. If the sample size is increased by a factor of 4, the standard deviation of \hat{p} is halved.

Step by step solution

01

- Understand the standard deviation of \hat{p}

The standard deviation of the sample proportion, \hat{p}, when sampling from a population, is given by the formula: \[\text{Standard Deviation of } \hat{p} = \sqrt{\frac{p(1-p)}{n}} \] where \p is the population proportion and \ is the sample size.
02

- Recognize the effect of increasing sample size

When the sample size \(n\) increases, the denominator in the standard deviation formula increases, which typically causes the overall value of the standard deviation to decrease. This means as \(n\) increases, the variability in \hat{p} decreases.
03

- Calculate new standard deviation with larger sample size

If the sample size is increased by a factor of 4, the new sample size becomes \4n. Substitute \4n into the standard deviation formula: \[\text{New Standard Deviation of } \hat{p} = \sqrt{\frac{p(1-p)}{4n}} = \frac{1}{2} \sqrt{\frac{p(1-p)}{n}} \] This shows that the new standard deviation is half of the original standard deviation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sample size effect
Many students often wonder, 'What happens to the standard deviation of \( \hat{p} \) as the sample size increases?' To understand this, let’s break it down. The standard deviation of the sample proportion \( \hat{p} \) is given by the formula: \(\text{Standard Deviation of } \hat{p} = \sqrt{\frac{p(1-p)}{n}}\). Here, \( p \) is the population proportion, and \( n \) is the sample size.

  • When the sample size increases, the value of \( n \) in the denominator gets larger.
  • This causes the value under the square root to become smaller.
  • Consequently, the overall standard deviation decreases as sample size increases.
The decreasing standard deviation means there's less variability in \( \hat{p} \). Things get more predictable, and our estimates become more accurate.

Now, imagine you increase the sample size by a factor of 4. So, the new sample size is \('4n'\). Inserting \('4n'\) into our formula gives: \(\text{New Standard Deviation of } \hat{p} = \sqrt{\frac{p(1-p)}{4n}} \). This simplifies to \( \frac{1}{2} \sqrt{\frac{p(1-p)}{n}} \). As you can see, doubling the sample size reduces the standard deviation to half of its original value. In other words, the standard deviation decreases, making \( \hat{p} \) more reliable.

population proportion
Understanding the term 'population proportion' is crucial for mastering the concept of standard deviation in sample proportions. Essentially, the population proportion \( p \) represents the ratio of a certain characteristic in the entire population. For example, if we were examining the number of students who prefer online classes, \( p \) would be the proportion of students in the entire population who prefer online classes.

In mathematical terms:
  • \( p = \frac{N_{\text{characteristic}}}{N_{\text{total}}} \)
  • Where \( N_{\text{characteristic}} \) is the number of individuals with the characteristic and \( N_{\text{total}} \) is the total population.
When using sample proportions in studies, \( \hat{p} \) is used as an estimate of \( p \). One significant benefit of knowing the population proportion is that it allows researchers to design more accurate and reliable studies. When \( p \) is known, statisticians can better understand how varying the sample size \( n \) will affect the variability of \( \hat{p} \).

variability reduction
Variability reduction is an important concept in statistics, especially when dealing with sample proportions. Variability refers to how spread out the values of \( \hat{p} \) are around the true population proportion \( p \).

  • As sample size increases, the standard deviation of \( \hat{p} \) decreases.
  • This means that the sample proportions are more likely to be closer to the actual population proportion \( p \).


This reduction in variability is significant in research contexts. When variability is reduced:

  • Researchers can be more confident in their findings.
  • The results are more consistent and reliable.
  • Predictive models become more accurate.
So, by understanding and managing the effects of sample size on standard deviation, you can significantly reduce variability and improve the quality of your data analysis.

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Most popular questions from this chapter

The reading speed of second grade students is approximately normal, with a mean of 90 words per minute (wpm) and a standard deviation of 10 wpm. (a) What is the probability a randomly selected student will read more than 95 words per minute? (b) What is the probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute? (c) What is the probability that a random sample of 24 second grade students results in a mean reading rate of more than 95 words per minute? (d) What effect does increasing the sample size have on the probability? Provide an explanation for this result. (e) A teacher instituted a new reading program at school. After 10 weeks in the program, it was found that the mean reading speed of a random sample of 20 second grade students was 92.8 wpm. What might you conclude based on this result? (f) There is a \(5 \%\) chance that the mean reading speed of a random sample of 20 second grade students will exceed what value?

A simple random sample of size \(n=1000\) is obtained from a population whose size is \(N=1,000,000\) and whose population proportion with a specified characteristic is \(p=0.35\). (a) Describe the sampling distribution of \(\hat{p}\). (b) What is the probability of obtaining \(x=390\) or more individuals with the characteristic? (c) What is the probability of obtaining \(x=320\) or fewer individuals with the characteristic?

Determine \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\) from the given parameters of the population and the sample size. \(\mu=27, \sigma=6, n=15\)

Describe the sampling distribution of \(\hat{p}\). Assume that the size of the population is 25,000 for each problem. $$ n=1010, p=0.84 $$

The shape of the distribution of the time required to get an oil change at a 10 -minute oil-change facility is unknown. However, records indicate that the mean time for an oil change is 11.4 minutes, and the standard deviation for oilchange time is 3.2 minutes. (a) To compute probabilities regarding the sample mean using the normal model, what size sample would be required? (b) What is the probability that a random sample of \(n=40\) oil changes results in a sample mean time of less than 10 minutes? (c) Suppose the manager agrees to pay each employee a \(\$ 50\) bonus if they meet a certain goal. On a typical Saturday, the oil-change facility will perform 40 oil changes between 10 A.M. and 12 P.M. Treating this as a random sample, what mean oil-change time would there be a \(10 \%\) chance of being at or below? This will be the goal established by the manager.

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